When the example in the beginning of Linear Algebra changes, some earlier mistake persists, and instead of showing [1*5 + 2*6] = [17], it shows [1*2 + 5*6] = [32]
I am deeply confused. In the final decryption formula. How do i use the k-1 and the C together? Is it the same as in the begging? As in when i am decrypting do i do 15x17 plus 7 x 8 when decrypting like when you encrypt Or do i do something else with the numbers? Also how does 3 3 2 5 work? It shares a divisor of 3 with 26 so it cant work.
In these simple cases when we have small numbers you can think of it like this, 9 * something = 1 (mod 26), if you try out different values for "something" you get: 9 * 3 = 27 = 1 (mod 26). That's how in this specific example, for the general case I suggest you learn about The Extended Euclidean Algorithm. There are other great videos on RUclips to learn that! Hope that helps
there are a lot of mistakes within this video that causes unneeded confusion, I recommend proof hearing your videos in the future as I was rewinding many times as you say numbers equals a completely different number, for example you say that inverted k becomes 3, -3 etc but you call "2", '-3' which makes me think there are now two -3's.
When the example in the beginning of Linear Algebra changes, some earlier mistake persists, and instead of showing [1*5 + 2*6] = [17], it shows [1*2 + 5*6] = [32]
Yeah that was an odd mistake, I showed it correctly then I guess I mistakenly wrote 5 instead of the 2. Thanks for catching that mistake
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@Kylen Cannon yup, I have been watching on Flixzone} for since december myself =)
@Kylen Cannon Definitely, I've been using flixzone} for since december myself =)
@@kylencannon1524 Sorry I dont have a GF
I am deeply confused.
In the final decryption formula. How do i use the k-1 and the C together?
Is it the same as in the begging?
As in when i am decrypting do i do 15x17 plus 7 x 8 when decrypting like when you encrypt
Or do i do something else with the numbers?
Also how does 3 3 2 5 work? It shares a divisor of 3 with 26 so it cant work.
Great video, I finally understood the concept :)
In 9:41 I don't get how the mod obly changes 2 of the numbers
Great explanation! Keep up the good work
Tack så mycket! Du räddade tentan
sir here u have divided text to n*1 matrix..but some of the channels used 1*n matrix which is correct ?
i can’t get it how 9^-1 modulo 26 is 3
In these simple cases when we have small numbers you can think of it like this, 9 * something = 1 (mod 26), if you try out different values for "something" you get: 9 * 3 = 27 = 1 (mod 26). That's how in this specific example, for the general case I suggest you learn about The Extended Euclidean Algorithm. There are other great videos on RUclips to learn that! Hope that helps
Mubeth Praditya mantep le sinau beth, warai aku :)
why is k 9?
why mod (26)
26 letters in alphabet
7:35 google search says "do you mean Hill cipher is complicated"
thank you very much
Happy to help!
there are a lot of mistakes within this video that causes unneeded confusion, I recommend proof hearing your videos in the future as I was rewinding many times as you say numbers equals a completely different number, for example you say that inverted k becomes 3, -3 etc but you call "2", '-3' which makes me think there are now two -3's.