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What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on RUclips) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test.
Without choaching students please read this... I m in 11th class studying in "The aakash" instiute... Preparaing for medical.. But trust me guys there is nothing special in these institutes ... Uh knw wht we have completed gravitation like chapter in 3 classes for 1 hour 30 min duration not just clearing the concepts like alakh pandey sir give us.who give us 8 lectures on it ... They just give us books enough.. I just want to make uh believe guys uh can too crack exam without choaching ... Do hard work be regular ... Please like this if it help uh in anyway to motivate yourself... Just showed the reality
Its not like that.. Coaching se faiyada b h bhoot but yah aisa b nhi h tht kuch ho nhi skta coaching ke bina... Uh can too crack exam without coaching .. Do hard work 😊 praticse mcq
For Screenshot ==> 3:37 = Formula of RMS Velocity 8:37 = Derivation of Formula of RMS Velocity 11:38 = Q1 (Based on RMS Velocity) 14:36 = Q2 (Based on RMS Velocity) 15:58 = HW - Q1 (Based on RMS Velocity) 21:10 = RMS Velocity in Terms of Pressure & Density 31:42 = Maxwell's Distribution of Velocities 35:24 = Introduction to Free Path & Mean Free Path 47:43 = Derivation of Formula of Mean Free Path
@@nidhikeshan2665 see if it was 300°C (for H2) the answer which is coming is 9168 but if it was 300°K the answer is 4800°K which is in option..so it was a bit wrong..nothing else
18:40 for finding that Vrms is inversely proportional to square root of density we can also get it from d = PM/RT, RT/M = P/d, Vrms = under root 3RT/M = under root 3P/d. Hence Vrms is inversely proportional to the square root of density.
Aapke channel ka ab tak ka sara physics ka lecture dekh chuka. Physics ko maine real jindgi me jiya sir. Thanks a lot sir. Iit nikalne ke baad mai aapse jrur se jrur milunga sir... My dear sir. Mai 10th ke baad financial weaknesses ke karan mera padhai chhuth gya. Pr mujhe isaki kami feel nahi hone di. Mera jee ka exam 2022 me hoga sir . Aur iit jane se pahle aapse aashirwad jarur lunga sir
Sir, Sabse pehle mey apko thanks kehna chahungi apke physics ke difficult and tricky topic ko itna easy and elaborate way mey numerical ke saath samjhaane vale videos ke liye.... Jo mene der se dekhe kyuki pehle I don't have any access to Internet, on those samajh nhi aata tha kaise kr paungi pr ab lagta h kr lungi...... Vo alag baat h ki abhi time se race chal rhi h kyuki Dec tk pura krna Sir apke padhne ke tarike ka universal law ban sakta h ki aapka padhne ka tarika especially physics Superb👏👏👏👏👏👏👏👏👏👏👏👏h pure universe mey (#Pw law ya LAW OF SUPERB PHYSICS TEACHING ) Or dusra mera doubt Vrms is a Velocity or a speed? as in maxwell distribution curve when u write vavg before it "u said another speed like"
@@ArmanMulla-l1j Sir ne question me 300°C likha hai, agar isko kelvin me convert krke solve karenge to ans 9168 aayega, pr agar quest. Me 300K lekar solve kren to ans 4800 aayega!!
Assalamualaikum, sir apka bahut bahut shukriya sir ap jio hazarao saal sir ap ne pura topic yt per pada Diya aj Kal Kon bhi aisa nahi karta ap sab se dayalo aur ap duniya ke sab se ache insaan ho sir allaha bless you sir apki jo bhi preshani ho vo door hujaye ap ki income bade ap isse bhi zyda uncha muqaam hasil kare Meri duva hai...🥺❣️💕💯💯
You are my best teacher ever in my whole life I say with confident that i will never able to get a teacher like you. You are the only & only 1 masterpiece love you sir ♥️♥️♥️♥️
12:55 ANS: T1=T2 For H2=> √R*T1/M=Vrsm √R*T1/M= x T1=x^2/4 Since Temp is same as For H2 gas, therefore T=x^2/4 For O2=> √R*T2/M=Vrsm putting t=x^2/4 and R is constant i.e. 8.314 (maine toh 8 li h iski value), we get: Vrsm for O2 = x/4
Find the temperature at which oxygen molecules would have the same rms speed as of hydrogen molecules at 300k . Then answer is 4800k 16:00 But in question sir given h.w Ans is 9168 will be correct answer Awesome lecture with full of josh ❤️💐😁😁😁😁😁😁😁😁😁👍👍👍👍👍👍
The ques at 15:26 has a error it will be 300 K rather than 300°C which sir as written by mistake...as on solving ques considering 300°C the ans is approx 9168 K bt on considering 300 K u will get option C of ques that is 4800 K...I wish u all will understand...at last sir you are the best phy teacher...♥️♥️♥️
Sir if I take Temperature of Oxygen in 300 degree celsius then I get 9168 but there isn't any option for this result sir previously we have taken Temperature of Oxygen in 27 degree Celsius if take Temperature as 27 degree Celsius then I get 4800K sir :)
Many gases such as nitrogen, oxygen, hydrogen, noble gases, some heavier gases like carbon dioxide and mixtures such as air, can be treated like ideal gases within reasonable tolerances over a considerable parameter range around standard temperature and pressure.
Sir I wanted to ask u a Question, 10 th ke liye aap jo pada rahe hai physics and chemistry, voh bahut hai yaa book se aalag phir se padna padega. Sir I'm so weak pls reply. And thanks for video very nice.👍👍👍👍
Sir at 16:30...HW Q... the temp should be in 'K' ..soo that the temp is 300 K and after that the ans will be "c.4800" ...bcoz with 300*C the ans coming is 9168 K which is not given in options...
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2)Live Classes and recorded Video Lectures (New, different from those on RUclips)
3)PDF Notes of each class.
4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.
5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.
6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
7)In case you missed a live class, you can see its recording.
8)You can view the videos any number of times.
9)Each chapter will be discussed in detail with all concepts and numericals
10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.
****Test Series for XI & XII****
We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.
H. W Q. Answer is C) 4800
@@next_in question mein 300 celcius mein de rakha hai 300 Kelvin mein hota toh yeh answer aata
@@aarti8103 meri marzi kya karlega
@@aarti8103 ha
@@aarti8103 u hi
Without choaching students please read this... I m in 11th class studying in "The aakash" instiute... Preparaing for medical.. But trust me guys there is nothing special in these institutes ... Uh knw wht we have completed gravitation like chapter in 3 classes for 1 hour 30 min duration not just clearing the concepts like alakh pandey sir give us.who give us 8 lectures on it ... They just give us books enough.. I just want to make uh believe guys uh can too crack exam without choaching ... Do hard work be regular ... Please like this if it help uh in anyway to motivate yourself... Just showed the reality
Hi ayushi can i help waise me kota se coaching kr rha hoon iit ka
@@kishansingh4939sure... what help you would do..?
@Ayushi Singh.... really coaching se koi fayeda nhi h ??😮😮😮
AYUSHI AKASH K KIS CENTRE ME HO
Its not like that.. Coaching se faiyada b h bhoot but yah aisa b nhi h tht kuch ho nhi skta coaching ke bina... Uh can too crack exam without coaching .. Do hard work 😊 praticse mcq
Best!!! Mera naam Physics Wallah...or hamara or aapka pyara sa channel Alakh Pandey 😂😂😂😂
Reverse ho gaya
😂 Reciprocal hogya
This is the reverse or u can say reciprocal theorem. 😂😂😂😂
Good
its evolving.. just backwards
ATQ, T = 9168K
And if 300K is taken ,then the answer would be (c) 4800 K
Ryt
Yes bro
@@karansahni3533 kese bro
In kalvin temp will be 573k if temp is taken 300*C
@@karansahni3533 but fir to ans 9168k aata he na
For Screenshot ==>
3:37 = Formula of RMS Velocity
8:37 = Derivation of Formula of RMS Velocity
11:38 = Q1 (Based on RMS Velocity)
14:36 = Q2 (Based on RMS Velocity)
15:58 = HW - Q1 (Based on RMS Velocity)
21:10 = RMS Velocity in Terms of Pressure & Density
31:42 = Maxwell's Distribution of Velocities
35:24 = Introduction to Free Path & Mean Free Path
47:43 = Derivation of Formula of Mean Free Path
Mean free time reh gaya , sir ne cover nahi kiya
Thanks bhai It save my time
Bhai kuch kam me nhi aaya
Made my day
Thanks a lot siddharth
I DONT THINK AANE WALE SMAY ME KOI LAKHON RUPAY DEKE OFFLINE PDHEGA AGR AAP JAISE TEACHER SATH HO. VO BHI ONLINE FREE. THANK U SOOO MUCH SIR
correct
offline class feels more interactive u know
Your predictions...🔥
Became true❤
16:30
Sir yahan temperature 300°C ki jagah 300K, nahi aana chahiye, isse, answer would be c. 4800K
I m also confused
I also figured that
@@nidhikeshan2665 see if it was 300°C (for H2) the answer which is coming is 9168 but if it was 300°K the answer is 4800°K which is in option..so it was a bit wrong..nothing else
Ya right 300° c laka ans approx 9168 k arra
Yes 300 k ma hi hona chaiya
Sir I think 300calcius ky jagaha 300K hoga. Tho ans 4800K ayaga.
Yes 300℃ nhi hoga....
Yes. Apologies
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Haan sir 300k heho gai
Yeah
Who wants PHYSICS WALLAH COMPLETE 800000 subs in these year
Like for A.P sir
Utne log neet ya jee 2020 likhrahe h👆?
Now 10 million ok bhaiya or behen
Now 1.2 cr
10:47 me doing all the calculation after pausing the video by taking R=8.314 . Le alakh sir isko 8 maan liya jaaye 😂😂😂😂
😂😂😂
sameee
Same 😂😂😂
Dimag ko use karna sikh lo
Toh aisa nahi hoga
@@mika4444 r u a weeb
18:40 for finding that Vrms is inversely proportional to square root of density we can also get it from d = PM/RT, RT/M = P/d, Vrms = under root 3RT/M = under root 3P/d. Hence Vrms is inversely proportional to the square root of density.
sir made a mistake there by equating (V rms)2 = ROOT(3PV/M) am i right?
@@ItsMe-uv8kv yeah i also think
Ab dukh bhare din bito re bhaiya kyuki ab alakh sir ayoooo re👍👍👍👍👍👍👍👍👍👍
Sahi bola
Aapke channel ka ab tak ka sara physics ka lecture dekh chuka.
Physics ko maine real jindgi me jiya sir.
Thanks a lot sir.
Iit nikalne ke baad mai aapse jrur se jrur milunga sir... My dear sir.
Mai 10th ke baad financial weaknesses ke karan mera padhai chhuth gya. Pr mujhe isaki kami feel nahi hone di. Mera jee ka exam 2022 me hoga sir . Aur iit jane se pahle aapse aashirwad jarur lunga sir
Itni subah kaun video upload karta hai 😱. A big salute sir.
Kitne baje aayi thi video?
Kitne baje aayi video???
Sir aap baccho se bahut achhe se interact karte hai ...And u r a god gift to those students who are not able to get coaching from kota..
Legends are watching this video on nov 2021😂
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Yup struggling for finals🤣
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@@Mriganka25 yes absolutely
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Sir,
Sabse pehle mey apko thanks kehna chahungi apke physics ke difficult and tricky topic ko itna easy and elaborate way mey numerical ke saath samjhaane vale videos ke liye.... Jo mene der se dekhe kyuki pehle I don't have any access to Internet, on those samajh nhi aata tha kaise kr paungi pr ab lagta h kr lungi...... Vo alag baat h ki abhi time se race chal rhi h kyuki Dec tk pura krna
Sir apke padhne ke tarike ka universal law ban sakta h ki aapka padhne ka tarika especially physics Superb👏👏👏👏👏👏👏👏👏👏👏👏h pure universe mey (#Pw law ya LAW OF SUPERB PHYSICS TEACHING )
Or dusra mera doubt
Vrms is a Velocity or a speed? as in maxwell distribution curve when u write vavg before it "u said another speed like"
After watching lecturs of alakh sir.. I can solve all the problems from my coaching material ..Thankyou sir..
Worlds biggest salute and respect to your mother who has born such a legend
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@@vikki9762 Hmm..🙏🙏Hamari responsibility hai ki Hum Like kre 💯💯
@@vikki9762 now it is 2.34
@sadaf ansari yeahhh ikik....2 weeks ago it was 2.34 and now 2.38
Over smart hai ye
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Jan abhi nahi jayegai kyu ki physics wallahe sir hai Zindabad,😙😙😎
Waah
T=9168k if we take 300°c , when we take 300°K then T=4800K answer is C
16:11 at 300°C for H2 vrms for O2 is 9168K
But at 300K for H2 vrms for O2 is 4800K which is option (C)
that is not vrms that is temp.... temp for oxygen is 9168k and 4800k
How
@@ArmanMulla-l1j Sir ne question me 300°C likha hai, agar isko kelvin me convert krke solve karenge to ans 9168 aayega, pr agar quest. Me 300K lekar solve kren to ans 4800 aayega!!
@@gkdhkdky 2400 hoga
4800 hoga Calc check karlo ek bar
Assalamualaikum, sir apka bahut bahut shukriya sir ap jio hazarao saal sir ap ne pura topic yt per pada Diya aj Kal Kon bhi aisa nahi karta ap sab se dayalo aur ap duniya ke sab se ache insaan ho sir allaha bless you sir apki jo bhi preshani ho vo door hujaye ap ki income bade ap isse bhi zyda uncha muqaam hasil kare Meri duva hai...🥺❣️💕💯💯
You are my best teacher ever in my whole life I say with confident that i will never able to get a teacher like you. You are the only & only 1 masterpiece love you sir ♥️♥️♥️♥️
is this the last lecture for this chapter?
Yes
@@preetiraut787yes
" Isko special maine banaya hai, ye kuch special paida nahi hua tha" Literally Felt it Sir!!
16:25 Ans is 9168 if you take temprature in Kelvin (573k)
But by °C (300°C) answer is C 4800
Thank you so much man, I was confused and thought that I did something wrong
Answer of question is option c 4800 k when temperature of H^2 is 300k and if temerature of H^2 is 300 °C then answer is 9168k
Sir u are just superb
.. I improved
a lot because of u
Absolutely
Correct
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Kyuki legends ka JEE hai Feb me LOL!
I am also watching in 2021 😁😁😁
Bro legends are watching this in 2021 and thinking that this video is not available on physics wallah app.
Ultra Legends watching before one day of exam
Kal exam he me aaj dekh rha hu
After watching his videos of physics in class 12.. I continued to watch him for chemistry bsc part 1.. He is super awesome 🙌🙌
3:30 , sir ur alternating current video lectures was awsum
16:30 9168 K.... When we take temp. as 300°C
4800 K..... When we take temp. as 300 K
That correct no body is perfect
Sir itni thand mein subah subah lecture........... 😱😱😱😱😱
HARDWORK
🤯
@@kritikagrover6117 girlfriend bano gi 😅🥺🥺
@@ashutosh2_0_0_3 😂
4th & 5th lecture kha h ??
Answer is coming 9100.7 approx. When taken Tof H↓2 as 300°C or 573 K
Mene ye lecture bhi dekhkar notes 📝 bana liye 🙏👍
Sir physics is incomplete without you.❤
Answer 9168kelvin when temperature 300°c
Answer 4800kelvin when temperature 300kelvin
12:55 ANS:
T1=T2
For H2=>
√R*T1/M=Vrsm
√R*T1/M= x
T1=x^2/4
Since Temp is same as For H2 gas, therefore T=x^2/4
For O2=>
√R*T2/M=Vrsm
putting t=x^2/4 and R is constant i.e. 8.314 (maine toh 8 li h iski value), we get:
Vrsm for O2 = x/4
Q)15:58
Ans if taken 300°C ans is 9168 K
And if taken 300K ans is 4800 K
correct
I also thought that
thank u jaanu
Ye ham hai
Ye hamare alakh sir hai
Aur ye hamari padhai ho rahi hai
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Pakistan me bhi physics he kya
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Find the temperature at which oxygen molecules would have the same rms speed as of hydrogen molecules at 300k . Then answer is 4800k
16:00 But in question sir given h.w
Ans is 9168 will be correct answer
Awesome lecture with full of josh ❤️💐😁😁😁😁😁😁😁😁😁👍👍👍👍👍👍
Yes
Bro but no option
Sorry
Sir, please make a video on distance of closest approach in Kinematics.
You tube pe bhot se se teacher hai or to or pace batch bhi chal rha hai , Lekin abhi tk sir ke pdaye hue lecture dekhte hai❤️❤️
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Sir thank u so much...for teaching us😳
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Maxwell's distribution of Velocities 21:50
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sir in the hw question the ans would be 9168K
but if the temp is 300 K then the ans is c) 4800K
Right
Sir at 16:07 par ek question me sir jo temprature hai wo 300 k lene p answer aa raha h , 300 c lene par nhi.
Hmmm u r correct
Yes
Yes bro
Sahi hh bhai....4800 degree Celsius aayega...
👍
congrats on completing this short yet imp chapter mate !!more power to you love you all
Sir I am Maharashtra state board student but still your video s are enormous helpfull for me ...thank you
If you are watching this video in 2024 then you're legend
July 31 2023
sir
16:00 ans is 9168 K
(c)will be right if T is in (K)
Thank you sir ☺️☺️☺️
16:27
Sir question mey 300'C k jgh Kelvin hona chiye tha..tb answer 4800K aarha hai. Otherwise 300'C ko ley kr answer 9168k hai.
Yes bro
@rohan saxena 😂mera to alag aaya to me direct comments me aa gaya tha
@rohan saxena sameeeeeee
@@shreyash8294 op😂
@rohan saxena same here
Infinity aura if you are watching it in 2025 😂
The ques at 15:26 has a error it will be 300 K rather than 300°C which sir as written by mistake...as on solving ques considering 300°C the ans is approx 9168 K bt on considering 300 K u will get option C of ques that is 4800 K...I wish u all will understand...at last sir you are the best phy teacher...♥️♥️♥️
Amazing lecture sir!!!!! Loved it...!!!
9168 K... When we take temp. as 300°C
4800 K... When we take temp. as 300 K
@Asad Khan correct answer will be 9168K
@@shubhanshurajiitm7335 agreed
Can uhh give solution of this ques??
@@ossumindia4995 read the question it is given 300 degree C so convert it into kelvin
Mera naam physics wallha. Hamara aur aapka pyara sa channel alakh pandey. 🤗🤗🤗👌👌👌Bhut mast bole sir..
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Kb kha sir ne
@Lisha Kumari ye video suru ka half minute dekho.
@@dobby4445 watch my comment
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See what u are writing
I am telling you about English ,(sister)
ruclips.net/video/29I4gCEyFrI/видео.htmlbest video of alakh sir
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Friends, this concepts are enough for neet
Yes
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Ans is 4800K ( T= 300*32/2 by using √3RT/M)
16:00
Agar 300k liya to 4800k
❤️✨THANK U SIR 😻🔥
Sir if I take Temperature of Oxygen in 300 degree celsius then I get 9168 but there isn't any option for this result sir previously we have taken Temperature of Oxygen in 27 degree Celsius if take Temperature as 27 degree Celsius then I get 4800K sir :)
The question points out that the Vrms of O2 at “300*C” and H2 at T(Kelvin)
🧠👈🏽
Sir aapne 300°c likha hai us hisaab se temperature 9168 aa rha hai
Or agar use Kelvin mana jaye I think aapko Kelvin likhna tha tab 4800 aayega 🙏🏻😃
That's right I'm also agree with ur answer
Yess ur right my ans is also 4800
Sir I completed 👌💯 this lecture now.
And congratulations 🎉🎉🎉 sir for marridge.
Rip to those watching this 1 day before exam on 2x speed
😂😂😂
My exam is today
M aasa hi kar raha hu kyuki kal h exam h
2days watching at 3am
itna accurate kaise ho bhai😅
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Sir, i think temperature given is incorrect.... Apke question ke liye sahi answer hai 9168 kelvin....
yes ,l think also
haa bro agr kelvin me nikalo to itna hi aa rha h pr agr celcius me nikalo to opt. c shi h
Sahi bola
Ha sahi h
Many gases such as nitrogen, oxygen, hydrogen, noble gases, some heavier gases like carbon dioxide and mixtures such as air, can be treated like ideal gases within reasonable tolerances over a considerable parameter range around standard temperature and pressure.
Sir 16:30 ans is 4800K
But you the given temperature is degree centigrade which should have been in Kelvin.
Sir I think instead of 300degree celsius it would be probably 300 K
Consequently our ans would be 4800 K
THANK YOU SO MUCH SIR FOR BEST EXPLANATION..........
Are you in class 11
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sir, you are all in one for our chemistry and physics
Option c:) 4800K
But i can't understand why we put the temp in this question in celsius and get the answer in kelvin
You're probably giving 12th preboards now, but same is happening with me
Sir answer for the given question is 4800K(temp of O2).
How
16:28 ..The answer is (C)4800K
Point me aayega aapi
Mera mtlb exact 4800 nhi aayega 4584 final h jo approx h
Kon kon enn vedios ko 2022 me dekh rha I want to see how many students like sir old way of teaching. 🙂🙂🙂🤗🤗🤗
Sir I wanted to ask u a Question,
10 th ke liye aap jo pada rahe hai physics and chemistry, voh bahut hai yaa book se aalag phir se padna padega. Sir I'm so weak pls reply. And thanks for video very nice.👍👍👍👍
no u need not to i also studied from video and I got 94 in chemistry and in physics 88 icse board exam last year
Thank you very very much sir. Just because of you, no question will be skipped from this chapter ☺️❤️💕🙏
Sir answer for the question at 16:27 is 4800K option C
thankyou sir
Sorry to say par sir videos thodi late aa rhi hai aajkal
Is everything fine?
T=9168k
In Kelvin( 273+300)K
√3*R*573/√2 = √3RT/√32
Squaring both side
R and 3 cancel
573*16=9168 answer
Ya too option he nhi ha....
Yhi aata ha k..ma..c. ma 4800..aata ha
Sir at 16:30...HW Q... the temp should be in 'K' ..soo that the temp is 300 K and after that the ans will be "c.4800" ...bcoz with 300*C the ans coming is 9168 K which is not given in options...
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Yes sir
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Yes sir please
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Sir Jo ab padha rahe h bhai wo padh lo yr pehle ye sir ne bhi kaha tha isse demotivation milta h
Sir temperature of O2 is 4850kelvine option (c)
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13:14 ans. d) x/4
16:23 300°C nhi 300k lena h sir ne galti se 300°C likh dia
300°C lene se answer ayega 9168K
300K se correct answer ayega 4800k(option C)
Right mein bhi soch rha tha kya galti kari hein But temperature kelvin mein hoga 😊