At 17:00 protons should be Diastereotopic as the plane which I've shown in example will bisect the protons. Thanks Suvamoy Malik for making this correction
sir, how to decided when the protons are bisected by the plane and when the protons are reflected by the plane...... i have seen by videos from different youtube channels and couldn't find the answer
Sir in diastereomers for example in one molecule has two centres are there one is chiral another one is not chiral in this case is it diastereomers sir pls tell me
No sir, am talking about 5:10, after substitution of hydrogen by x, then also the carbon is not chiral, so how its mirror image could be its enantiomer ??
@@akb0014 in that example I'm just showing relationship between H1 and H2 for that were assuming that molecule will remain as it is, just by making substitution we are trying to see the change. So we don't have to worry about C-C single bond rotation.
Bcoz that carbon which is attached to two methyl group is achiral, on C2 rotation as we have methyl above and below both the groups so it doesn't make any difference.
Sir in 3rd example...m confused.bcz if we apply second plane except which u apply then proton will b reflect ...n become enantiotopic...how we decide it... either it they will b enantiotopic or diastereotopic..plz explain it
In 3rd example.....There is only one plane, which bisects Ha & Hb and reflect H & H where the methyl group is attached.... So H & H is Enantiotopic and Ha & Hb are Diasteriotopic
Bro you are wrong about the mirror image bro. The concept that you said is right but when you reflect a molecule the substituent above the plane will come above only even after reflection
At 17:00 protons should be Diastereotopic as the plane which I've shown in example will bisect the protons.
Thanks Suvamoy Malik for making this correction
It's really a nice video .....Could you make for pole notations such as AA TYPE AX type Nuclei with various example....thanks you for this video.....
Make videos on main group elements..
Axis and planes are sufficient to find topocity of compound.
Can we find out this with R S configuration?
Sir in example number 3, the protons Ha and Hb are bisected by the plane,so these should be diastereotopic!
Please reply sir
Wow that's so cool i was about to searching for this topic got notification thank u very much
TQ so much sir🙂
sir, how to decided when the protons are bisected by the plane and when the protons are reflected by the plane...... i have seen by videos from different youtube channels and couldn't find the answer
Full of concept....
Nice video sir
Very useful sir
Thank you very much sir
Thank you sir
Really useful vedio for csir net 🤘🤘🤘🤘🤘
Nice explanation sir
Sir in diastereomers for example in one molecule has two centres are there one is chiral another one is not chiral in this case is it diastereomers sir pls tell me
In the examples what is the difference between 1st one and the 3rd one
If both c2 and sigma present what we have to give priority?
Sir in 47 question why don't they are enantiotopic. On replacement of one H it can generate chiral centre.
But there is no plane of symmetry
The plane only bisect each other hydrogens
In the second example how can be the two molecules mirror image.. Cause the c-c single bond can rotate freely ??
If you're talking about cyclo propane ring molecule then that can not move as single bond forming the ring will not allow rotation
No sir, am talking about 5:10, after substitution of hydrogen by x, then also the carbon is not chiral, so how its mirror image could be its enantiomer ??
@@akb0014 in that example I'm just showing relationship between H1 and H2 for that were assuming that molecule will remain as it is, just by making substitution we are trying to see the change. So we don't have to worry about C-C single bond rotation.
Ok.. Sir thank uu
Sir make lecture on steriochemistry mainly on interconverrions
I'll try
Sir from where we have to pass an axis in a molecule
Sir 3 rd example of five member ring,Two proton would be diastereotopic relationship.
As plane is passing through the two proton, not the between two proton.
Thank you for the correction, yes it should be Diastereotopic
At 25:08 while rotating by C2 why don't you change the configuration of methyl grp ,sir.
Bcoz that carbon which is attached to two methyl group is achiral, on C2 rotation as we have methyl above and below both the groups so it doesn't make any difference.
Sir in 3rd example...m confused.bcz if we apply second plane except which u apply then proton will b reflect ...n become enantiotopic...how we decide it... either it they will b enantiotopic or diastereotopic..plz explain it
In 3rd example.....There is only one plane, which bisects Ha & Hb and reflect H & H where the methyl group is attached.... So H & H is Enantiotopic and Ha & Hb are Diasteriotopic
The third example (at 18.06 min.) should be diastereotopic bcs the hydrogens are not getting bisected but they contain the plane.
Yes that I've corrected in the pinned comment.
Thank you for pointing it out.
@@AllBoutChemistry Thank u so much..sir
sir can you explain the question 116 december 2014 booklet A
Sir make videos on Main Block elements..full concept of it..
Acknowledged
Thank u Sir
Sir Gate Expected cutoff for GM
Bro you are wrong about the mirror image bro. The concept that you said is right but when you reflect a molecule the substituent above the plane will come above only even after reflection
Not easy to understand
7:10 is not a chiral carbon.
నూరుల్ ఉండగా చింతెందుకు దండగ😅
Sir u looks r looking different. I think aapne hair cut krwa h😂😂
Yes 🤣🤣
@@AllBoutChemistry 👌🤗
😂😂😂
Poor explanation
If you can't appreciate, don't put negative comments!!!!
Thanks a lot sir
Thanks sir