Mam but in the book, its mentioned that the formula of (equivalent of CaCO3) is = (Amount of hardness producing salt x Molecular weight of CaCO3)/ Molecular weight of hardness producing salt . And not equivalent weight
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Mam At 7:10
Equivalent weight of mgcl2 might be
10*50/47.5 = 10.5263 mg/litre
Is this correct??
Btw awesome explanation...
Yes it should be 47.5
I have written 55.5 by mistake.
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Maam mgcl2 equivalent weight is 47.5
Yes
Yes
Thanks a lot mam
Most welcome 😊
Mam notes available hai kya..😊
Mam but in the book, its mentioned that the formula of (equivalent of CaCO3) is = (Amount of hardness producing salt x Molecular weight of CaCO3)/ Molecular weight of hardness producing salt .
And not equivalent weight
Instead of using molecular weight you are telling us to use equivalent weight
Yes because molecule weight is not applicable for all salts and ions.
Is eq. wt. of MgCl2 is correct?
So sorry! It should be 47.5.
55.5 is the equivalent weight of CaCl2.
Yes mam
Thankyou Mam 🙏
Most welcome 🙂
😊 wonderful
Mam mgcl2 ka 59.5 hota h 55.5 bss suggestions tha mam mera or koi mean nhi tha
should be 47.5
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Mam ya btech 1 st year vala bachoo ka liya bhi hai na
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Nice explanation mam
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great teaching mam
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Mam please upload lectures on Fuels for applied chemistry
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kash maine pahale ap ki video dekha hota MAM
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Mam please explain corrosion chapter
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@dr.nishasingh mam I am in btech 1st year from MDU university so I want to share my syllabus with you so aapki koi telegram ya Instagram I'd hai mam jha me aapko syllabus ki pic send kardu because maine bhout saare teachers search Kiya hai youtube pe but mujhe aapka samaj aarha hai so please help me.
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