#3.[IN HINDI]LAW OF GEARING |KOM||TOM|

[@alamkhan37379]

After watching many... Finally this video is helpful.. Great explanation 👍

[@easylearning6684]

Glad to hear that

[@nitish2018]

Finally I got it.... thank you very much for helping... that's why I love internet and RUclips...👍👍

[@salimbhai1143]

Sir only one word...I don't know who u r . But u r such a amazing guy...!!! Your way of teaching is Awesome...!!! I learning this derivation since 6 months but you teach me simply One night before the exam....Thank u sir...Love from Karnataka..

[@easylearning6684]

Thanks... keep supporting.:)

[@sudarshankadam805]

nice

[@neutronn4058]

Sir i think 1st draw commen tangent and then after draw normal which is perpendicular to comman tangent which is must always passes through pitch point of two gear because without comman tangent , normal can not possible and if you draw then which basis it's normal from which linw it's normal or perpendicular? Ans plz

[@rituk5256]

Great content! Shared it with my friends. Amazing Explanation for the entire playlist!

[@universalrefractoryandserv1591]

Bahut easy se smjh Aya mere dost .... Low of gearing

[@abhijitmall2291]

Sir ek daam ek baar me dek ke samaj me aa gaya thanks sir

[@amitanshushukla3704]

Probably the best video explanation of this topic

[@Kamal_sahu]

Bahut badiya bhai, acchi koshish kari..

[@praneethjayanthi9139]

Nice, explanation. Thanks for the videos, please upload more such content, we are waiting to see lot more of these.

[@tusharikatiwari4987]

U r so intelligent...tq u helped a lot in my exam...nicely explained 👍👍

[@jayeshahirrao3868]

Finally samjh aya 👍 you just saved my exam thank you sir ☺️

[@harshaldeore7468]

Great sir all doubts are clear now 😊

[@easylearning6684]

Great 👍

[@vishalvishwakarma6664]

Sir ... ..both acche se apne smjhaaya ..... .

[@prathameshkhapare8946]

😎😎😎😎really great and easy to learn bro 😎😎😎😎😎😎

[@drdjwalker9973]

I had forgotten how to derive this. Even thought I can't speak Hindi (?), your derivation reminded me. Thanks!

[@shloktrivedi125]

Excellent work!

[@rishikumarsingh5506]

The explanation provided is worth appreciating.. Better than many teacher's.. Hatts off mate

[@easylearning6684]

Thanks

[@shristisahu9087]

Thank you so much. Very well explained. ✨

[@akashdeep5088]

Bahaut hi accha explanation....

[@akashanand1329]

finally i got the video which explain this topic nicely

[@wildwolf7220]

great video bhai❤

[@kaustubhyawalekar4021]

Bohot acha Bharatiy bhasha me seekhna aasan ho jaata he !!

[@dhananjayvibhandik6455]

Thank sir ek no bataya😍

[@pritamkulkarni4688]

thanks for this video.....very nice , easy explanation

[@bijayakumarswain121]

Ur mobile no plz

[@manjeetkhare7124]

awesome work.
please provide other topics too.
like one after another topic.
such as involute and cycloidal teeth profile after this video.

[@easylearning6684]

+Manjeet OK...sure

[@zeeshanahmed9719]

Bahut zabardast Thank you.

[@maulik61196]

Bahot khub...👌

[@hiiirenpatel4906]

Totally understand..bro..!

[@sagar_617-u8b]

Bhaii, Thanks 👍🔥

[@mirajjadhav8399]

how can you draw normal to a point.as far as i know you gotta draw a tangent through the point of contact first and then normal to the tangent

[@megirl2883]

Yes .....I had the same question....kuchvi samajha raha hai banda

[@Allinoneshort78]

Nice bro..Thnx a lot..

[@RahulKumar-mt3dy]

Thank you sir kal exam h apne achhe se samjha diya

[@omkarbaile3472]

Very great explained

[@RajeshKumar-iy5pd]

Good video sir, I need a video related calculate gear module according gear tangential force

[@RahulThakur-bb8db]

Superb 👍

[@vivekyadav-ku8it]

Thanks u...sir..👌👌👍

[@nahidnahid68]

Simply amazing

[@easylearning6684]

+nahid nahid
Thanks

[@nitishtodkar4374]

Hi,
Could you please make one video on below part ?
compound planetary for different different arrangement and how we can find their respective gear ratio ?

[@vedantpratik9352]

Bahut hi mast bhaiya

[@easylearning6684]

Thanks bhai.
Keep supporting :)

[@rishabhsen1304]

thank you sir👍...✍️

[@bholeshvarprasad3702]

Nice explanation 👍

[@abhinavsharma9342]

gd job sir....

[@vijendrasahu2048]

बहुत बहुत धन्यवाद आपका

[@thankyou2770]

sir ap Jo bhi video banate hai kisi topic se related. to video ke last me usse related questions bhi Jo exam me aate hai ko bhi bataye

[@easylearning6684]

Thanks for suggesting:)

[@gourav.singh_407]

at the point of contact we draw a normal .at this point we draw two different velocity how it is possible?? as we know that at one point two velocity at different direction is impossible

[@manojkumargupta8903]

Yeah right,how is it possible?

[@dashrathmeena3247]

Whick book do u refer
And very much thanks for helping

[@easylearning6684]

+Dashrath Meena
I have two books rs khurmi and VB bhandari.
Thanks for watching

[@easylearning6684]

+EASY LEARNING
And also some other local books which are normally students use.

[@easylearning6684]

+Dashrath Meena
Bro is video ko share karna taki dusre logo ki bhi help ho

[@vijendrakankheriya]

SS ratan kesi rhegi

[@jaysolanki6535]

suppp awesome sir , plz add sir new video of gear example

[@easylearning6684]

+Jay Solanki
Thanks,
Sure examples ke bhi video aaenge

[@easylearning6684]

+Jay Solanki
Your video is ready watch it
And don't forget to comment.

[@sparshsadhu9658]

Great

[@easylearning6684]

+SPARSH SADHU THANKS

[@JatinKumar-sb6ds]

O2NP and O1MP, how are they both similar?
there is only 1 same angle which is 90.

[@vishveshsharma564]

Thanks bro!

[@ajitdake1328]

Very nice

[@rishavmishra7478]

👍

[@hathivats]

You should reduce amount of ads

[@rohitdubey6845]

Very nc job...But their is a mistake in the diagram section As u have explained M but it is written as N....N that is Class 10th concept I.e,Similar Triangles 😊

[@ashishdayanand9578]

Nice

[@nnymps3313]

MastBhai

[@praveenmunagapaka2888]

Nice bro

[@ShobhaDevi-er8ii]

nice video #easylearningpoint

[@easylearning6684]

Thanks

[@aasifahanger3583]

Thanku sir....

[@azamkhan1526]

👌👌👌👌👌

[@anujsaini5257]

Thanks sir very nice teach

[@easylearning6684]

+ANUJ SAINI
Thanks

[@sandeepmaurya2703]

Thakns a lot of sir

[@krushnachaugule1584]

2 ghante me exam hai
Wish me luck
Second try hai

[@ketanthakur8966]

Main thing is 2 ghnte phle aake dekh rha hai bhai tu video 😂

[@surajkuttarmare1027]

thank u vry muc sirjiiiiii

[@parthghaydar5403]

Thank you sir🙏

[@easylearning6684]

You're welcome 👍

[@thankyou2770]

best

[@bhuneshwar2547]

Tell me cos(alpha) where that come from ?

[@nikhilpanchal8914]

As u know the velocity has two components vertical and horizontal. Here to calculate the velocity in horizontal direction it's horizontal component cos@ is used.

[@sailorbout2sail718]

@@nikhilpanchal8914 Thanks. It helped me actually.

[@RaviKumar-xx7ds]

Coriolis acceleration topic make it sir

[@shantanukhan5218]

Ravi Kumar sir nice video it was helpful

[@princetiwari3841]

Thanks sir

[@prashantnonia9692]

Mast

[@GaneshGanesh-yg2vr]

Super

[@VirajLatke]

Sir aaj mera exam hai aur hmare university me 1Q. 6marks ka hota hai aur agr aaj ye Q. 6marks keliye aya aur me likh paya to uska credit sirf apko jyega ...thanks 😊🙏

[@easylearning6684]

Exam kaisa hua?

[@VirajLatke]

Accha gya pr badluck law of gearing nhi pda 😑

[@ashutoshsuthar3753]

Nyc

[@onkarpawar1]

thanks bro

[@Nav_Kmr]

Thnkx sir

[@neelamdhalwal2724]

Cos to base upon hypotenious hota h na to ap perpendicular upon hypotenious ku lere ho smj ni aaya

[@easylearning6684]

Time batao...to me check karu

[@2ndlife320]

angle ke samne wali side perpendicular hoti he, so he have done correct

[@nirajsah3017]

Thanks you so mach sir

[@easylearning6684]

+niraj kumar
Thanks for comment

[@divakarpandey7990]

Yarr bhaiii M to kahi mentioned hi nii h aur puri lacture me M hi bta rkhe ho

[@easylearning6684]

2 minute pe dekho

[@yashshetty9409]

Tangent kaha hai?

[@amanwadte1495]

thanks

[@easylearning6684]

Aman Wadte
Thanks for watching

[@amitandhimani]

Annoying aads bro pura concentration kharab ho jata h , thoda kam add dala kro bhai..

[@easylearning6684]

Ok... Thanks

[@Mr_karan787]

Ye sahi hai na bhai law of gearing kal exam. Ye pura prepare hoo gaya hai par jab you tube ki help se notes banata hu or jab sir dekhte hai to kehte hai ye wrong or puchte hai kaha se likha or hum kehte hai RUclips se likha hai. Pure notes pe chokdi maar dete hai

[@easylearning6684]

Is video me maine kuchh bate bhi boli hai vo bhi likhani chahie....vest tarika hai video dekho and fir apke pas jo book usko padho sab samaj aa jaega

[@swarnimguptafact7382]

Sir plz ek what's app grup bna dijiye

[@rabkidua2267]

Tnx u sir

[@adityapandey0143]

achha smjh aaya but digram whi whi whi bta rhe ho to smjh nhi aa rha h

[@prakharthadian5150]

Add bhut zada plz inko htao it's disturbing

[@217sourabhpatil2]

How to assum V1=w1×o1k

[@322_samuel6]

Velocity at r distance from centre of a rotating body of w rpm is given by : V = wr

[@yahitajam7944]

Most boring Topic in Gear designing

[@suleemansuleeman7217]

Sir you should reply.

[@easylearning6684]

Ha bolie

[@vishal_015b]

bhai perpendicular to draw kr le thik se .....

[@Noname-jp8kb]

bhai tu padai kar le thik se🤣🤣

[@officialgamermz1961]

Ye gutkha kha ke na parao

[@abhi...4420]

…….

[@abhishekrathore9994]

Improve language

[@NiharParekh]

thank you sir

[@kushkhurana8275]

Thanks bro

[@physicsbyvikas9890]

Thanks sir

[@Sanjay_kumar_k_h]

Thanks

[@sachinkumaryadav7783]

thank u sir

[@indiantourist2790]

Thanks