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It’s a secondary alcohol so only undergoes one oxidation, despite being under reflux.
This topic is hard 😔
At 5:29,Since alcohol E is heated under reflux, do we use 2[O]?We use 2[O] because in reflux the condenser is placed vertically which allows 2 stages of oxidation.Do all reflux oxidation reactions require 2[O]?Thanks
Why must it be 32 S at 8:47?
It’s a secondary alcohol so only undergoes one oxidation, despite being under reflux.
This topic is hard 😔
At 5:29,
Since alcohol E is heated under reflux, do we use 2[O]?
We use 2[O] because in reflux the condenser is placed vertically which allows 2 stages of oxidation.
Do all reflux oxidation reactions require 2[O]?
Thanks
Why must it be 32 S at 8:47?