Thanks so much! This video made me figure out that a 0.47F 5.5V capacitor is actually two 0.94F capacitors wired in series. The capacitance goes down to about half (0.47) while the voltage rating goes up.
Really nice explanation. For me knowing what's happening "under the hood" it's always easier to remember things. Coz hard knowledge get always forgotten bud knowing the concept one can deduce the hard knowledge. The example with dialectic surface and thickness is perfect.
does this mean in the parallel circuit if it has the same capacitance in each capacitor, do you add them all? or do you have to divide them in half and get their total capacitance as half since they are all the same?
I don't fully understand how in the series case, if the charge can just act on the plate across the dielectric, essentially forcing electrons to move through the circuit; then why does the current stop when the combined p.d of the captors is equal to the batteries e.m.f? Is this because if it continued to flow beyond this point it would gain a greater p.d than the battery, thereby violating energy conservation law (and kirchoff voltage law)?
Thanks so much! This video made me figure out that a 0.47F 5.5V capacitor is actually two 0.94F capacitors wired in series. The capacitance goes down to about half (0.47) while the voltage rating goes up.
This is an extremely well explained and useful series. Thank-you!
Really nice explanation. For me knowing what's happening "under the hood" it's always easier to remember things. Coz hard knowledge get always forgotten bud knowing the concept one can deduce the hard knowledge. The example with dialectic surface and thickness is perfect.
You are saving my butt preparing for the eta2 test thank you!
Dave, thanks a lot! Very useful channel, I will recommend it to others as well, who want to learn AC theories.
He went straight to the concept. Instead of a winding road that leads to confusion.
I really like the way you explained it and didn't speak 1000 miles an hour .
Thanks allot for this helpful class.
does this mean in the parallel circuit if it has the same capacitance in each capacitor, do you add them all? or do you have to divide them in half and get their total capacitance as half since they are all the same?
I don't fully understand how in the series case, if the charge can just act on the plate across the dielectric, essentially forcing electrons to move through the circuit; then why does the current stop when the combined p.d of the captors is equal to the batteries e.m.f? Is this because if it continued to flow beyond this point it would gain a greater p.d than the battery, thereby violating energy conservation law (and kirchoff voltage law)?
thanks dave! great vids
why it isn't a same case in series batteries?
You are the don!
انت معلم
Can you take one farad and show us in a circuit with one led/resistor and how long it will work/light...
Look into supercapacitors.
Please how do you get that 6v
so how do i work out disparate value series capacitors am still looking for that bit of the title.. ?
1/C = 1/C1 + 1/C2
Thank you for saving my ass
Dave I don’t know what local you’re from but I could kiss you right now
LU46
I fucking switched it and now I have a B. goddamn it