Oh my lord I'm not going to fail science anymore!!!!! BLESS YOU! THANK YOU SO MUCH FOR THIS VIDEO!!! THIS VIDEO MUST BE A GIFT FROM THE GODS!!! THANK YOU SO MUCH FOR THIS! YOU HAVE SAVED MY FUTURE!!!!
Caleb Hubbell Do you mean the subscript 3 in K3PO4? If so, the charge on K is + and the charge on PO4 is 3- so you need 3 K^+ to balance out one PO4^3-, making K3PO4. As to your question regarding H2SO4 + NaHCO3, the products would be Na2SO4 + H2CO3 but the H2CO3 becomes H2O + CO2. Balanced it would be H2SO4 + 2 NaHCO3 -> Na2SO4 + 2 H2O + 2 CO2. Hope that helps!
Kent sir , I have become fan of your videos and also chemistry , the subject I was once thinking of dropping. Thank you for presenting Chemistry in a simple and easy to understand form ,above all making it free and accessible for all.
Thank you very much! I will subscribe! I got to my chemistry class and sit there not understanding one thing that goes on, come home and watch the videos you make and learn it in the matter of minutes. I think for every video I watch of yours my college should send you the money I paid haha. Thank you!
Jarrod Tkach Haha! I'll send them the address of where to mail the check. ;) Glad you're finding it so helpful! Definitely inspiring me to produce new video content. :)
In my textbook sulfates are SO4 (4 as subscript). Is there a reason that sulfurous acid becomes SO3 (3 as subscript) as you have it here in the last example?
This was extremely helpful! I have a test tomorrow of this and i was really nervous, but now i feel very confident. Thank you so much!
+carmen Great! I hope you kicked butt! Be sure to share the chemistry love with your friends and point them to my channel. :)
Your lessons are so easy to understand!!! Thank you!
You're very welcome! Tell a friend!
This was so very helpful. It allowed me to tie in 3 important concepts, naming, solubility and balancing. Thank you.
Oh my lord I'm not going to fail science anymore!!!!! BLESS YOU! THANK YOU SO MUCH FOR THIS VIDEO!!! THIS VIDEO MUST BE A GIFT FROM THE GODS!!! THANK YOU SO MUCH FOR THIS! YOU HAVE SAVED MY FUTURE!!!!
Haha! Happy to hear I was a Godsend. ;) Tell a friend!
Thanks for the encouragement! Make my day and tell a friend. :)
this is such a life saver, writing the compounds out is such great help!!
you helped me a lot with you mentioning to balance the hydrogen separately from the hydroxide...big help ty
+phuniephunie1204 Glad to hear it! That's definitely a tip that has helped me and my students as well. :)
Caleb Hubbell Do you mean the subscript 3 in K3PO4? If so, the charge on K is + and the charge on PO4 is 3- so you need 3 K^+ to balance out one PO4^3-, making K3PO4.
As to your question regarding H2SO4 + NaHCO3, the products would be Na2SO4 + H2CO3 but the H2CO3 becomes H2O + CO2. Balanced it would be H2SO4 + 2 NaHCO3 -> Na2SO4 + 2 H2O + 2 CO2.
Hope that helps!
this was very helpful. especially the part when you said the product will always be salt and water! thank you!
Thanks so much now i understand this just in time for my test tomorrow
Thank you so much! Such a pleasantly presented lesson. It is appreciated!
Thank you so much. This was very helpful and clear! I really appreciate it.
Glad you enjoyed it, Nicole! Be sure to subscribe to be notified of new videos as soon as they're released. :)
Nicole Lipp. I
your vids are so helpful! THANK YOU!!! so much better than anything i read in my textbook
TatianaPetry Awesome! Be sure to subscribe and keep checking back whenever you need help with Chemistry. :)
What I couldn't understand in 6 months I understood in 8 minutes.Thanks
I suppose that's a good thing!? Check out the video "Chemistry Practice Problems: Double Displacement Reactions" for even more examples. :)
Absolutely marvelous. You're a lifesaver!
great video, im ready for my chem test tommorow
Your profile picture is making me think otherwise 😂
did you pass
Kent sir , I have become fan of your videos and also chemistry , the subject I was once thinking of dropping. Thank you for presenting Chemistry in a simple and easy to understand form ,above all making it free and accessible for all.
great, thanks for the help
this makes so much sense now
Glad to hear it! :)
That was honestly so helpful thank youu
I get this more than in my own class, BTW I'm Dutch and I don't get all that in my country but this is just very helpful. Thanks Kent
Videos on solution stoichiometry, and the m1 v1 = m2 v2 stuff would be a major help.
They're on their way, so be sure to subscribe to get notified as soon as they're posted. Thanks!
Thank you very much! I will subscribe! I got to my chemistry class and sit there not understanding one thing that goes on, come home and watch the videos you make and learn it in the matter of minutes. I think for every video I watch of yours my college should send you the money I paid haha. Thank you!
Jarrod Tkach Haha! I'll send them the address of where to mail the check. ;) Glad you're finding it so helpful! Definitely inspiring me to produce new video content. :)
THANKKK YOU, it help me soo much
Very helpful video!!
I'm in 10th grade and this is really helpful!
Oof I'm in 10th grade as well but your probably like in your 20s by now
Alex Kamara how’s life going now
@@jadalove9819 ^ yeah we'd all like to know
This helped a lot thank you
separately balancing the hydrogen and hydroxide was an awesome tip
Wow superb helpful information
thanks for the information , that helps me a lot and i'm going to get a test soon
can you do a video on non-arrhenius acid-base neutralization? How do you determine the products?
So helpful!
Thanks, Jacob! Subscribe and stay tuned for more videos.
Thanks
It is very helpful
Glad to help! Be sure to subscribe to be notified when new videos are uploaded.
Thanks for your great explanation
Extremely helpful thanks so much!
Better than my teacher ngl
How do you know if the acid-base equation requires neutralization or just adding H+ to the base and subtracting H+ to the acid?
Great video
Thank you so much
Great help :)
can you pleas put up how to do pH problems
Thanks so much
Excellent
I'm ready for my Chem test tomorrow
must be nice
@@violetjira6152 same
Thank you Dr.
You're very welcome, Jose! Be sure to subscribe and tell a friend. :)
Fantastic help thanks alot!
very helpful
You are awesome sir!!!
Thanks for the help!
Ted Hadges Glad to hear it! Be sure to subscribe so you never miss a video. :)
Do you mean single displacement?
When Lithium combinded with sulfide, how did Lithium obtain its 2 subscript?
Thank you very much!
thanks a lot!!
You're welcome, a lot! ;)
thanks for the help
In my textbook sulfates are SO4 (4 as subscript). Is there a reason that sulfurous acid becomes SO3 (3 as subscript) as you have it here in the last example?
sulfite not sulfate
i got acid and bases switched up and got a 34 in my exam... now I'm gonna get my final test... wish me luck
I never heard of separating H from OH before thank you
Virgo Lexus Happy to help! Check out my other videos for more helpful tips. :)
Hi! For #2, I was wondering why bromide on the right side is Br2 while on the left it is just Br.
oh wait I understand now
aha thanks for this lesson! it was very helpful
Emily Zhang Glad to hear it, Emily! Keep up the great work. :)
can you explain simple displacement plz :)
I've been wondering this for a while, but what does "(aq)" symbolize or mean?
Yousef Alwan it means aqueous. A solution in water is called an aqueous solution.
+RocKzz T thanks
What grade level is this?
This really helped bro I fucking hate chemistry 🖕🏽😂
do you still hate chemistry
I'm really confused about writing the formulas down
+Forkfour What formulas are you confused about?
I love you
It's easy when you do it...
i'm just year 7
The videos are helpful until you take the exam; work problems to check comprehension.
Oh well I didn't even get one mark on my test...
your voice is very distracting . please surgically alter it. thank you :)
thanks
Thank you so much