Shape of the Nuclear Potential

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  • Опубликовано: 1 янв 2025

Комментарии • 8

  • @brendawilliams8062
    @brendawilliams8062 2 года назад

    Wonderful Lecture. Thankyou

  • @lorenzo1764
    @lorenzo1764 6 лет назад

    Thanks, clear and straightforward

  • @Zhardamon
    @Zhardamon 9 лет назад

    If you shift the wave function by phase angle delta in order to get a continuous wave, then at the merging point the two connected wave functions wont have the same derivative. I dont think you could really do this that way, dont you?

    • @BalerionFyre
      @BalerionFyre 9 лет назад

      +Zhardamon That is a good point because if the amplitudes of each wave are the same but they're frequencies are different, then it would seem that the r values at which the derivatives are the same, there would be a discontinuity in the wave function. Likewise, the r values at which the wave functions has the same value, there derivatives would be different and thus there would be a sharp turn.
      Since it is obvious that the frequencies are different, I think that the only way out of this is to conclude that the amplitudes must be different. This way you could choose each wave amplitude so that, at the r value in question, the functional values and derivatives are both the same. And I think, indeed, that is how the differential equation is solved.

  • @7mus7y
    @7mus7y 10 лет назад

    Really enjoyable videos, I did ohysics at A levels and got an A (no A stars back then) and I had a similar teacher to you. Thanks.

  • @MrRajashik
    @MrRajashik 7 лет назад

    thank you sir!!

  • @kanchansarkar7870
    @kanchansarkar7870 6 лет назад

    Thanks sir..

  • @jimdogma1537
    @jimdogma1537 10 лет назад

    First!