--a*(5+b)/2-c++*b --0*(5+1)/2-(-1)++*1 Firstly we evaluated which is written in bracket --0*6/2-(-1)++*1 Now we evaluate postfix increment op --0*6/2+1*1 We write +1 bcz in postfix firsly value assigned then value incremented After postfix increment we evaluate prefix decrement -1*6/2+1*1 We know that * and / has same precidence and associativity is from left to right -6/2+1*1 -3+1*1 We know that +has lower precidence than * then * evaluated first -3+1 =-2 Hence answer is -2
For me it's the ever most helpful comment, that I ever read on this earth. Ya, there are some gems on earth, in which you are the one. Smile because you're unique. Thanks for helping me out to understand it in form of a comment 😊
@@kkkkkkk754 in post increment we firstly assigned the value then incremented. Eg. int a=2; printf("a=%d",a++); It gives output a=2 then a becomes 3. In post decrement we firstly assigned the value then it is decremented . Eg. int a=2; printf("a=%d",a- -); It gives you the output a=2 then a becomes 1. Hints:- Incremented means plus 1 Decremented mean minus 1
Ans = -2 - -a * (5+b) / 2 - c++ * b - -a * 6 / 2 - - 1 * b (#(),++,#) - 1 * 6 / 2 +1 * b (#- -, -,# ) - 3 + 1 (#* ,/ ,*#) - 2 (#+#) Operation done on the previous line is commented with # inside the bracket in the new line, in other of operation precedence and separate by non-computing commas. I didn’t use compiler anyways, but you are free to point out mistakes if found😅
I think it's after the program runs for the first time, then when it runs the second time it will increment to 1 because it's a postfix. That's how the postfix program runs. If it was a prefix it will increment from 0 to 1 the first time it runs.
Mam ur DS playlist really helped me a lot for exam prep... please make a playlist for Computer architecture also mam... the subject sounds so vague pl help mam... 🙏🙂
Q . --a * (5 + b) / 2 - c++ * b given a = 0, b = 1, c = -1; ans = -2 explaination- firsty bracket will be evaluated so it will give 6 now evaluate --a, it will give -1 since we are pre decrementing 0 now, -1*6 = -6 now -6/2=-3 then -3 - (-1)*b(due to post fix the value of c will remain same ) will give -3 +1*1(since b is given as 1) hence -3+1=-2 ans
Shortcut to remember the operator precedence table in C… Use PUMA' S REBL TAC. ( spell "REBL" as if "REBEL"). (Note: all operators with associativity not specified is left to right). P - Primary U - Unary M - Multiplicative A - Additive S- Shift R- Relational E- Equality B- BitWise ( & > ^ > |) L- Logical ( logical && > logical ||) and the last three operators are T- Ternary A- Assignment C- Comma If you need a shortcut for Assosiativity then "AUTo rides in the right side", meaning Assignment, Unary and Ternary operators are Right to Left, O is added for completion)
--a will decrement the value of a by 1 and return the new value (-1). 5+b will add 5 to the value of b (which is 1) and return 6. --a*(5+b) will multiply the result of step 2 by the result of step 1, which gives -6. /2 will divide the result of step 3 by 2, which gives -3. c++ will return the current value of c (-1) and then increment it by 1 (to become 0). c++*b will multiply the result of step 5 by the current value of b (which is 1), which gives 0. -3-0 will subtract the result of step 6 from the result of step 4, which gives -3. Therefore, the output of the expression --a*(5+b)/2-c++*b will be -3.
C++ means post increment so value of c used is -1 but in output in you print c you will get zero. In program c=-1 will be used. Now you will get -2 as the answer.
Nice one. Thank you. This part need more clarification and workouts as most of the entrance exams have bunch of questions from this area. To my knowledge, none of the books in market covering this area fully. There is always a grey area where people get confusions. If possible, please comeup with more videos with more sample questions from placement question papers and show with step by step explanation in detail. Thanks once again.
dear mam thank you will be very less for your videos , praying for all happiness n success to u n to ur family , i m benefited a lot by your videos , you are an excellent teacher
Welcome Back and HnewY 2021 Lecturer Jenny, wish you higher advancement in this year and I promise you to be a good programer because of you. Step by step any thing is possible
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Compiler Answer : -2 but what i understood from your lecture: int a=0,b=1,c=-1; int k= --a *(5+b)/2-c++*b; --a *6/2-c++*b --a *6/2-0*b -1 *6/2-0*b -6/2-0*1 -3-0*1 -3-0 -3 tell me where i am wrong??
Videos are good as talking about the explanation, but I am wishing project based tutorial as these videos totally like as some online Computer Engineering Quick Guides. If you could do it I would be very thankful to you ,MAM!, as I am just in 9th. Please..
int a=0,b=1,c=-1; - -a * (5+b)/2 - c+ + * b.................. ['/ ' is higher precedence than '*'] -1 * 3 - -1 * 1.......................... [value of a will increment first , c is now incremented to 0{-1+1=0}] -3 - -1..................['*' have higher precedence value than '-'] -3 + 1 = -2 ( output)
--a*(5+b)/2-c++*b here, a=0, b=1, c=-1 --0*(5+1)/2-(-1)++*1 brackets, postfix have the same precedence(highest), therefore we have to go from left to right --0*6/2+1*1 now the prefix has the highest precedence in the above expression, -1*6/2+1*1 now * / have the highest precedence in the above expression, to break the tie we from left to right, -3+1 now + has has the highest precedence in the above expression, -2 We have the values of the variables as, a=-1, b=1, c=0
-3 will be correct answer.. --a * (5 + b) / 2 - c++ * b given a = 0, b = 1, c = -1; --a * (5 + b) / 2 - c++ * b -1*(5+1)/2-0*1 (--a becomes -1,The value of a is updated to -1 becuase its a prefix dcrement and c is postfix increment so it will be update -1 to 0). -1*6/2-0*1 -1*6/2-0 -6/2-0 -3 ans................
I usually watch your videos they so well and I like them. thanks so much. I would ask you do you know anyone who would teach me data structure and java programming. I'm going to pay for the service.
--a*(5+b)/2-c++*b
--0*(5+1)/2-(-1)++*1
Firstly we evaluated which is written in bracket
--0*6/2-(-1)++*1
Now we evaluate postfix increment op
--0*6/2+1*1
We write +1 bcz in postfix firsly value assigned then value incremented
After postfix increment we evaluate prefix decrement
-1*6/2+1*1
We know that * and / has same precidence and associativity is from left to right
-6/2+1*1
-3+1*1
We know that +has lower precidence than * then * evaluated first
-3+1
=-2
Hence answer is -2
For me it's the ever most helpful comment, that I ever read on this earth. Ya, there are some gems on earth, in which you are the one. Smile because you're unique. Thanks for helping me out to understand it in form of a comment 😊
can you explain the post fix increment. -1++ is 0 right?
@@aakashyericharla8668 no this is not right bcz in postfix firstly we put value then incremented
That means (-1)++=-1
Hi, can u explain what is post increment and dercrement after the step of 5+1 pls. I am school student.. I will be grateful
@@kkkkkkk754 in post increment we firstly assigned the value then incremented.
Eg. int a=2;
printf("a=%d",a++);
It gives output a=2 then a becomes 3.
In post decrement we firstly assigned the value then it is decremented .
Eg. int a=2;
printf("a=%d",a- -);
It gives you the output a=2 then a becomes 1.
Hints:-
Incremented means plus 1
Decremented mean minus 1
11:03 #include
int main()
{
int a=0,b=1,c=-1;
printf("%d",--a*(5+b)/2-c++*b);
return 0;
}
output: -2
working: --a*(5+b)/2-c++*b => -1*6/2+1*1 => -3+1 => -2
Ans = -2
- -a * (5+b) / 2 - c++ * b
- -a * 6 / 2 - - 1 * b (#(),++,#)
- 1 * 6 / 2 +1 * b (#- -, -,# )
- 3 + 1 (#* ,/ ,*#)
- 2 (#+#)
Operation done on the previous line is commented with # inside the bracket in the new line, in other of operation precedence and separate by non-computing commas.
I didn’t use compiler anyways, but you are free to point out mistakes if found😅
You didn't increment the value of c by 1.
@@omarfaruque1095 it was a post increment, so c was evaluated before being incremented, as such it remain as -1 as shown in the second line
@@Dr._Aniekan_udo apt. Followed the same reasoning and compiled to verify my answer
I think it's after the program runs for the first time, then when it runs the second time it will increment to 1 because it's a postfix. That's how the postfix program runs. If it was a prefix it will increment from 0 to 1 the first time it runs.
Thank you sir
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Your work is awesome Mama. Your courses of the C language are the best I found on the internet.
Excellent teaching mam , no words for your teaching
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Q . --a * (5 + b) / 2 - c++ * b
given a = 0, b = 1, c = -1;
ans = -2
explaination-
firsty bracket will be evaluated
so it will give 6
now evaluate --a, it will give -1 since we are pre decrementing 0
now, -1*6 = -6
now -6/2=-3
then -3 - (-1)*b(due to post fix the value of c will remain same )
will give -3 +1*1(since b is given as 1)
hence -3+1=-2 ans
After brackets c++ na postfix increment has higher precendence that. Prefix
Thnx for ur gd expln abt the c++
Wrong ans
He is right you can compile it
@@rutujajadhav1782 I got -3? is it correct
Mam ur teaching is marvelous this is what a beginner expects
You're really good at explaining things clearly. Good job.
teaching "extraordinary, fanstatic and mind blowing mam salute mam😇"
Shortcut to remember the operator precedence table in C…
Use PUMA' S REBL TAC. ( spell "REBL" as if "REBEL").
(Note: all operators with associativity not specified is left to right).
P - Primary
U - Unary
M - Multiplicative
A - Additive
S- Shift
R- Relational
E- Equality
B- BitWise ( & > ^ > |)
L- Logical ( logical && > logical ||)
and the last three operators are
T- Ternary
A- Assignment
C- Comma
If you need a shortcut for Assosiativity then "AUTo rides in the right side", meaning Assignment, Unary and Ternary operators are Right to Left, O is added for completion)
Super bro no need to see video
kis channel se padthe ho
thanks
Ans is -2
Thanks a lot Mam
how i couldn't got it
--a will decrement the value of a by 1 and return the new value (-1).
5+b will add 5 to the value of b (which is 1) and return 6.
--a*(5+b) will multiply the result of step 2 by the result of step 1, which gives -6.
/2 will divide the result of step 3 by 2, which gives -3.
c++ will return the current value of c (-1) and then increment it by 1 (to become 0).
c++*b will multiply the result of step 5 by the current value of b (which is 1), which gives 0.
-3-0 will subtract the result of step 6 from the result of step 4, which gives -3.
Therefore, the output of the expression --a*(5+b)/2-c++*b will be -3.
but -2 is given by computer
@@MissionEr32 -3+1 will become -2
Wrong
C++ means post increment so value of c used is -1 but in output in you print c you will get zero. In program c=-1 will be used. Now you will get -2 as the answer.
Mam your videos is easily understandable for me on RUclips platform... Thank you mam for this course🙏
Watched your whole ds algo videos...
Really helpful for me..
Keep making such videos🙏
Nice one. Thank you.
This part need more clarification and workouts as most of the entrance exams have bunch of questions from this area.
To my knowledge, none of the books in market covering this area fully. There is always a grey area where people get confusions.
If possible, please comeup with more videos with more sample questions from placement question papers and show with step by step explanation in detail. Thanks once again.
do we have to learn this???to solve, but how will i learn such a big table? any short trick? like bodmas or something?
dear mam thank you will be very less for your videos , praying for all happiness n success to u n to ur family , i m benefited a lot by your videos , you are an excellent teacher
I have seen c programming topic video. Amazing presentation.
Best teacher ever
Welcome Back and HnewY 2021 Lecturer Jenny, wish you higher advancement in this year and I promise you to be a good programer because of you.
Step by step any thing is possible
Thank you so to press like on my comment, now I want to invite you if possible to press follow on my instagram which is instagram.com/hadieudonne43 🤦🤦🤦🙏
ruclips.net/video/qI29eAhdJIc/видео.html
Thank you so much mam
aap kitna hard work karti h mam
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Compiler Answer : -2
but what i understood from your lecture:
int a=0,b=1,c=-1;
int k= --a *(5+b)/2-c++*b;
--a *6/2-c++*b
--a *6/2-0*b
-1 *6/2-0*b
-6/2-0*1
-3-0*1
-3-0
-3
tell me where i am wrong??
You didn't take c++=-1
@@yashkumar-lg1jq why?
c is already -1 .and after c++ it becomes 0
@@ankitrawat978 bhai post increment hai
Yaa i got the same answer
Best teacher i have ever seen
Tq mam clearly understood 😊
Videos are good as talking about the explanation, but I am wishing project based tutorial as these videos totally like as some online Computer Engineering Quick Guides. If you could do it I would be very thankful to you ,MAM!, as I am just in 9th. Please..
Maam u r soo cute
And through your teaching pattern I'll learn more and more....
U r amazing😍
Love from FoET lucknow CSE(AI). ❤
int a=0,b=1,c=-1;
- -a * (5+b)/2 - c+ + * b.................. ['/ ' is higher precedence than '*']
-1 * 3 - -1 * 1.......................... [value of a will increment first , c is now incremented to 0{-1+1=0}]
-3 - -1..................['*' have higher precedence value than '-']
-3 + 1 = -2 ( output)
Thankyou very much❤️
You have a great way of teaching but i want to say that I laugh 🤣 when you scream 'now' out of nowhere 😆.
😂
😂
🤣
Mam u r so pretty..❤ and a good teacher also..😊
Super teaching mam
ans = -3
is it right ?
Thanks a lot ma'am 😍😍😇😇
Is FINAL answer -3?
Mine is -1
Super bro
Bro explanation pls ?
-3
-3 ans
Happy New Year Madam G.. Thanks Jii
10:58 mam is the ans -2?
super i love you for ur teaching🥰🥰🥰🥰🥰🥰🥰🥰
Thank you ❤
Good explanation mam
Mam aap English kitna simple bolte ho 👌👌🤗🤗
What is the difference between uniary + and binary +
thanx you are great well madam.....
Great going mam 🔥🔥
Mam can u give a more clarity about postfix and prefix with an example
Great Guide ma'am
Keep Spreading knowledge 🥰
Nice teach mam ❤️❤️
My thanks goes to u mam
-2 is my final answer
a= -1
b= 1
c= 0
If it is right please let me know jenny mam
Hey Jenny did you make a video how to deal with functions? Thanks!
Nice maam ur inspiration for me
Thank u very much mam ❤️❤️❤️❤️❤️❤️❤️
answer is -2
👇
Thank you mam for your effort ...
#friend_of_minds
--a*(5+b)/2-c++*b
here, a=0, b=1, c=-1
--0*(5+1)/2-(-1)++*1
brackets, postfix have the same precedence(highest), therefore we have to go from left to right
--0*6/2+1*1
now the prefix has the highest precedence in the above expression,
-1*6/2+1*1
now * / have the highest precedence in the above expression, to break the tie we from left to right,
-3+1
now + has has the highest precedence in the above expression,
-2
We have the values of the variables as,
a=-1, b=1, c=0
Thank you mam for the owsmful video🙏❤️
Thanks maam❤
12:40
Answer : -2
Can u explain?
It is right answer
@@shoba2212
-1*6/2-(-1)*1
-1*6/2+1*1
-6/2+1
-3+1
-2
C has postfix increment then y it still be -1, the value must change to 0 I guess..pls clarify
@@madhukasturi9953 yeah I think ansr is -4
Looking gorgeous mam🥰😍
Sister plz Jarvis Al tell us how to do as your teaching is very understandable and interesting and easy to learn
🤣🤣
Mam thanks 😊 .
I m beginner 🔰 mam give a video how to start
What is the output? Mine is -3
yup
-2 is the output
@@sahilyadav2146 is that correct
@@mani6896 yes
I too got-3👍👍
ta mam...lecture was quite good
Am getting -3 as the ans
-3 will be correct answer..
--a * (5 + b) / 2 - c++ * b
given a = 0, b = 1, c = -1;
--a * (5 + b) / 2 - c++ * b
-1*(5+1)/2-0*1 (--a becomes -1,The value of a is updated to -1 becuase its a prefix dcrement and c is postfix increment so it will be update -1 to 0).
-1*6/2-0*1
-1*6/2-0
-6/2-0
-3 ans................
Correct
Thank you
I kindly Request . To Pls Make Videos on Python As soon as possible mam ❤️ . Because we are Addicted to u 🙏☺️
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Mam I love uu
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ruclips.net/video/qI29eAhdJIc/видео.html
Sister after c++ course jarvis Al mam plz
Thank you so much
I usually watch your videos they so well and I like them. thanks so much.
I would ask you do you know anyone who would teach me data structure and java programming. I'm going to pay for the service.
You are a very experienced and skill in teaching mam .... really
answer is -2 mam
for the last expression
Thank you sow Match miss
Happy New Year mam 🎈🎈
Very use ful
I need online ' c 'course
How run the c program in system
Mam please check priority of postfix (++ and --) is left to right or right to left?????
Left to Right
Mam how to decide the step is L to R, or R to L if both associativity is involved in ques
a=o
b=1
c=-1
--a*(5+b)/2-c++*b
=0*6/2-c++*b
=0*6/2-2*b
=0-2
=-2
Ans is -2
Thanks ma'am
Post inc. Will increase value after that statement... That's why -3
@@anjanhalder7164 can u plz elaborate?
My output is just showing -2
Ans is -2. I was wrong.
@Prajwal @Anjan Halder @VISHAL AWATI Please tell me about the --a when the a is an integer and it's value can be -1 after the --a?🤔
Wrong
Mam discuss about Python course step by step please.....🙏🙏🙏🙏🙏
I could not solve why when a=0, b=1, c=-1 why --a*(5+b)--c++*b comes out to be -2
12.30-( answer is -2 mam)
Can u explain?
video starts at 2:10
Super
Madam ur looking osm🔥🔥
Osm vedio mam
Good
Mam do videos on python programming language
How can we understand between uneary + - and binary + - how can we find difference
Mam add more languages like C++ and JAVA please
good
Madam please upload solving towers of honoi problem in data structures
Mam why the associativity of ?: is right to left in ternary operators we first check condition which is left to right
When u will finish this c programming