I just came across the 3D glasses example kinda by accident, and the more I experimented the more confused and perplexed I got. After watching a bunch of videos and still feeling slightly disappointed by their explanations I came across this one. This was expertly explained and your demonstrations helped a ton. I love youtube videos from the earlier days, always the purest content.
That is a very beautiful demonstration involving day to day experience making it comparatively easier to understand the whole polarization concept. Good job Kevin..!
YOU NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOB BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
5:25 I still don't understand how did the intensity increased ? I mean in polarisation, I2 = I1 (cosx)^2 So intensity should have decreased But it increased ? I don't think it should have been possible in an isolated system
The colours in the Petri dish arise because the plastic is birefringent, meaning that it has not one but two polarisation axes each with their own index of refraction. The polarised light is resolved into two perpendicular waves which travel at different speeds through the plastic. The parts of these two waves that are parallel to the analyser interfere, producing interference colours much like those seen in a slick of oil on the surface of a puddle or in soap films.
Videonun bilgiyi aktarım kalitesine bayıldım. Thank you for this much effective way delivering this concept at this much of ease. Demonstrations are so valuable
Hi there, thanks for your demonstration, however at 6:07, you polarise them horizontally and than you use your sun glasses which are polarised vertically, how can you go light, from the horizontal, the intensity should be zero.
Good spot! This is an example of the extinction ratio. This is the ratio of the unwanted to the wanted light. So a ratio of 1:10 would mean that for every 10 photons of light you want (horizontally polarized in this case), 1 of vertically polarized light makes it through. You can also think of this as a fraction; 1/10 (I think this is more useful as we can just multiply with it). (To be even more confusing, some people write this ratio the other way; 10:1) An extinction ratio of 1:10 is pretty bad, but probably about right for my cheap pair of sunglasses. The square polarizers are better, so let's say that they have an extinction ratio of 1:500. What does this do for the light that we see in the video? The light that makes it through to the camera has to make it past both. So here's the breakdown of what happens (V = vertical, H = horizontal). Light source: Initially unpolarized light a 1:1 mix of V and H. Let's use the numbers; 500 V and 500 H. First polarizer: This is set to allow H light, but the extinction ratio is 1:500, so for every 500 H, we still get 1 V (or we just multiply the light by the extinction ratio: 500 V * 1/500 = 1V). We now have; 1 V and 500 H. Second, square polarizer. This is set to allow V light to pass, But the extinction ratio is still 1:500, so some H light makes it (again, 500 H * 1/500 = 1H). So the camera 'sees'; 1 V and 1 H. Only 2 units out of the 1000 we put in. That's pretty good, we can round that down to 'zero'. What happens if we replace the second polarizer with the (not so good) sunglasses: After first polarizer: 1 V and 500 H Second, sunglasses: These have an extinction ratio of 1:10, so the amount of H light that makes it is 500 H * 1/10 = 50. So the camera 'sees'; 1 V and 50 H This is 50x larger than the previous case! Which, is exactly the difference in extinction ratios; 1/10 / 1/500 = 50. But it gets worse if you have two bad polarizers! Here's the math replacing both polarizers with sunglasses: Starting with: 500 V and 500 H After first (H sunglasses): 50 V and 500 H After second (V sunglasses): 50 V and 50 H So now we've let through 100 units of light total, double the previous case! This is why if you're shopping for polarizers one of the numbers you'll see is the extinction ratio. Typical cheap lab polarizers are in the 1:500 or 1:1000 range. Really good lab polarizers are in the 1:100,000 range!
Saw a video where the two opposing lenses nothing gets through light changed the look of certain gems to lots of colors and different geometric patterns. I think quartz was one. (Edited) Found it. I don't know how to paste a link but the video is called 12 foundation stones of new jerusalem. It's 2 yrs old only has about 6k views. I forgot this video says some gems like diamonds look black in different light. Why have i never heard of this? Wife and daughter are into rocks, me too. This is interesting.
Thanks a lot for this video. I find myself coming back to it occasionally. I am now curious about this behaviour at 4:35 . 1) Why does this behaviour occur at all? 2) Is there any name for this behaviour that I can lookup on the net?
Re-radiation. It's "re-radiation" of the light energy (EM wave) at a new polarization angle. Take a look at the vid below- the metal grate is re-radiating the microwave energy in the direction that the grate is positioned, having intercepted the RF from the transmitting end at 45 degrees. So, re-radiation of the RF then takes place at the new 45 deg angle AND is picked up at the far end receiver. ruclips.net/video/KM2TkM0hzW8/видео.html&t=116 Also, this MIT demo goes into a little more detail: ruclips.net/video/AVn49LbYoB8/видео.html
Good job Kevin! Thanks for making this Video. I am having a problem with my progressive prescription polarized sunglasses. While I am driving, each time I look at the navigation screen, I tend to tilt my head slightly to the right to look at the screen, and when I do the light from the screen is blocked and I can't see it. I didn't have this problem with my old clip-on sunglasses that I used to clip on to my old progressive prescription glasses.
Thanks so much for this ! Do you think that polarised light therapy (500-2500nm) can be more effective than regular red light therapy due to a wider spectrum of light combined with polarisation ? Does polarisation of light increase its capacity to permeate the skin ??
Ok so in the first case where both first and second polarizer were in horizontal and analyzer was in vertical - A horizontal light has no vertical component so we see dark But in second case 2nd polarizer was in a angle with both 1st polarizer and analyzer. And it has both vertical and horizontal component so we can see the light through that glass Now your question is why we are seeing more brighter light, now here malus law comes in we now intensity of light directly proportional with the square of value of cosine of that particular angle. So the more value of cosine will increase the more brighter light will be. And at 90° cos =0 and at 0° it's 1 we are seeing brighter so we can say to get brighter light 2nd polarizer will be in less angle with analyser.
so it's like a slope and movement? going forward with a wall in front of you gets you stopped, but if you put a gradual slop to change directions it'll change the direction to up? (no gravity etc)
Best demonstration of polarization I've seen! Thanks for taking the time to demonstrate it. Also, I've read that there is a theory that turtles are able to find new bodies of water to migrate to by being able to see the polarized light reflecting off the water. Can you explain how this is possible? Thanks
***** I had the same question. The key to understanding this is that a diagonal vector has horizontal and vertical components! So what the middle filter does isn't bending the light but rather allowing the horizontal or vertical components (according to the middle filter's direction of axes) through. The sunglasses at the end do the same thing.
I think it's not a linear wave like people demonstrate, it's a three dimensional field. I believe that all fields pass through even if we don't see the light. I think the polarized glass change the shape of the field making it invisible through our eyes and the other glasses reshape back to normal somehow.
What does it get darker when the two filters are place together with the axis aligned ? Shouldn't intensity be the same since the polarized light is already blocked by the first filter ?
awesome explanation . amazing. Before watching this video I thought polarisation as topic I could never be able to understand but now I am curious about it. thanks 😘
Hi Kevin, great video! Thanks a lot for sharing how to show this effect. Just to be sure, you now place the polarization filter in front of your cameralens. But do you also see the colors when you just look with your eyes through the polarization filter? And is the petri dish you are using a glass or plastic one? Can I use it to see the stress in a glass of wine for example?
Good question, let me explain in words and then try a diagram as well. After the, say, left-circular (LC) polarized light is reflected from the mirror and becomes right-circular (RC) polarized. The 'circular' polarizer, isn't actually just a circular polarizer. It's a quater-wave plate (1/4-wave plate). This transforms the RC light to linear polarized. But it's polarized 90-degrees to the linear polarizer it encounters next. So the linear polarizer ultimately blocks the light. Here's an attempt at a diagram: Incoming light (arrows show direction of light - read from right to left): | No light out ^mirror
how would you filter light by virtue of its magnetic component? Would there be some kind of lines. So is the polarizing filter containing lines that are proportional to the amplitude of the light? Low amplitude light would thus make it through. Does this mean light flows through space as planes that can make it through slots? If so then the magnetic component at right angles to it would have the volume where two sides are equal to the plane of the light ray which is a two dimensional plane and it would have some arbitrary third dimension at right angles to the plane of the light.
Let me re-order your questions somewhat: "how would you filter light by virtue of its magnetic component?" I haven't thought much about this. While we typically draw pictures with the magnetic component (B) equal in size to the electric one (E), the magnitude of B = E / c - so it's much smaller. This means that it's typically easier to manipulate light by the electric component. "Does this mean light flows through space as planes that can make it through slots?" For linear polarization - yes, you can think of it like this. Of course, not all slots will act as polarizers - they have to have an interaction with the field. "polarizing filter containing lines that are proportional to the amplitude of the light? Low amplitude light would thus make it through." Typical polarizing filters do not care about the amplitude (or intensity) of the light. We call this "linear optics" because things get brighter / darker in a 1:1 ratio with the light getting brighter / darker. There is a field of "nonlinear optics" which studies what happens when this doesn't work. For example, when the response changes depending on the brightness of the light. "If so then the magnetic component at right angles to it would have the volume where two sides are equal to the plane of the light ray which is a two dimensional plane and it would have some arbitrary third dimension at right angles to the plane of the light." I'm not sure what you mean? Perhaps you could link to a picture?
re: "how would you filter light by virtue of its magnetic component? " Same way one would 'filter' the magnetic wave from an EM radio wave; its not an easy proposition at light wavelengths, much easier at radio wavelengths, as in the use of ferrite loop antennas (magnetic loop).
still doesn't explain why my room projecting outside building with colours and movement. I just wanted to know why I see the building with its original colours on my wall. I know it somehow being projected from my window but I'm just curious.
perfect explanation, but i think that the expression for the sun light polarization is due to the difference between the plane of polarization of the aye and that of polarizer
That's incorrect. The human eye is not sensitive to the polarization of light. This is why we need eg, the analyzer to view the polarized stress in the plastic cup. Bee eyes are another matter.
Today i took one specs from 3d movie theatre and i found that both the sheets present on specs are polarized screen i took one sheet out and saw through it from changing its angle from one face it seems to become yellow and blue and from other SIDE NOTHING happened as its now become plan polarized. After that i put that one sheet on other sheet present on other side of specs when i put it and start rotating it changes intensity as I/2 and when i putted that sheet on other side i saw that it makes rainbow effect which is in high intensity and when i started rotating it other colors coming so how that is working . And ya i have one more polarized screen which i took out from my old button nokia phone and results are different this time it only changes intensity no color effects . Plz explain
sweet. I was wondering about those 3D glasses for a long while now. I used to have tons of fun popping the lens out and watching it change colour as I turned them in front of each other. So since it lets light come in differently from each side, that makes sense why it's not recommended to wear them as sunglasses. XD
nejinaji Ah good spot! The sunglasses aren't a pure polarization filter. They're a polarizing film placed on a plastic lens. monitor light ---> polarizing film | plastic lens --> eye By flipping it around; monitor light --> plastic lens | polarizing film --> eye you put the plastic between the monitor and the polarizer. Then you get colors for exactly the same reason that the colors appear on the petri dish - the polarizing coating visualizes the strain in the plastic lenses. Naturally this would be distracting for drivers, hence why the polarizing film goes on the outside of the lens. You can verify this with another piece of plastic monitor light --> plastic --> sunglasses (normal way) --> eye = colorsmonitor light --> sunglasses (normal way) --> plastic --> eye = no colors
3 minutes in and anyone paying some amount of attention would understand polarization, great contribution, the internet is pleased.
4:30, understanding destroyed
@@skaramicke 🤣🤣🤣
I just came across the 3D glasses example kinda by accident, and the more I experimented the more confused and perplexed I got. After watching a bunch of videos and still feeling slightly disappointed by their explanations I came across this one. This was expertly explained and your demonstrations helped a ton. I love youtube videos from the earlier days, always the purest content.
How people dare to dislike such a video when that much effort is put in. Thanks a lot !!
That's is RUclips's fuckin algorithm
Less than 0.03% of views disliked this. What are you even on a tiff about?
Better than my 1 hr physics class
So many presenters on YT get the 3-polarizer explanation wrong, but, you got it right!!
Congrats.
Your practical examples really quenched the trust.....!
No theory can clear the things in such a intresting way ☺
That is a very beautiful demonstration involving day to day experience making it comparatively easier to understand the whole polarization concept. Good job Kevin..!
YOU NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOB
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
~one of the most coolest way to understand polarized light~
Thanks a bunch, im in Electricity,Magnetism & Optics right now and next monday is my final. This is a great explanation of Malus Law!
Best demonstration of polarization I've seen!
Very lucid elegant explanation. Thanks a lot Mr. Kevin.
Wonderful way to express the idea of polarisation. I like your practical approach, thank you.
thank you for explaining polarization so well, i hope your doing amazing!!
Sir we were just to take off our heads to put this topic into our head. U just showed us what exactly it is....thank you...
splendid teaching...........thanx a lot!
You have the mind of a teacher. Good job.
5:25
I still don't understand how did the intensity increased ?
I mean in polarisation, I2 = I1 (cosx)^2
So intensity should have decreased
But it increased ?
I don't think it should have been possible in an isolated system
It became polarised at a diff. angle that's why it regained the intensity, as it no longer made 90° with the sunglasses & the 2nd polariser.
The colours in the Petri dish arise because the plastic is birefringent, meaning that it has not one but two polarisation axes each with their own index of refraction. The polarised light is resolved into two perpendicular waves which travel at different speeds through the plastic. The parts of these two waves that are parallel to the analyser interfere, producing interference colours much like those seen in a slick of oil on the surface of a puddle or in soap films.
Nice vid! Why exactly are different parts of the sky reflecting a variety of polarisations?
Fate. Hirata, Pillars of light, Eyes of Wisdom, Fate. Crow and Declaration, Between front and back, Imaginary Technique, Hollow Purple
Videonun bilgiyi aktarım kalitesine bayıldım. Thank you for this much effective way delivering this concept at this much of ease. Demonstrations are so valuable
Wow really thanks for the video. Very useful and informative video.
I just wonder how amazing nature is
Hi there, thanks for your demonstration, however at 6:07, you polarise them horizontally and than you use your sun glasses which are polarised vertically, how can you go light, from the horizontal, the intensity should be zero.
Good spot!
This is an example of the extinction ratio. This is the ratio of the unwanted to the wanted light. So a ratio of 1:10 would mean that for every 10 photons of light you want (horizontally polarized in this case), 1 of vertically polarized light makes it through. You can also think of this as a fraction; 1/10 (I think this is more useful as we can just multiply with it). (To be even more confusing, some people write this ratio the other way; 10:1)
An extinction ratio of 1:10 is pretty bad, but probably about right for my cheap pair of sunglasses. The square polarizers are better, so let's say that they have an extinction ratio of 1:500. What does this do for the light that we see in the video?
The light that makes it through to the camera has to make it past both. So here's the breakdown of what happens (V = vertical, H = horizontal).
Light source:
Initially unpolarized light a 1:1 mix of V and H.
Let's use the numbers; 500 V and 500 H.
First polarizer:
This is set to allow H light, but the extinction ratio is 1:500, so for every 500 H, we still get 1 V (or we just multiply the light by the extinction ratio: 500 V * 1/500 = 1V).
We now have; 1 V and 500 H.
Second, square polarizer.
This is set to allow V light to pass, But the extinction ratio is still 1:500, so some H light makes it (again, 500 H * 1/500 = 1H).
So the camera 'sees'; 1 V and 1 H. Only 2 units out of the 1000 we put in. That's pretty good, we can round that down to 'zero'.
What happens if we replace the second polarizer with the (not so good) sunglasses:
After first polarizer:
1 V and 500 H
Second, sunglasses:
These have an extinction ratio of 1:10, so the amount of H light that makes it is 500 H * 1/10 = 50.
So the camera 'sees'; 1 V and 50 H
This is 50x larger than the previous case! Which, is exactly the difference in extinction ratios; 1/10 / 1/500 = 50.
But it gets worse if you have two bad polarizers!
Here's the math replacing both polarizers with sunglasses:
Starting with: 500 V and 500 H
After first (H sunglasses): 50 V and 500 H
After second (V sunglasses): 50 V and 50 H
So now we've let through 100 units of light total, double the previous case!
This is why if you're shopping for polarizers one of the numbers you'll see is the extinction ratio. Typical cheap lab polarizers are in the 1:500 or 1:1000 range. Really good lab polarizers are in the 1:100,000 range!
fenerbahce262 What are you asking?
Thanks so much, Kevin. Greetings from Spain.
Great video man you explained every concept of polorization with examples in one video.
Man this explains so much things, bro I gotta thanks you what an amazing video
Saw a video where the two opposing lenses nothing gets through light changed the look of certain gems to lots of colors and different geometric patterns. I think quartz was one. (Edited) Found it. I don't know how to paste a link but the video is called 12 foundation stones of new jerusalem. It's 2 yrs old only has about 6k views. I forgot this video says some gems like diamonds look black in different light. Why have i never heard of this? Wife and daughter are into rocks, me too. This is interesting.
Thanks a lot for this video. I find myself coming back to it occasionally. I am now curious about this behaviour at 4:35 .
1) Why does this behaviour occur at all?
2) Is there any name for this behaviour that I can lookup on the net?
Re-radiation. It's "re-radiation" of the light energy (EM wave) at a new polarization angle. Take a look at the vid below- the metal grate is re-radiating the microwave energy in the direction that the grate is positioned, having intercepted the RF from the transmitting end at 45 degrees. So, re-radiation of the RF then takes place at the new 45 deg angle AND is picked up at the far end receiver.
ruclips.net/video/KM2TkM0hzW8/видео.html&t=116
Also, this MIT demo goes into a little more detail:
ruclips.net/video/AVn49LbYoB8/видео.html
Good job Kevin! Thanks for making this Video.
I am having a problem with my progressive prescription polarized sunglasses. While I am driving, each time I look at the navigation screen, I tend to tilt my head slightly to the right to look at the screen, and when I do the light from the screen is blocked and I can't see it. I didn't have this problem with my old clip-on sunglasses that I used to clip on to my old progressive prescription glasses.
Best video on polarisers. Thanks a lot.
Thank you for these awesome demonstrations👏👏💖
100 times better than my Indian rote learning education system
Really made the topic more intresting! Loved it!!
Thanks so much for this ! Do you think that polarised light therapy (500-2500nm) can be more effective than regular red light therapy due to a wider spectrum of light combined with polarisation ? Does polarisation of light increase its capacity to permeate the skin ??
Thanks for clearing my concepts on this topic, From India
I still dont know, why the lamp appears brighter at 4:31, did anyone understand?
Ok so in the first case where both first and second polarizer were in horizontal and analyzer was in vertical -
A horizontal light has no vertical component so we see dark
But in second case 2nd polarizer was in a angle with both 1st polarizer and analyzer. And it has both vertical and horizontal component so we can see the light through that glass
Now your question is why we are seeing more brighter light, now here malus law comes in we now intensity of light directly proportional with the square of value of cosine of that particular angle. So the more value of cosine will increase the more brighter light will be.
And at 90° cos =0 and at 0° it's 1 we are seeing brighter so we can say to get brighter light 2nd polarizer will be in less angle with analyser.
awesome explanation.👌
fantastic explanation of applications ...keep it up bro
so it's like a slope and movement? going forward with a wall in front of you gets you stopped, but if you put a gradual slop to change directions it'll change the direction to up? (no gravity etc)
Best demonstration of polarization I've seen! Thanks for taking the time to demonstrate it. Also, I've read that there is a theory that turtles are able to find new bodies of water to migrate to by being able to see the polarized light reflecting off the water. Can you explain how this is possible? Thanks
Where can i get those linear polarising filters?
You made polarization so much more fun for me! Thankyou!
nice, thank you for the enlightening ^^ I was looking for that exact simple explanation
repolarized? I see it, but I don't buy it. You're saying that the sandwiched filter is 'changing' the polarity of the light wave?
Yes, it does - but in the case of the sandwiched filter it comes at a cost. The filter blocks some of the light, reducing the overall brightness.
***** I had the same question. The key to understanding this is that a diagonal vector has horizontal and vertical components! So what the middle filter does isn't bending the light but rather allowing the horizontal or vertical components (according to the middle filter's direction of axes) through. The sunglasses at the end do the same thing.
I think it's not a linear wave like people demonstrate, it's a three dimensional field. I believe that all fields pass through even if we don't see the light. I think the polarized glass change the shape of the field making it invisible through our eyes and the other glasses reshape back to normal somehow.
What does it get darker when the two filters are place together with the axis aligned ? Shouldn't intensity be the same since the polarized light is already blocked by the first filter ?
awesome explanation . amazing. Before watching this video I thought polarisation as topic I could never be able to understand but now I am curious about it. thanks 😘
what a brilliant demonstration
Real life explanation wow..simple but powerful
My mind was blown, thank you for that
You nailed it in our understanding. Thanks 😊
How come when you overlap the second polarizer with the same axis as the first one, it dimmed the light slightly?
that was a smooth learning curve.. gr8 video.. Thank you :)
Fabulous vedio !!!
Thanks kevin sir
For doing this experiment.
Why the 3D glasses change the colour of the light apart from its polarisation?
Brother what is that glass ur using for the rotation
Thank you very much for making this video. It was pretty easier for me to understand than other videos. Keep it :D
Nice experiments, can you tell me what kind of flashlight is that?
very much thank u . I was reading stress analysis and in photoelasticity it helped me a lot
That was so helpful to understand the polarization in an interesting way thanks
How does the “repolarization” alluded to at ~6.00 because to that point i see polarization filters are removing photons in proportion to sine theta…
how do you explain polarization in terms of photons? We're told light is a particle. Can a particle/photon be polarized?
Hi Kevin, great video! Thanks a lot for sharing how to show this effect. Just to be sure, you now place the polarization filter in front of your cameralens. But do you also see the colors when you just look with your eyes through the polarization filter?
And is the petri dish you are using a glass or plastic one? Can I use it to see the stress in a glass of wine for example?
Thanks a lot Mr. Kevin.
That was great! I wish I had found it before. Thank you very much Kevin.
Very well explained, thank you! At the very end when the light is reflected off the mirror, is it blocked by the linear polarizer or the circular one?
Good question, let me explain in words and then try a diagram as well. After the, say, left-circular (LC) polarized light is reflected from the mirror and becomes right-circular (RC) polarized. The 'circular' polarizer, isn't actually just a circular polarizer. It's a quater-wave plate (1/4-wave plate). This transforms the RC light to linear polarized. But it's polarized 90-degrees to the linear polarizer it encounters next. So the linear polarizer ultimately blocks the light. Here's an attempt at a diagram:
Incoming light (arrows show direction of light - read from right to left):
| No light out
^mirror
How does polarization support the model that light is an electromagnetic wave?
Sir which material consist that polariser please tell..
how would you filter light by virtue of its magnetic component? Would there be some kind of lines. So is the polarizing filter containing lines that are proportional to the amplitude of the light? Low amplitude light would thus make it through. Does this mean light flows through space as planes that can make it through slots? If so then the magnetic component at right angles to it would have the volume where two sides are equal to the plane of the light ray which is a two dimensional plane and it would have some arbitrary third dimension at right angles to the plane of the light.
Let me re-order your questions somewhat:
"how would you filter light by virtue of its magnetic component?"
I haven't thought much about this. While we typically draw pictures with the magnetic component (B) equal in size to the electric one (E), the magnitude of B = E / c - so it's much smaller. This means that it's typically easier to manipulate light by the electric component.
"Does this mean light flows through space as planes that can make it through slots?"
For linear polarization - yes, you can think of it like this. Of course, not all slots will act as polarizers - they have to have an interaction with the field.
"polarizing filter containing lines that are proportional to the amplitude of the light? Low amplitude light would thus make it through."
Typical polarizing filters do not care about the amplitude (or intensity) of the light. We call this "linear optics" because things get brighter / darker in a 1:1 ratio with the light getting brighter / darker. There is a field of "nonlinear optics" which studies what happens when this doesn't work. For example, when the response changes depending on the brightness of the light.
"If so then the magnetic component at right angles to it would have the volume where two sides are equal to the plane of the light ray which is a two dimensional plane and it would have some arbitrary third dimension at right angles to the plane of the light."
I'm not sure what you mean? Perhaps you could link to a picture?
re: "how would you filter light by virtue of its magnetic component? "
Same way one would 'filter' the magnetic wave from an EM radio wave; its not an easy proposition at light wavelengths, much easier at radio wavelengths, as in the use of ferrite loop antennas (magnetic loop).
Thanks Kevin. Can you please explain 5:40-5:55 again. Doesnt make sense. Please be clear. thanks /MJ
no words can express my appreciation than I love you hhh
very good job! this will hopefully help me with the understanding for my electromagnetics exam next week :)
We're in 2020,i wanna ask u, did u pass the exam?? ☺️☺️
Just an aswm explanation.....Very clear concept.....Just amazing......😍😍😍❤Aswm job brh!!!....Keep making videos like this.....I reaply love it.....
Its really not reaply😂
still doesn't explain why my room projecting outside building with colours and movement. I just wanted to know why I see the building with its original colours on my wall. I know it somehow being projected from my window but I'm just curious.
Great explanation, thanks for upload this kind of useful videos. It helped me a lot to learn about this subject matter.
Thank you so much Kevin 👏👏👏👏
Quick Question: Is there a difference between an Analyzer and polarizer?
which glass u used ???
Thank you very much!!! I only wanted to see an animation but a real life experiment is more helpful :D
Cool video, thanks for the explanation and demonstrations!
perfect explanation, but i think that the expression for the sun light polarization is due to the difference between the plane of polarization of the aye and that of polarizer
That's incorrect. The human eye is not sensitive to the polarization of light. This is why we need eg, the analyzer to view the polarized stress in the plastic cup.
Bee eyes are another matter.
thank you so much for your explanation. very helpful!
excellent examples ! i commend you
Glow array of spherical photons get pole arrayed or polarized via certain crystals. Tensors.
what pulls it back to 0?
if light has a electrical field then why we not sock .plese answer me
Excellent explanation.
Great explanation, Now I can apply my 3D glasses to microscopy.Thanks.
Truly fascinating!
Wow 👍
Today i took one specs from 3d movie theatre and i found that both the sheets present on specs are polarized screen i took one sheet out and saw through it from changing its angle from one face it seems to become yellow and blue and from other SIDE NOTHING happened as its now become plan polarized. After that i put that one sheet on other sheet present on other side of specs when i put it and start rotating it changes intensity as I/2 and when i putted that sheet on other side i saw that it makes rainbow effect which is in high intensity and when i started rotating it other colors coming so how that is working . And ya i have one more polarized screen which i took out from my old button nokia phone and results are different this time it only changes intensity no color effects . Plz explain
sweet. I was wondering about those 3D glasses for a long while now. I used to have tons of fun popping the lens out and watching it change colour as I turned them in front of each other.
So since it lets light come in differently from each side, that makes sense why it's not recommended to wear them as sunglasses. XD
that was a really nice demonstration ! tysm
Hey from where did you get those cards. .
I notice that with some phones polarized sunglasses will often block the light.
so if you flip the polarized lens of sunglasses (so they are looking at you) against a monitor and see that rainbow effect, whats that mean.
nejinaji Ah good spot! The sunglasses aren't a pure polarization filter. They're a polarizing film placed on a plastic lens.
monitor light ---> polarizing film | plastic lens --> eye
By flipping it around;
monitor light --> plastic lens | polarizing film --> eye
you put the plastic between the monitor and the polarizer. Then you get colors for exactly the same reason that the colors appear on the petri dish - the polarizing coating visualizes the strain in the plastic lenses.
Naturally this would be distracting for drivers, hence why the polarizing film goes on the outside of the lens. You can verify this with another piece of plastic
monitor light --> plastic --> sunglasses (normal way) --> eye = colorsmonitor light --> sunglasses (normal way) --> plastic --> eye = no colors
Kevin Claytor Hey there! May I know where to get a polarizer glass? By the way.. awesome lesson and demonstration
great job,now a will be able to tell if sun glasses genuine or not
How did you make the index cards? I am a teacher and I think that would be great for the students to do !
We can buy it online.
@@june756 Where?
You are amazing.....❤️❤️
one of the best on this topic, thanks!
Awesome!! Keep it up ❤️
Thanks a lot, learned a lot in 15 minutes