Ostwald dilution law / ionic equilibrium / class 11 / L12

[@abhiramiravichandran6328]

Very great.
Within 5 mins explained very well

[@anikatasnim9218]

Perfectly explained within 5 minutes! great. Now I want more 5minutes chemistry. I have no problem understanding it. You are really a good teacher.

[@chirayukesharwani1470]

Thankyou sir the video was very helpful 👍

[@pyaarsepapabolte8060]

GREAT SIR , VEDANTU , UNACADEMY KA DEKHA PAR SIRF AAPKA HI SAMJHA , SACH MAIN , GREAT

[@nosubscribers1869]

*Explained very beautifully!! Love from Nepal sir* ❤❤

[@Secrets.behind.colors]

Thankyou sir for such a simple and less time consuming explanation.👍🏻

[@Nofeesah]

Thank you very much
Your video is more explanative than other video

[@Chemistrygyanacademy]

Glad it was helpful!

[@faryalshujashuja8212]

Great sir👍👍

[@sandeeppant2060]

Gud video .. short simply and easy to understand

[@rinkuchowdhury4314]

Loved it a lot sir❤

[@firasaijazbaba]

This is the best explanation for the topic I've seen

[@ravigautam5691]

Perfectly explain 👌

[@Sky-j2o9p]

Very good explanation thank you so much 👍

[@Chemistrygyanacademy]

I'm glad you found it helpful!

[@nikhilraj7120]

Hello sir....
I am studying in allen kota
In class the teacher explained totally as like you
Great sir

[@Chemistrygyanacademy]

Thanks for appreciation

[@OttianSamim]

Then why you came here?😂

[@vedant544]

Very good explanation 😊

[@Chemistrygyanacademy]

Thanks a lot 😊

[@prajaktashinde528]

Your teaching is best 👍👍

[@laibaaqureshi3274]

Very easy and understandable explaination 👍👍.

[@Chiisuuu]

Thank you sir great explanation

[@Chemistrygyanacademy]

You are welcome

[@stayahead48]

Best explanation ever sir good video liked by meeee

[@Chemistrygyanacademy]

Thanks and welcome

[@_SreejithPM]

Thank You sir For explaining in English.God Bless You too👍

[@Chemistrygyanacademy]

Thanks and welcome

[@lightningstar2356]

(1000th like)😄
god bless u

[@Chemistrygyanacademy]

Thank you so much 😀

[@harshrajput9535]

Very good explanation

[@anjalivaanju5751]

Very good class sir.

[@Chemistrygyanacademy]

Thanks and welcome

[@victorajor2871]

Thank you. Your explanation was super helpful!

[@Chemistrygyanacademy]

Glad it was helpful!

[@itzavishu]

Very nice explation sir💓💓

[@Chemistrygyanacademy]

Thanks and welcome

[@CORPORAL-xg6iv]

Great explanation sir , thank you :)

[@moreshwarbhuskute4950]

Thank you soo much sir it was very helpful for me

[@Mdkaifraza932]

Great sir 👌..... you cleared my concept just in 5mins

[@Chemistrygyanacademy]

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[@Chemistrygyanacademy]

Its a great help if you share my channel on your social media handles

[@mimitsalavouti1314]

Perfect explanation, thank you very much!

[@Chemistrygyanacademy]

Glad it was helpful!

[@SanniJuliet]

Thank you sir

[@hostelitis4835]

Thank you so much sir 🙏🙏you are great....

[@shaikmubarak5234]

Thank you sir...good explanation...

[@JackMillerIndia]

AWESOME SIR!

[@davevevev]

Thanks sir, really well explained

[@dhruvdahivalikar8993]

Thnx a lot sir
👏👏👏

[@payalbhardwaj3762]

Thanku sir. Your video helps me a lot. Thanku so much🥰🥰

[@Chemistrygyanacademy]

Most welcome 😊

[@aditiverma2274]

Thank you sir your video helps me lot

[@Chemistrygyanacademy]

Glad to hear that

[@AshRider-fi2th]

Good understand

[@HangingQueen]

I think you are brother of paras thakur in unacademy
Am i correct??

[@dhanrajjaybhaye9378]

Thanks Sir 🙏

[@masiramulla7749]

Thnx sir 🙃❤️

[@sachithanb8617]

sir please reply what is 'K' in the problem??

[@kjaideep]

K is =dissociation constant of a weak acid

[@tradertalk001]

Thank you sir ❤️

[@abhishekscovers7673]

Thanks a lot sir🥰👍👍

[@Chemistrygyanacademy]

Always welcome

[@futuredr.5986]

Osm explanation

[@Chemistrygyanacademy]

Thank you

[@asmitbisht2951]

Sir thanks

[@rijultandon728]

Awesome

[@abbaspeham7845]

Sir dgree of dilution kia hai

[@thefistschool2235]

thank u sir

[@Chemistrygyanacademy]

So nice of you

[@Chembynlsir]

Thank you

[@sunderverma6133]

So nice

[@njr145]

Sir thanks a lot sir

[@nehayadavnehayadav4147]

Thanku sir 🙏

[@RAJENDRAKUMAR-in1qx]

Good sir

[@Chandrakant0404]

𝓝𝓲𝓬𝓮 𝓿𝓲𝓭𝓮𝓸 𝓼𝓲𝓻

[@upasanaupadhyay5650]

Thank you.

[@Chemistrygyanacademy]

You're welcome!

[@Rajputanish_268]

Thanks sir.. Hmko lga tha ki aap bhul gye.
Lekin sir video's K duration thode jyada hote to aur accha lgta.
I'm not forcing you but it's a suggestion

[@tanusingh5490]

Dissociation kaise ho raha hai

[@tanusingh5490]

Alpha ka

[@Chemistrygyanacademy]

Alpha is taken as degree of dissociation means out of 1 mol of salt alpha moles are dissociated. As we have C moles of salt so C *Alpha moles are dissociated.

[@tanusingh5490]

Kohlraush's and ostwald dilution law mai different

[@Chemistrygyanacademy]

Yes

[@bishnupriya4443]

@@Chemistrygyanacademy tq so much sir🙏

[@roshanneupane2264]

Good video but Hindi maa vako va jhan ramro huntho hola. 🇳🇵🇳🇵🇳🇵🇳🇵🇳🇵

[@hamdanfareed]

Nepal flag 😂😂😂😂😂😂

[@AshRider-fi2th]

Nive

[@dasouvik123]

c is not equal to 1/v......C is proportional to 1/v

[@Chemistrygyanacademy]

It's equal to 1/V when number of moles equal to one. You are also right if moles are not fixed. But I fixed the number of moles as one.

[@dasouvik123]

Yes Sir . I understand mistakenly

[@shubhekshachand8793]

Thank you sir

[@namratawadibhasme667]

Thank you sir ☺