#37 Python Tutorial for Beginners | Pass List to a Function in Python

[@poojithareddy7346]

lst=[]
for i in range(5):
x = input("Enter the name")
lst.append(x)
def count(lst):
greater = 0
lesser = 0
for i in lst:
if len(i) >= 5:
greater += 1
else:
lesser += 1
return greater,lesser
greater,lesser = count(lst)
print("greater : {} and lesser : {}".format(greater,lesser))

[@saadahnaf208]

'f len(i) >= 5 ', assignment is more then five letter.

[@cityrunner-x3x]

Unlike other tutors, watching Mr.Navin teaching never get bored.Very active and motivating.

[@ravikumarsingh3680]

you lie

[@ojasvisharma3021]

@@6ft333 ayoo why you here😂😂😂 you learnt python??????

[@harshvora1922]

Assignment :
def counts(lst):
more = 0
less = 0
for i in range(len(lst)):
if len(lst[i]) > 5:
more = more + 1
else:
less = less + 1
return more, less
list = []
x = int(input("How many names you want to enter:"))
for k in range(x):
list.append((input()))
more, less = counts(list)
print('Names more than 5 characters : {} and Names less than 5 characters : {}'.format(more, less))
Output :
How many names you want to enter:10
amitabh
shahrukh
ranveer
harsh
naveen
moushmee
viral
suraj
ishan
karan
Names more than 5 characters : 5 and Names less than 5 characters : 5
Process finished with exit code 0

[@yashsharma685]

what if the no. of names are not defined or asked..... any no. of names to be added.

[@satyajitsahoo1064]

for k in range(x):
list.append((input()))
what is the need of this Mr.Harsh??

[@AJabcdefghi]

@@satyajitsahoo1064 x inputs will be taken and each time list will append i.e new inputs will be added to the list x times

[@karthik3778]

@@satyajitsahoo1064 If you don't specify the length of list ,then you to always add the same number of elements to the list.
Ex.for i in range(5):
Here you cannot add more than 5 elements to the list

[@vj729]

@@satyajitsahoo1064 to append (add) the names given by the user into the blank list [] created

[@gadgetunboxing8485]

def name(lst):
lst2=[]
count =0
for i in lst:
if len(i)>=5:
lst2.append(i)
count = count+1
else:
continue
return lst2,count
lst=[]
for i in range (0,10):
x=(input("Enter a name "))
lst.append(x)
print(lst)
lst2,count=name(lst)
print ("Name greater than 5 letter or equals ",lst2)
print ("Total number of person ",count)

[@Yash8147]

Thanks Navin Reddy for this wonderful tutor. Really it's an interactive and interesting session :) Please try to give us more assignment so that we can think a lot on it.
def count(list):
lengthy_name=0
short_name=0
for i in list:
if len(i)>5:
lengthy_name+=1
print(i,end=", ",)
else:
short_name+=1
return lengthy_name, short_name
list=[]
x=int(input("Enter how many names would you like to enter:"))
for k in range(x):
list.append(input('Enter Name: '))
lengthy_name, short_name = count(list)
print('
')
print('Names more than 5 char: {} and Names below 5 char: {}'.format(lengthy_name,short_name))

[@bov._.v]

it has and error

[@bov._.v]

an*

[@ale94ge]

Assignment:
list_names = []
n = int(input("Enter the lenght of the list: "))
for i in range (1,n+1):
names = input("Enter the names: ")
list_names.append(names)
print("Here the list of names:", list_names)
five_letters =[]
for k in list_names:
if len(k)>=5:
five_letters.append(k)
else:
continue
print("Here the names with more than five letters:", five_letters)

[@bss.]

def count(lst):
x=0
for i in lst:
if len(i)>=6:
x+=1
print('no.of names having more than 6 letters ', x)
lst=[]
for j in range(10):
a= str(input('enter name'))
lst.append(a)
count(lst)

[@devasish204]

Good Evening Everyone, here I am to master Python 3, great effort by Naveen, looking up to you man.
I come from 0 experience in programing, after doing lot of research about where to learn python, I ended up here...
Lets Began...!

[@Meego_007]

def count(lst):
for i in lst:
if len(i)>5:
print(i)
a=[]
print("enter the names")
for i in range (10):
name=input("")
a.append(name)
print(a)
count(a)

[@riaz_ay]

assignment 2:
lst=[(input())for i in range(10)]
def count(lst):
k=0
for i in lst:
if len(i)>5:
print(i)
k+=1
return k
count=count(lst)
print("the no is:{}".format(count))

[@yogeshkumarshankariya642]

name = []
for i in range(5):
name.append(input("Please enter the name"))
for i in name:
if len(i)>5:
print(i)
else:
pass

[@ramprasath4050]

by the way, where is the function??

[@ayushsahu1475]

y=[]
x=int(input('how many username uw ant to enter'))
for i in range(x):
k=input('enter your name')
j=len(k)
if j>5:
y.append(k)
l=0
for e in y:
l=l+1
print(l)
hw question

[@uvishnuprasad2944]

def count(lst):
lesser =0
notlesser=0
for i in lst:
if len(i)

[@ainaryaravindkumar4681]

def count(lst):
length = 0
for i in lst:
if len(i)>=5:
length += 1
else:
pass
return length
lst = list(map(str,input("Enter the names = ").split()))
length = count(lst)
print("Names = {}".format(length))

[@kasyapmaddala7341]

Solution for the assignment qsn(display count and names with length more than 5):
//10 Names from user
from array import *
arr=[]
n=10
for i in range(n):
x=input("enter the name")
arr.append(x)
print(arr)
//Count and display the names with length more than 5
cnt=0
for j in (arr):
if(len(j)>5):
print("name:{},length:{}".format(j,len(j)))
cnt+=1
print("Total number of names with length more than 5 is:" ,cnt)

[@yogeshwarprasad6797]

#1
from array import *
n = int(input(' enter the lenght of string = '))
list = array('i',[])
for i in range(n):
x = int(input("enter the next number = "))
list.append(x)
def count():
even = 0
odd = 0
for i in list:
if (i%2==0):
even = even +1
else:
odd = odd +1
return(even,odd)
print(list)
e,o = count()
print("even : {} and odd :{}".format(e,o))

[@HarryPotter-jd1dx]

thanks sir....i was trying this and got nothing..it really helped me (:

[@puneet8705]

why use array tho when you can simply do with list

[@shreeja9265]

def name(lst):
for i in lst:
if len(i)>5:
print(i)
a = []
b = int(input('enter length of list : '))
print(f'enter {b} strings :')
for i in range(b):
c = input()
a.append(c)
name(a)

[@12nov83]

assignment
lst=[]
i=int(input("Enter the numbers of lists:"))
for k in range (i):
n=input("enter the name:")
lst.append(n)
print(lst)
lst1=[]
for l in lst:
count=0
for m in range(len(l)):
if m < len(l):
count += 1
if count >= 5:
lst1.append(l)
print("list count grater than five :")
print(lst1)

[@chiragukey7283]

def count(x):
l = 0
for i in x:
if len(i)>5:
l+=1
print(l)
x = []
for i in range(5):
y = input('enter the name')
x.append(y)
count(x)

[@hruthiksai7061]

# this program is to check the number of user inputs having len of 5 or more than
lst = []
n = int(input('enter the size of the list'))
for i in range(0,n):
x = input('enter the next string')
lst.append(x)
print(lst)
count = 0
for i in lst:
x = len(i)
print(x)
if(x>=5):
count = count + 1
print('the no of inputs that have length of string more than 5 are :',count)

[@4kmovies157]

You don't use the function here know

[@kavitanailwal9634]

HURRAY! WE GOT OUR WINNER.

[@shubhambhosale8467]

its showing error

[@soumithjavvaji3310]

easy solution without complexity:
lst1=[]
def soumith(lst):
for i in lst:
if len(i)>5:
lst1.append(i)
print(lst1)
lst=['sachin','virat','dhoni',......(10 names)]
soumith(lst)

[@klausop69]

what can be done if we want the input to be taken from the User itself only. Could you please modify the code and resend it ??

[@praveen1193]

@@klausop69 Use input() to read values from keyboard and store it in list and pass it to function

[@puneet8705]

@@klausop69 then you will need to define an empty list first,
and then using for loop each time you ask for a input from the user and append it to the list

[@NikhilWhiskyKumar]

sir ur natural linguistic speed already 1.25x speed XD

[@omkarmore7017]

Seriously even i experienced that on the go.

[@sr-ju4lq]

😂😂

[@kritikajaiswal3712]

😂😂😂😂😂

[@AaryanGupta-c4g]

def count():
for i in range(4):
a = input("Enter a name: ")
if len(a) >= 5:
print(a)
count()

[@atulayagupta785]

list = []
a = int(input("Enter the number of names you want to enter:" ))
for i in range(a):
names = input("Enter the names: ")
list.append(names)
print(list)
count = 0
countless5 = 0
for i in range(a):
lenght = len(list[i])
if lenght > 5:
count +=1
else:
countless5 +=1
print("Count of names having letters greater than 5", count)

[@anandbhojane8156]

Thankyou brother

[@BalajiSuresh1995]

assignment:
def names(user):
count = 0
for i in user:
if len(i) > 5:
count += 1
return count
x = int(input('enter the total number of names'))
lst = []
for i in range(x):
x = input('enter the names')
lst.append(x)
print(lst)
count = names(lst)
print('names greater than length five are {}'.format(count))

[@prof.fauwazparkar9446]

here in for loop, input shall be replaced with raw_input as string to be used for names

[@aniketaher4691]

'''Program to print names which contain
more than 5 letters from given names'''
def count(l):
for i in l:
if len(i)>5:
output.append(i)
else:
pass
print(output)
l=[]
output=[]
i=0
while i

[@chinmaydas4053]

Many many thanks sir.. We are getting two great python videos in a same day 🙏🙏🤗...

[@alienyijoseph6318]

def len_of_name(len):
upper=0
lower=0

for name in user:
if name.isupper():
upper+=1
elif name.islower():
lower+=1
length=upper + lower
print(length)

user=input("enter the names:")
print('The number of the names character entered is:')
len_of_name(user)

[@easydatascience2508]

Try mine too. The channel gives playlist for Python and R, hope they will be helpful. Source codes available too.

[@snowbraze6299]

def display(list):
print(list)
for i in list:
if len(i)>5:
print(i)
list=[]
for i in range(5):
name=input("enter the names")
list.append(name)
display(list)
it takes 5names from user and print the names with more than 5 letters

[@prabalagrawal4058]

Soln of assignment:-
from numpy import*
x=[]
n=int(input('enter the length:'))
for i in range(n):
z=input('enter the names:')
x.append(z)
def count(n):
a=0
for i in x:
if(len(i)>5):
a=a+1
print("
names of person having letters greater than 5:",i)
else:
pass
print("
no of persons",a)
count(X)

[@vikramsey]

Code for assignment problem :
# create the list of names
x = int(input('Enter number of inputs: '))
lst = []
for i in range(x):
name = input('Enter next name: ')
lst.append(name)
# defining the function
def name(lst):
x = 0
for i in lst:
if len(i) >= 5:
x += 1
print(x, 'names with five or more letters.')
# calling the function
name(lst)

[@tapansaha6624]

great

[@ajayprajapat18]

bhai esme x me jitne bhi name likhate h vo sab output aa rha h

[@BhuveshDhiman]

def count(list):
a=0
b=0
for i in range(len(list)):
if len(list[i])>5:
a+=1
else:
b+=1
return a,b
list=[]
k=int(input("Enter no of names you want to enter"))
for i in range (k):
list.append(input("Enter a name"))
a,b=count(list)
print("Names > 5 = {} and names

[@axwaizee9582]

entr = ''
names = []
def count(names):
return max(names, key=len)
while True:
inpt = input("Enter the names (Press Enter on completion):
>")
if inpt == entr:
break
names.append(inpt)
print(count(names))
to be honest i searched for max() function on Google but that input part is legit made by me fully by me 😌😌

[@deepakvm1475]

print("enter the 10 names")
def finds():
max=5
for j in range(1,10):
if max

[@vishwasbharadwaj9386]

Hi Navin. You can print the output as
print(f'Even : {even}, Odd : {odd}'). It might look easy for learners I feel.

[@nehaaadarsh]

How can it be print??
Dude it gonna generate error

[@prathyushareddy8386]

@@nehaaadarsh What error did it generate to you? @vishwas is right :
print(f'even : {even} and odd : {odd}')
>> even : 5 and odd : 6
f is used instead of using format. try it and reply

[@dishantkumbhar8822]

@@nehaaadarsh it works fine

[@karthikeyanatmakuru1349]

@@prathyushareddy8386 i agree with u we can use f instead of using format function

[@tabzeal8726]

@@karthikeyanatmakuru1349 it work good

[@just_a_living_being]

def name(name_list):
return sum(1 for i in name_list if len(i) > 5)
print('Enter 10 names: ', end='')
name_lst = [input() for i in range(10)]
print(name(name_lst))

[@Maks05N]

can you explain why you were using sum(1) in for loop

[@just_a_living_being]

Here "1 for i in name_list if len(I) > 5" gives 1 if name length is greater than 5 and sum function add these 1's together

[@just_a_living_being]

You can checkout "list comprehension" for better understanding

[@sagarsinha668]

def fun(str):
F_L=0
for chr in str:
if len(chr)>5:
F_L+=1
return F_L
val=list(input("enter your name: ").split())
res=fun(val)
print(res)

[@navinduabhishek8564]

Assignment
def count():
counter = 0
for i in range(5):
name = input('Enter name: ')
if len(name) > 5:
counter += 1
print(counter, "users name has length more than 5 letters")
count()

[@cloudlyrics9344]

def count(list):
name5=0
namegr5=0
for i in list:
if len(i)

[@YONAnYONA]

Thanks! Navin for this wonderful tutorial on python. It's really easy to understand and the assignment making me much curious to learn python .
def lst(User_lst):
for i in User_lst:
if len(i)>5:
print(i)
names=[]
for i in range(0,10):
names.append(input("Enter a name: "))
print(names)
lst(names)

[@new_beginning2571]

printing list of even and odd separately
lst=[]
lst_even=[]
lst_odd=[]
num=int(input('enter the no of elements'))
for i in range(num):
x=int(input())
lst.append(x)
def even_odd(a):
even=0
odd=0
global lst_even,lst_odd
for i in a:
if i%2==0:
lst_even.append(i)
even+=1
else:
lst_odd.append(i)
odd+=1
return even, odd
even , odd=even_odd(lst)
print('even : {} and odd : {}'.format(even,odd))
print("even no. =",lst_even)
print("odd no.=",lst_odd)

[@giveaway4002]

I really like the way he taught in such as small time .keep videos short, more information and accurate. thank you

[@AdityaSingh-v6r]

# 1) Take 10 names from the user and display the names that have length greater than 5.
x = int(input("Enter the number of elements: "))
list = []
for i in range(x) :
list.append(str(input("Enter the element: ")))

# print(list)
def count(list):


for i in list:
if len(i) > 5 :
print(i)

length = count(list)

[@divyanshusingh6105]

def length(name):
for i in name:
if(len(i)>=5):
print(i)
name = [str(input("Enter Name:"))for i in range(11)]
length(name)

[@skaliya5158]

Hii sign ' can u explain
How the 10 names added to name =[]

[@divyanshusingh6105]

@@skaliya5158 In List First i used input function which will run 10 times and for each input length function will be run and check the length of the input if the name have more than 5 characters it will print

[@skaliya5158]

@@divyanshusingh6105
Can u tell me how u get this type kwldg its cool ":)
Pls give me some advice so that i can also get this typ of kwldg

[@tushargupta6570]

lst = []
for i in range(1, 11):
x = input("Enter: {} name out of 10 ".format(i))
lst.append(x)
def count(lst):
length = 0
for i in lst:
l = len(i)
if(l>5):
length+=1
return length
ans = count(lst)
print("Total number of names with length more than 5 chracters =", ans)

[@harisbagwan9984]

#Name Count with User input
def namecount(lst):
for i in lst:
if len(i)>5:
print(i)
lst=[]
for i in range(0,5):
n=input('Enter Name:')
lst.append(n)
lst
namecount(lst)

[@Habonzgold]

1. def count(lst):
2. greater = 0
3. lesser = 0
4. for i in lst:
5. if len(i)>5:
6. greater+=1
7. else:
8. lesser +=1
9. return greater
10. lst= [input(f'enter name number {i+1}') for i in range(10)]
11. greater = count(lst)
13. print('Number of names with length greater than 5 is = {} '.format(greater))

[@deveshmaniar4383]

thanks a lot for this video, Kudos to you for your initiative, I am beginning to learn. Have a question - When i tried to use even and odd (summation within if) ,it gives zeroes. is there a reason why it is doing like that. I had to use even=even+1, odd=odd+1 to get the results.
please let me know, thanks again
🙂

[@shivanshtiwary5829]

def name(lst):
for names in lst:
if len(names) > 5:
print(names)
li = []
for inp in range(10):
a = input()
li.append(a)
name(li)

[@Notyouranalyst]

hey bro could you help me with this video (from 1:36 - 2:30)
please bro help me out bro

[@prakashreddy7277]

n=int(input ("enter no of values to enter "))
inputs = [input() for i in range(n)]
print(inputs)

[@Notyouranalyst]

hey bro could you help me with this video (from 1:36 - 2:30)
please bro help me out bro

[@tusharkantidebnath2316]

def countname(list):
count = 0
for i in list:
if len(i)>5:
count = count+1
print (count)
list= ["Ajay","Sanjana","Tushar","Anil","Ranjana"]
countname(list)

[@abhishek7882]

i love your assignments
def names(lst):
count=0
for i in lst:
if len(i)>=5:
count+=1
return count
a=0
lst = []
while(a

[@doserastalmi]

o=[]
def func(lst):
for i in lst:
if len(i)>5:
print(i)
z=int(input('How many names do you want?- '))
for i in range(z):
x=input('Name-')
o.append(x)
func(o)

[@doserastalmi]

Mine is more simple

[@skvytla]

Assignment Ans:
def func(count):
more5=0
less5=0
for i in count:
if len(i)>5:
more5+=1
else:
less5+=1
print(more5)
print(less5)
count=int(input("number of names:"))
lst=list()
i=0
while i

[@ashwinbicholiya6691]

1 -Take ten names from the user and then count and display the number of users
Who has length more then Five letters
n=int(input("Enter the numbers of Users : "))
lst=[]
for i in range(n):
lst.append(input('Enter the user name : '))
print(lst)
lst1=[]
c=0
for i in lst:
if len(i)> 5 :
lst1.append(i)
c+=1
print("no. of user whose name is > 5 is : ",c)
print(lst1)

[@vainayak30]

def count(lst):
counter=0
for i in lst:
length=len(i)
if length>4:
counter+=1
return counter
list=[]
c= int(input('Enter the number of names: '))
for i in range(c):
name=input('Enter a name: ')
list.append(name)
print(list)
ans=count(list)
print('Number of names with letter greater than 4 are: {}'.format(ans))

[@054_ritesh3]

Sir you had made me to fall in love with Python

[@astakalasuswith6946]

@Rithesh Jaiswal absolutely bro❤️

[@abhinaylakhera2273]

no need to use function
lst=[]
for i in range(5):
x=input("enter name:")
lst.append(x)
i=0
while i=5:
print(lst[i])
i+=1

[@mrlokeshkumar76]

answer to your assignment question sir- i was having some problems while taking input from user so I defined a list of names myself-
names = ['arushi','shorya','lokesh','yash']
def count(names):
words = 0
for i in names:
if len(i)>5:
words+=1
else:
pass
print(words)
count(names)
output- 3

[@divyanshupandey8150]

you didn't have to write else

[@vishugusain5232]

your code is giving an error

[@akashkumarsagar1423]

// try this
x=int(input())
c=0;
lst = []
for i in range(x):
y=str(input())
lst.append(y)
for i in lst:
if(len(i)>5):
c+=1
print(c)

[@meerajadhikari1877]

Printing the names as per the user input
user_input = input("Enter the list numbers or elements separated by space: ")
userList = user_input.split()
print("user list is ", userList)
for i in userList:
length = len(i)
if(length > 5):
print("Congrats, the name ",
"is ", length, "characters long.")
else:
print("Sorry man!! You need to rename yourself with at least six characters..")
Hope it helps somebody...

[@sourabhchoudhary7289]

It did❤️

[@kingsleyihemere6121]

Here is my code and I am loving is. Thank you sir
newName = []
def checkName():
name = input('Please give us your name ')
if len(name) > 5:
print('Here is your name, it is greater than 5, please choose another name')
newName.append(name)
print(newName)
else:
print('Bavo! your name is accepted')
checkName()

[@sohomdas8693]

def even_odd(*args):
lst = []
count = 0
for i in args:
if len(i) > 5:
lst.append(i)
count += 1
else:
pass
return count, lst
args = list(map(str, input().split(" ")))
count, lst = even_odd(*args)
print("This is the desired names: {} , and the total number is: {}".format(lst, count))
[Thanks Sir]

[@hardikjambhule3952]

assignment:
def list(x):
count=0
for i in x:
if len(i)>5:
count+=1
return count
lst=[]
n=int(input('enter nu of elements you want in list:'))
for i in range(n):
ele=(input('enter:'))
lst.append(ele)
print('list:',lst)
count=list(lst)
print('peoples who has name length greater then 5:{}'.format(count))

[@011gaurav]

def countletters(lst):
count = 0
for i in lst:
if len(i) > 5:
count+=1
return count
lst1 = ['Gaurav', 'Naveen', 'Raddy', 'Kalpesh', 'Mumbai']
count = countletters(lst1)
print("Name count - {} which is having more than 5 char ".format(count))

[@sahilsurve5361]

Assignment:
def names(lst):
Names_More_than_5=[]
for i in range(x):
if len(lst[i])>5:
Names_More_than_5.append(lst[i])
print('Number of names having length more than 5 are: ',len(Names_More_than_5))
print(Names_More_than_5)
lst=[]
x= int(input('enter the count of names: '))
for i in range(x):
name=input('enter the name: ')
lst.append(name)
names(lst)
(Kindly Let me know if its wrong)
Thank you to Telusko

[@riteshsarode8120]

Assignement:
l1=[]
n=int(input('enter number of names'))
for i in range(n):
name=input('enter names')
l1.append(name)
more=0
less=0
for i in l1:
if len(i)

[@HEMANTHKUMAR-ir5hc]

n=int(input("Please enter how many time user enter string:"))
j=0
d=[]
while j 5:
d.append(j)

print("List of 5 greater than letters is ",d ,"user")

[@Rajadahana]

If we add a float to the list, it doesn't give you an error, you can run the code.
if the decimal value is 0 eg - 2.0 or 3.0 it will run the operation and count either as an even or odd number.
But if the decimal value is not 0 eg - 2.1 or 2.2 it will count as an odd number.
You can copy the following code, do the changes to the list "lst1" and see it for yourself.
def count(lst):
even = 0
odd = 0
for i in lst:
if i %2 == 0:
even += 1
else:
odd += 1
return even, odd
lst1 = [1, 2, 2.1, 2.0, 2.2]
even, odd = count(lst1)

[@BhuveshDhiman]

def check(list):
for j in list:
if len(j)>5:
print(j)
list=[]
n=int(input("How many names you want ot enter?"))
for i in range(n):
list.append(input("Enter a name."))
check(list)

[@chandraroy8254]

Assignment Ans:
def user(names):
for name in names:
if len(name)>5:
print(name)
else:
continue
return name
names = ["Roy","meghana", "ram", "sruthi", "daivik", "valli", "srinidhi", "ramu", "swetha", "chandra"]
user(names)
Thank you ):
Navin's teaching rocks - Python shocks ):

[@narangparth]

Assignment:
name=[]
def enter():
for i in range(5):
x = input("Enter a name: ")
name.append(x)
return name
def check(name):
x = 0
for i in range(5):
if len(name[i]) > 5:
x += 1
return x
name = enter()
print(name)
a = check(name)
print(a)

[@joyekka1382]

def count(lst):
for i in lst:
if len(i)>5:
print(i,' has more than five letters');
else:
print(i,' does not have more than 5 letters');
lst=[];
l=int(input('enter the length of list of names
'));
for k in range(l):
naam=str(input('enter the names
'));
lst.append(naam);
count(lst);

[@saadahnaf208]

def count(name):
a = 0
b = 0
for i in name:
for j in range(len(i)):
if j>5:
a = a+1
break
else:
b=b+1
return a,b
x = int(input('how many names'))
name = []
for i in range(x):
y = input('enter the name ')
name.append(y)
z,m = count(name)
print('names given by user',name)
print("number of names more then five character : {} and less then five character {}".format(z,m))

[@vishnuvirat5821]

n = int(input("enter the length of the list"))
lst = []
for i in range(0,n):
k = input("enter the values")
lst.append(k)
print(lst)
def countlength(a):
count = 0
for j in a:
if (len(j)>5):
count = count + 1
else:
print()
return count
count = countlength(lst)
print("no of users with more than length 5:",count)

[@hariomchaudhary7194]

thanks a ton ! @Navin Reddy for making this beginner friendly python bootcamp. it is the best python bootcamp on the youtube

[@FactsDiscoveryyoutube]

#take input from the user in empty list as a integer and calculate it.
def count(lst):
even=0
odd =0
for i in lst:
if i%2==0:
even+=1
else:
odd+=1
return even,odd

list =[]
x = int(input("Number of indux in a list?"))
for j in range(x):
x= int(input("Gives the input please!"))
list.append(x)
even, odd = count(list)
print(even)
print(odd)

[@golshanswonderland8906]

Assignment:
def count(name):
k = 0
for i in name:
if len(i)>=5:
k=k+1
return k
roster=[]
for j in range(10):
a=input('write a name')
roster.append(a)
print(roster)
longName=count(roster)
print(longName)

[@chandsujoy]

Thanks @Harsh Vora for your post was able to create out of it
arr =[] # to create a blank array
n = int(input("enter element count for array"))
for i in range(n) :
x = str (input("Enter next name : "))
arr.append((x))
print(arr)
def count(arr):
counter_more_5 = 0
counter_less_5 = 0
for i in range (len(arr)) :
if len(arr[i])>5 :
counter_more_5=counter_more_5+1
else:
counter_less_5=counter_less_5+1
return counter_more_5,counter_less_5
even,odd =count(arr)
print("counter_more_5 : ", str (even) + " Counter_less_5 : " ,str (odd))

[@jugalvaidya9476]

Easy solution to this:
def people(list):
list=[]
x=int(input("How many people ?"))
for i in range(x):
list.append(input("enter the names"))
for i in list:
if len(i)>5:
print(i)
people(list)

[@pricepleasebd6873]

lst = []
n= int(input("enter the length of the list"))
print("enter the names one by one")
for i in range(n):
lst.append(input())
print(lst)
def count(lst):
lol=0
for i in lst:
if len(i)>=5:
lol+=1
print("num of the names containing more than or equal 5 letter: ",lol)
count(lst)

[@kuldeepnareliya4841]

def count(lst):
n = 0
for i in lst:
if len(i) > 5:
n+=1
return n
lst = []
x = int (input (" enter the no names "))
for a in range (x):
b= input(print("enter the next name"))
lst.append(b)
n = count(lst)
print(n)

[@VijayAdhithyaramasamy]

def count(lst):
lst1=[]
for i in lst:
if len(i)

[@sumansaurabh2669]

n = int(input("enter the size of list"))
list = []
for i in range(n):
val = input()
list.append(val)
c = 0
for e in list:
if len(e) > 5:
c+=1
else:
pass
print(c)

[@abhishekshukla6466]

from numpy import*
arr = list()
count = 0
n = int(input("enter the length of the array"))
for i in range(n):
x = input("enter a string ")
arr.append(x)
print(arr)
for j in arr:
if len(j)>5:
count+=1
else:
pass
print(count)

[@shreshtkapoor97]

Taking no.of names also as user input and then printing it:
def name(lng):
for i in range(len(lng)):
if(len(lng[i])

[@sagarr1640]

def count(lst):
for i in lst:
if (i.count('')-1)>5:
print('names with Letters>5 is',i)
lst=[]
for e in range(10):
x=input('Enter the names:{}'.format(e))
lst.append(x)
print(lst)
count(lst)

[@rajneeshpatel5028]

names = []
# Taking Input from user
while True :
name = input('Enter a name : ')
names.append(name)
option = input("Do you want to add next name Yes|No")
if option.lower() == 'no' :
break
def checkLenGreaterThan5(names):
len_names = 0
name = []
for x in names:
if len(x) > 5 :
len_names += 1
name.append(x)
return len_names , name
a , b = checkLenGreaterThan5(names)
print('The Number of names greater than length 5 are ' , a , '
The names are ' , *b , sep = ',')

[@binaygupta478]

Brother y r u using *b plz explain

[@karangupta5401]

def count(length):
counting=0
for x in (length):
if len(x)>5:
counting+=1
return counting
user_input=input("please enter a names using space")
names_as_strings= user_input.split( )
length= [str for str in names_as_strings]
counting= count(length)
print("counting:)
print(length)

[@dhayanandshanmugam7183]

l=[]
n=int(input("Enter the length:"))
for i in range(n):
y=input("Enter:")
l.append(y)
for i in l:
k=0
for j in i:
k+=1
if k>5:
print(i)
else:
pass
Code for the assignment Qn

[@liya6313]

Def names(list)
For i in list:
If len(i)>=5
Print(i)
List[ ]
For i in range(10)
X=input(‘enter the nxt value’)
List.append(x)
Names(list)

[@karthikeyan-gy8tn]

def list(lst):
For i in lst:
For j in range(len(i)):
If j>=5:
Print(i)
lst =["any names"]
list(lst)

[@sumanthchatra8242]

Assignment:
lst =[]
for j in range(4):
nm=input("enter the name")
lst.append(nm)
def play(lst):
for i in lst:
if len (i) > 5:
print(i)
play(lst)

[@karthibalaji3817]

Assignment from an alien :
print("----This program is about getting 10 names from the users and enumerate & display the names which are all exceeding more than 5 letters----")
names=[]
print("Enter the names below")
for i in range(11):
names.append(input("Enter the name:"))
print(len(names),"names added to the list names")
print(names)
def count(names):
for i in names:
if len(i) < 5:
continue
else:
print(i)

count(names)

[@pimppakoda1153]

def counter(arr):
cnt = 0
for j in arr:
if len(j)>5:
print("name : {} and length : {}".format(j,len(j)))
cnt+=1
arr = []
no = int(input('please enter the number of names you want in a list'))
for i in range(no):
x=input('please enter a name')
arr.append(x)
print(arr)
name = counter(arr)

[@adarshprasad4666]

lst = []
num = int(input("How many numbers you need in a list? "))
for i in range(num):
x = int(input("Enter number: "))
lst.append(x)
def count(lst):
even = 0
odd = 0
for f in lst:
if f % 2 == 0:
even += 1
else:
odd += 1
return even, odd
even, odd = count(lst)
print("Even numbers count:", even)
print("Odd numbers count:", odd)

[@abhisekdas4770]

def names(lst):
count = 0
for i in lst:
for j in i:
count += 1
if count > 5:
print(i)
count = 0
lst = list()
n = int(input('Enter no.of persons: '))
for i in range(n):
lst.append(input('Enter names: '))
print(names(lst))

[@arjyabasu1311]

print("Enter 10 names")
list=[]
for i in range(0,10):
ele=input()
list.append(ele)
def display(list):
for i in list:
if len(i)>4:
print(i)
display(list)

[@monausavlogs9796]

def count(Names):
for i in Names:
if (len(i)>10):
print(i)
Names= str(input("Enter names"))
string_names= Names.split(",")
count(string_names)

[@prapullachandrakoganti9811]

x=int(input("enter the size of list"))
A=[]
for i in range(x):
u=int(input("enter the list elements"))
A.append(u)
print(A)
def evenorodd(A):
for e in A:
if(e%2==0):
print("{} is even".format(e))
else:
print("{} is odd".format(e))

evenorodd(A)

[@wicked87manu]

def inputuser():
for i in range(number):
name = input("Enter the names")
lst.append(name)
def callength(lst):
for i in range(len(lst)):
if len(lst[i]) > 5:
print(lst[i])
number = int(input("Enter the number of person you want to add to the list"))
lst = []
inputuser()
callength(lst

[@ThoRBaaP]

def name_length(list_of_name):
for i in list_of_name:
if len(i) >= 5:
print(i)
list_of_name = []
list_of_name_length = int(input("Please enter length of your list: "))
for i in range(list_of_name_length):
x = str(input("Enter a name: "))
list_of_name.append(x)
print(list_of_name)
name_length(list_of_name)

[@MGA0295]

def namecount(*a):
for i in a:
if len(i)>5:
print(i)
namecount('arg1','arg2',.......)
or or or or or or
def namecount():
names=[]
a=int(input('enter how many names u want to give'))
for i in range(a):
x=input('enter the next name:')
names.append(x)
for j in names:
if len(j)>5:
print(j)
namecount()