906,150,257 and the Pólya conjecture (MegaFavNumbers)

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  • Опубликовано: 22 ноя 2024

Комментарии • 241

  • @LeoStaley
    @LeoStaley 4 года назад +363

    Didn't even know you had your own channel. You're one of my favorite numberphile contributors.

    • @Neescherful
      @Neescherful 4 года назад +6

      Same here!

    • @bemusedindian8571
      @bemusedindian8571 4 года назад +4

      Yes. I think the ‘Tree Gaps and the Orchard Problem’ by Sparks is the best video in the numberphile collection.

    • @HasekuraIsuna
      @HasekuraIsuna 4 года назад +7

      @@bemusedindian8571
      No way, I still haven't pieced together my brain since it was mindblown by Chaos Game!

    • @modernkennnern
      @modernkennnern 4 года назад +1

      I didn't know about it either. Looking at his channel he doesn't *really* have one either (There are only 3 videos):
      Of course, 3 videos is a lot better than the 0 I was aware of ^^

    • @iamdigory
      @iamdigory 4 года назад +2

      He's tied for first with at least half of them

  • @ivarangquist9184
    @ivarangquist9184 4 года назад +233

    My mind is completely blown. I mean, the concept is so pure and simple. Yet, the result looks completely random. Wow.

    • @powewq1748
      @powewq1748 4 года назад +1

      Smarten up then

    • @terdragontra8900
      @terdragontra8900 4 года назад +4

      This of one of the big reasons we mathematicians love what we do

    • @bitterlemonboy
      @bitterlemonboy 4 года назад +4

      It's like the mandelbrot set.. These patterns come from nowhere. They are literally built-in to logic and reality.

    • @darsdm
      @darsdm 4 года назад +1

      Markets behave in the same way

    • @ffggddss
      @ffggddss 4 года назад

      "... concept is so pure and simple. Yet, the result looks completely random."
      And the same is true of Pell's Equation solutions (one of my own favorite, pet math topics).
      Fred

  • @TheoH54
    @TheoH54 4 года назад +178

    conjecture: most of the numbers are small.

    • @jonathanjacobson7012
      @jonathanjacobson7012 4 года назад +3

      I could write a Python script to disprove it!

    • @tomc.5704
      @tomc.5704 4 года назад +17

      Counter conjecture: "Small" is a relative term best defined as "below average"; exactly half of the numbers are small.

    • @04LightningFan
      @04LightningFan 4 года назад +7

      @@tomc.5704 How do you halve infinity? I would define "Small" number to mean calculable. The number of calculable numbers are finite while "Large" numbers are incalculable and infinite. Conjecture: most of the numbers are large.

    • @benbooth2783
      @benbooth2783 4 года назад +3

      @@tomc.5704 You can't talk about a fraction of infinite because it isn't a number. Infinite is the size of a set with no end. The cardinality (cardinal numbers describe an amount of things) of an infinite set is a special number which is not in the set of the integers called aleph null. You can only think about density with infinite sets, how often you expect something to occur, not how many times it occurs.

    • @timbeaton5045
      @timbeaton5045 4 года назад +2

      @@04LightningFan What numbers? Integers? Rationals? reals?
      Wish i could remember what i read somewhere about throwing an ideal dart at the number line, and seeing what the probability would say about the number you hit. i.e. that the numbers that you would hit, that are transcendental, incomputable, etc and would occur with probability, one.
      Probably got these details completely wrong, but i'm sure someone could correct me on this. Something to do with measure theory, i guess???

  • @Grabahan
    @Grabahan 4 года назад +116

    It takes 0% of the numbers to get people’s hopes up, but also 0% to shoot them down.

    • @fossil98
      @fossil98 4 года назад

      @Calen Crawford 1/n approaches zero as n goes to infinity. Your second quotient I dont understand as 1 divided by any positive integer apart from 1 does not equal 1. Where do surreal numbers come in?

    • @petemagnuson7357
      @petemagnuson7357 4 года назад

      @@fossil98 1/infinity%, meaning almost 0%, so the confusing part of the comment roughly translates to:
      "... then 1 equals [almost 0]% of all whole integers."
      With the surreal numbers coming in to explain exactly what "almost 0" means, I think the surreals are basically what you get if you take the reals but add infinity and 1/infinity an numbers.

    • @fossil98
      @fossil98 4 года назад

      @@petemagnuson7357 Ah I see. Misread. Yeah the surreals include all reals, +ordinal infinitie & infinitesimals.

    • @lyrimetacurl0
      @lyrimetacurl0 4 года назад

      Any%

    • @AFastidiousCuber
      @AFastidiousCuber 4 года назад +1

      @Calen Crawford Firstly, infinity is not a number in the surreal number system. You're probably thinking of the extended real line, but in that system 1/infinity = 0. Secondly, there are many ways of making sense of infinity as a number and it's misleading to act like any one way is the "correct" one.

  • @alvkarthik2018
    @alvkarthik2018 4 года назад +77

    when i was in high school i used to think maths is for genius people only but this lockdown changed everything, because of people like you and other mathematicians who contribute to numberphile channel now i see maths as something which is logical and simple abstract ideas which can describe the world and sometimes it just blows my mind by these simple ideas and this video blew my mind....

    • @maynardtrendle820
      @maynardtrendle820 4 года назад +6

      I love hearing this sort of thing. Welcome to the fold!

    • @thebagofsalt
      @thebagofsalt 4 года назад +6

      Me too! Watching Numberphile made me realize I wanted to study math in university this year. There is so much more out there than high school shows us. Thank you Ben and everyone in the only mathematics community!

    • @benbooth2783
      @benbooth2783 4 года назад +14

      Because maths is generally taught very badly in schools imo. I nearly failed maths at school, yet went to university at 30 and got a masters in physics.
      My analogy is this: It's like being taught French, you learn the grammer and the rules of how to construct sentences except they don't tell you what any of the words mean.
      I remember being taught calculus. I asked the teacher what the point of it was and got sent out of class, because the teacher didn't understand well enough to explain it.

    • @alvkarthik2018
      @alvkarthik2018 4 года назад +3

      @@benbooth2783 that's so touching. Thank you for your inspiration.

    • @ffggddss
      @ffggddss 4 года назад

      @@benbooth2783 You were unfortunate then, not to get a truly enthusiastic teacher. That can make all the difference.
      Fred

  • @PapaFlammy69
    @PapaFlammy69 4 года назад +73

    Hey! :D

  • @bjornmu
    @bjornmu 4 года назад +10

    I think this was the best fav number of the series. Yes it's amazing that this simple conjecture first fails at such a large number, but it's also amazing that it was so much *smaller* than the estimate from the proof that such a number existed.

    • @alexpotts6520
      @alexpotts6520 4 года назад +3

      Well, it was really a proof that there was *a* region where the summatory Liouville function was positive, around 10^361. The proof never said it was the first region where this was true. (And yes, you might think you'd have to calculate the SLF one value at a time, so if you reached 10^361, you'd have to go past 906,150,257 first. But... analytic number theory is more complicated than that, in ways I don't understand.)
      It's similar to Graham's number. You know that's only an upper bound on the solution to a problem, not the actual answer, right? And the *lower* bound to that problem, as of 2020, is... 13.

    • @bjornmu
      @bjornmu 4 года назад +1

      @@alexpotts6520 Yes, like a first stab at the twin prime conjecture had a limit of 70,000,000 and I think it's now down to 6. I was also puzzled when i read about this, that *a* counter-example was found already in 1960. If that was found by just counting up, you would hit the *first* counter-example but that wasn't found until 1980.

    • @alexpotts6520
      @alexpotts6520 4 года назад +1

      @@bjornmu Like I said, analytic number theory is weird, there are a bunch of similar results of the "small numbers obey this pattern, but at some really big number it breaks" kind. A lot of these number-theoretical functions can be written as series with error terms like log(log(log(x))), etc, that only become relevant and make their effects visible when you're looking at truly gargantuan numbers.

  • @algorithminc.8850
    @algorithminc.8850 Год назад +3

    Enjoyed the video greatly. Thanks much. Subscribed. Cheers

  • @bhaskarbagchi1643
    @bhaskarbagchi1643 Год назад +1

    Because of a famous argument due to Littleeood, if Polya's conjecture was true ( at least for all sufficiently large numbers), then Riemann hypothesis would follow. Littlewood used his argument to disprove the conjecture that pi(x) is less than li(x).

  • @mattjackson4041
    @mattjackson4041 4 года назад +14

    Hi Ben! I met you outside a pub inside Bath and got a pic with you! Very much enjoyed this project (I think this is the one you told me about) and all these mega numbers 😁

  • @quantumleap7964
    @quantumleap7964 4 года назад +4

    You are literally the reason I understand the Mandelbrot set

  • @eliyasne9695
    @eliyasne9695 4 года назад +21

    3:20
    I just thought of an interesting proof of that:
    For each factor k of a number n exists a duel factor, n/k such that their product is n.
    As long as k ≠ n/k the number of factors must be even since we can pair up all the factors like so:
    (k,n/k).
    Therefore, if the number of factors is odd there must be a factor that doesn't pair up and doesn't satisfy
    k ≠ n/k.
    Which therefore means k = n/k and
    *k² = n*

    • @shambosaha9727
      @shambosaha9727 4 года назад +1

      Fantastic!

    • @ffggddss
      @ffggddss 4 года назад +1

      ... and so k is the only unpaired divisor, and thus makes the total divisor count odd. Nice!
      Fred

  • @gilmonat
    @gilmonat 4 года назад +5

    Out of the MegaFavNumber videos I watched this one is the best number!

  • @rosiefay7283
    @rosiefay7283 2 года назад +1

    5:19 Thanks for giving us this hint! I find the oscillation even more fascinating than the general bias towards numbers that are the product of an odd number of prime factors. (That bias can be explained by the density of primes).

  • @HonkeyKongLive
    @HonkeyKongLive 4 года назад +6

    I knew it was gonna be a mind bender. I knew it would involve some really unique property. I knew it would be fascinating.
    I did not know Matt Parker would stick the DJ horn sound effect in.

  • @WylliamJudd
    @WylliamJudd 4 года назад +2

    This is one of the best meganumbers so far.

  • @albertosierraalta3223
    @albertosierraalta3223 4 года назад +6

    You should upload more regularly. Your content is always great

  • @lazer613
    @lazer613 4 года назад +2

    Great explanation. I really enjoyed your presentation. Thank you!

  • @Endothermia
    @Endothermia 4 года назад +1

    Really nice video. Favourite bit was about the Strong Law of Small Numbers (and Matt Parker's air horns, of course!).

  • @publiconions6313
    @publiconions6313 2 года назад +1

    He nonchalantly says at the beginning that only square numbers have odd number of factors.... wait, what?!.. my mind blown just by that. Heh.. had to pause the video and take some time to digest just that little tid bit.

    • @SparksMaths
      @SparksMaths  2 года назад

      Ha. It is a nice number fact, and I was a little blown away the first time I realised it. :)
      For what it's worth - this vid makes use of the fact: ruclips.net/video/-UBDRX6bk-A/видео.html

  • @Aequorin628
    @Aequorin628 4 года назад +24

    How could there possibly be a proof for this! I can't even imagine where I would start for something that seems as random as this. I would be incredibly interested in a video on the proof (no matter how complicated it is)

    • @edomeindertsma6669
      @edomeindertsma6669 4 года назад

      Proof by contradiction maybe?

    • @anticorncob6
      @anticorncob6 4 года назад +7

      You can find order in these kinds of sets with observations. Let p(x) equal -1 when x has an odd number of prime factors and 1 when x has an even number of prime factors. You can observe that p(xy) = p(x)p(y). And we're here considering the sums of the p(x)s. Already you might feel like some factoring techniques might work, but they don't, but then you start to see that it isn't completely unapproachable.

  • @PopeGoliath
    @PopeGoliath 4 года назад +2

    I'd love to learn more about large first counterexamples. What other trends seem to go on forever, only to break an obscenely long time later?

    • @arnouth5260
      @arnouth5260 4 года назад +1

      Numberphile has a video on Merten’s conjecture, which has something similar

  • @521Undertaker
    @521Undertaker 4 года назад

    Every prime number has one prime factor, and early on there are a lot of primes. This is probably the driving force behind the function’s initial dive below zero. However, as the primes begin to thin out, so does their impact on the sum.

  • @OceanBagel
    @OceanBagel 4 года назад +2

    I wonder if the cumulative sum of that sequence would always be negative. It certainly seems that way.

  • @cezarcatalin1406
    @cezarcatalin1406 4 года назад +2

    TIME FOR PÓLYA CONJECTURE 2.0 :
    For most integers M up to an integer N (however big), most integers below M have an odd number of prime factors.

    • @skrimosinbaldur6055
      @skrimosinbaldur6055 4 года назад

      So you're basically saying the running sum of the sign of the shown function is always negative. It certainly feels like it but I wouldn't be surprised if it also turns out wrong

    • @georgebulyga6717
      @georgebulyga6717 4 года назад

      This is such a vague conjecture, why even bother with it ?

  • @Xnoob545
    @Xnoob545 2 года назад +1

    Ben: *mentions a number over 10^300*
    Ben: that a huge number
    Googologists: pathetic

  • @a52productions
    @a52productions 4 года назад +2

    Might there still be more numbers with an odd number of factors, just in a weaker sense? For example, the limit of the proportion might still slightly favor odd numbers of factors, even if it moves around a bit along the way.

    • @dekippiesip
      @dekippiesip 2 года назад

      I know it's a discrete graph, but you can look at the graph @9:16 and consider the area above and under the graph. Saying that that area approaches -infinity as the number approaches infinity would be a weaker version of this statement.
      Still not easy to prove, but I would bet that that would be a true statement.

  • @kirkanos771
    @kirkanos771 2 года назад

    So the next challenge would be to find the first number under which positives and negatives cancel each other, if it ever happen.
    This would mark a domain of well distributed odd and even numbers if picked up randomly.

  • @maxamedaxmedn6380
    @maxamedaxmedn6380 4 года назад +5

    Ok this looks like the chart
    I mean exatly the candlesticks you see when trading (long and short)

  • @KoheiMomose
    @KoheiMomose 4 года назад +8

    This conjecture reminded me of some talk on Numberphile, and it was Mertens conjecture.
    ruclips.net/video/uvMGZb0Suyc/видео.html
    They are so much alike!

    • @CheeseAlarm
      @CheeseAlarm 4 года назад +1

      That one ignored numbers with repeated prime factors didn't it? I wondered at the time what would happen if you included them. Well now I know. Kind of. I guess there's a third sequence that considers the number of distinct prime factors.

  • @04LightningFan
    @04LightningFan 4 года назад +1

    Thanks Ben. Similar to the numberphile video with Holly Krieger on Merten's conjecture. Now that I know you have a channel, I've subscribed and turned on notifications.

  • @detectivejonesw
    @detectivejonesw 4 года назад +3

    Surely 1 is the first exception as it has an even number of prime factors (0)?

    • @timbeaton5045
      @timbeaton5045 4 года назад +3

      Guess this would be filed under "Trivial Solutions"?

  • @tahmidt
    @tahmidt 16 часов назад

    Can we have a video of the technical proof that you briefly talked about?

  • @hurktang
    @hurktang 4 года назад +1

    I postulate that there is a prime number around 30'102 that for some odd reason should count as 2 factors on it own. And it's because we count it as only 1 that this conjecture fail.

  • @NozaOz
    @NozaOz 4 года назад +1

    I really like this one

  • @yash1152
    @yash1152 3 года назад

    [10:06 , 11:32] my most favourite part and what i wanted to read/hear on record

  • @curtiswfranks
    @curtiswfranks 4 года назад +2

    New fave.
    What is the area of that region/running area under the curve as the upper bound increases? It seems doubtful, but does the running area ever become positive?

  • @miradrgn
    @miradrgn 4 года назад

    so what i'm curious about is, what would it look like if you were to add up the area underneath the curve of that function up to any given point? that should give some kind of idea of... how much the value of that function tends to be negative or positive for all the previous numbers. and as far as I can tell for everything we've seen in this video up to the ~906 million mark, that area would be very decidedly negative even after you add in that little chunk sticking into the positives. if we graph out the area underneath that curve as its own line, will *that* line, that overall count of how even or odd the prime factors tend to be up to any given point, keep trending into the negatives forever, or will it eventually cross into the positives too?
    i have no idea if this question is at all meaningful or relevant to the conjecture or anything else, but it's just the first place my brain goes to and kinda fun to think about!

  • @TyYann
    @TyYann 4 года назад +21

    You made a typo in your description, you wrote "Most numbers have an odd number of prime numbers!" instead of "Most numbers have an odd number of prime factors!"

  • @Locut0s
    @Locut0s 4 года назад

    There is an interesting corollary in nature and cosmology to the strong law of small numbers, and this is in the isotropy of the universe which only becomes apparent when viewed across the largest of distance scales. Scales we have only been able to measure in recent decades. It is not necessarily obvious at all that the universe is extremely even in distribution. On scales even up to superclusters the universe looks very lumpy. But pan out far enough and we now know that the distribution of mater is astoundingly uniform.

  • @mueezadam8438
    @mueezadam8438 4 года назад +1

    Great choice of content and presentation as always Ben!

  • @vonmiekka
    @vonmiekka 4 года назад

    Excellent video, would love to see more videos by you on similar topics / crazy & unexpected math concepts! Keep it up!

  • @inverse_of_zero
    @inverse_of_zero 2 года назад

    Just subscribed! I've watched you for years on Numberphile, but found your other content to be a bit too long for me to be able to watch in one sitting. This lenght was perfect, more like this would be fabulous! :)

  • @yash1152
    @yash1152 2 года назад

    so far have read about:
    * 4 comments on marten's conjecture/constant
    * 4 comments asking for the python script (not counting my own comment regarding this)
    * 3 comments wondering about when the area will be equal to zero
    * 2 comments confusing "random" with evenly distributed
    ... wow, there are many recurring themes in this comment section

  • @Anomaly92
    @Anomaly92 3 года назад

    If Riemann Hypothesis holds, the Louville Function would even behave exactly like a simple random walk.

    • @rosiefay7283
      @rosiefay7283 2 года назад

      But this summatory function looked unlike a random walk. There are long intervals where upward steps are much more common than downward ones, to be followed by long intervals where the reverse happens.

    • @Anomaly92
      @Anomaly92 2 года назад +1

      @@rosiefay7283 Wrong, this is a classic example of human misconception of randomness. There is even a statistical test exploiting this ('run' test for randomness). Humans tend to think randomness is somehow connected to perfectly shuffled sequences but in reality randomness also leads to longer sequences in mostly just one direction. Just plot some brownian motions, sometimes they will explode in one direction, sometimes not.

  • @jeromejean-charles6163
    @jeromejean-charles6163 6 месяцев назад

    At 3:12 : "Conjecture: n is a square if and only if it has an odd number of factors" . It is true , not a conjecture ( 2 minutes on the back of an enveloppe). In fact we may say more : Theorem: n is a k'th power if and only if it has a number of factors congruent to one modulo(k). I am wrong ?

    • @swordfishxd-
      @swordfishxd- 5 месяцев назад

      77 has 4 factors: 1, 7, 11, and 77. 4 is congruent to 1 mod 3. But 77 is not a 3rd power.

  • @mrilinski
    @mrilinski 4 года назад

    Лучшее видео с MegaFavNumbers.

  • @theultimatereductionist7592
    @theultimatereductionist7592 4 года назад

    How to properly state conjectures in number theory:
    "Most numbers have between log(N) & log(N)+1 prime factors" is bullshit
    "For each positive integer, N, let A(N) = the number of integers, k, 1 1/2, then that is what we mean by "Most numbers, N, have between log(N) & log(N)+1 prime factors" ".

  • @bemusedindian8571
    @bemusedindian8571 4 года назад +1

    Exceptional.

  • @zetadroid
    @zetadroid 4 года назад

    Given any positive or negative bound, is it known is that function breaks it for some arbitrarily large value of n?

  • @pataplan
    @pataplan 4 года назад

    Downvote? Someone blatantly disagrees that MATT IS THE BEST

  • @tourajtayebi2189
    @tourajtayebi2189 2 года назад

    Significantly most of the time, most integers have an odd number of prime factors. Done!

  • @shaun__3
    @shaun__3 4 года назад +1

    Great video and thanks to youtube recommendations!

  • @rupesh5300
    @rupesh5300 4 года назад +1

    Another examples of stong law of small numbers where we see issue very very late is 111111111111111... 19 1s is a prime number even though after 11 we didn't have any. Are there more such examples??

    • @arnouth5260
      @arnouth5260 4 года назад +1

      23 ones, 317, 1031 and 49081 are prime. It is believed (but not confirmed) that 86453, 109297 and 270343 ones are also prime.

  • @mauYair
    @mauYair 4 года назад +1

    best MegaFavNumbers video I've seen!

  • @iwersonsch5131
    @iwersonsch5131 4 года назад

    What if we put the intuitive idea into a weaker conjecture? The Liouville sum doesn't _always_ stay nonpositive, but does it stay nonpositive _most of the time?_ What if we conjecture that most numbers have an odd number of prime factors... most of the time?

    • @rosiefay7283
      @rosiefay7283 2 года назад

      So you're interested in the Liouville sum's sum?

    • @iwersonsch5131
      @iwersonsch5131 2 года назад

      @@rosiefay7283 Pretty much

  • @7infernalphoenix
    @7infernalphoenix 4 года назад +5

    Best #MegaFavNumbers video for me yet :)

  • @looney1023
    @looney1023 4 года назад +1

    Does it cross 0 infinitely many times? Does there exist some mega(fav)number N such that for n>=N it's strictly positive or strictly negative?

  • @NoobLord98
    @NoobLord98 4 года назад +3

    Question, if it's proven that the Liouville Sum crosses the x-axis an even amount of times, would that then prove that Pólya's conjecture is true after all? Because if it crosses the x-axis an even amount of times it will be negative as x goes to infinity (we start by going negative after all).

  • @TheManInRoomFive
    @TheManInRoomFive 4 года назад +3

    Strong Russel Crowe in A beautiful Mind vibes in the opening shot! :D

  • @yuvrajsarda6660
    @yuvrajsarda6660 4 года назад

    Voila! A problem based on this came in the IMEO 2020 paper as Q3 if I remember correctly. There I wondered if this function L(n) ever was positive, and was absolutely convinced that it could never happen. Opened my eyes! I wish this video was made before I gave that test 🙃. Have a look at the AoPS threads for the same to check out that problem. It's pretty interesting.

  • @MasterHigure
    @MasterHigure 4 года назад +5

    This is my favourite too. Was thinking about making a video, but this is easier and probably better.

  • @JamesJoyce12
    @JamesJoyce12 4 года назад

    exp(10^120) billion years is clearly the best number - that is the Poincaré recurrence time for our universe - it is somewhat sad how few people have an idea how smart Poincaré was.

  • @jaimalsingh5750
    @jaimalsingh5750 10 месяцев назад

    Perfectly explained 🤝

  • @calingligore
    @calingligore 4 года назад +1

    Why is this function continuous? I mean it’s not because it’s not using real numbers. But its values don’t jump. Why?

  • @antivanti
    @antivanti 4 года назад

    Is it proven that there are an infinite number of possible n for which this function is larger than 0? Or could there possibly be a largest number for which it is larger than 0? If so you could still argue that "most numbers" is fulfilled as a criteria. That would also be closer to how I would interpret the initial formulation of the conjecture.

    • @SparksMaths
      @SparksMaths  4 года назад +1

      It's actually proven (despite what I say around 10:00) that it crosses between negative and positive infinitely many times. Haselgrove proved this in 1958 in fact. So, unfortunately, even a modified version of the conjecture is false. :(

  • @maynardtrendle820
    @maynardtrendle820 4 года назад +1

    A great video Ben. More forthcoming?

  • @Antediluvian137
    @Antediluvian137 4 года назад +1

    Wonderful video

  • @willk7184
    @willk7184 Год назад

    I'm curious if primes themselves are counted in the Liouville function, and if so would they always be considered to have 1 factor?

  • @LeeSmith-cf1vo
    @LeeSmith-cf1vo 4 года назад

    Does the ratio of the area above the axis and below the line vs the area below the axis and above the line have any significance?

  • @SvNVdOz
    @SvNVdOz 3 года назад +3

    Here from the Collatz Conjecture video by Veritasium.

    • @yash1152
      @yash1152 2 года назад

      > _"Here from the Collatz Conjecture video by Veritasium."_
      same

  • @davipab
    @davipab 4 года назад +6

    Is the code you used to make those graphs available anywhere?

    • @yash1152
      @yash1152 2 года назад

      yeah, i am wondering same

  • @yuvrajsarda6660
    @yuvrajsarda6660 4 года назад

    Any ideas on why this occurs? And I guess some hundreds of people have already created Python codes to see if this happens after more time...

  • @Someone-cr8cj
    @Someone-cr8cj 4 года назад

    great lighting!

  • @lucas29476
    @lucas29476 4 года назад +4

    Is this just because you can't really have 0 prime factors, so you have to start at 1 prime factor (i.e. the primes), and 1 is odd, so this biases the number of prime factors being odd?

    • @petros_adamopoulos
      @petros_adamopoulos 4 года назад

      I don't know if I'm right but my idea at the onset was to say : assuming the number of prime factors is perfectly random for all numbers, then it still has to be odd for all primes, and this creates a bias. The numbers that are even powers would pull the other way but they are less dense than the primes.

    • @lucas29476
      @lucas29476 4 года назад

      Petros Adamopoulos yea we are essentially expressing the same idea in different words

    • @rosiefay7283
      @rosiefay7283 2 года назад +1

      1 is the product of 0 primes.
      What you say explains the initial downward trend, but doesn't explain later intervals where upward steps predominate over downward steps.

  • @yash1152
    @yash1152 3 года назад

    5:19 " it's kind of
    got a self-similar fractally look to it
    there's
    some interesting consequences from that
    um go look up the riemann zeta function
    if i see a connection
    with the riemann hypothesis in this "
    6:20 " and as i mentioned before there is
    to do
    with the riemann zeta function and look
    up the connections on wikipedia or wolfram "

  • @EebstertheGreat
    @EebstertheGreat 4 года назад

    Asymptotically, do we know if "most" (≥0.5) numbers satisfy the conjecture? Do almost all?

  • @MAP233224
    @MAP233224 4 года назад +1

    Really really cool!

  • @sebastiandierks7919
    @sebastiandierks7919 4 года назад

    Even though the polya conjecture is wrong how it was originally stated, isn't it still weird that the liouville function looks that way? I mean if the number of prime factors was completely random, i.e. equally likely even or odd, the liouville function would most probably cross 0 much earlier.

    • @wingracer1614
      @wingracer1614 4 года назад

      random is not the same as evenly distributed and prime numbers are not evenly distributed.

  • @rotjeknor3073
    @rotjeknor3073 4 года назад +1

    Nice one

  • @rainerbuechse6923
    @rainerbuechse6923 4 года назад

    Thanks!

  • @klaasbil8459
    @klaasbil8459 4 года назад

    If the conjecture is about 'most', then if the sum of odd and even is zero, it is already disproven, isn't it? Doesn't have to cross the x-axis into the positive arena for that.

  • @whoeveriam0iam14222
    @whoeveriam0iam14222 4 года назад +7

    This also shows how mind boggling big a billion is
    Jeff bezos would have checked 200 times as far as you've done here. Just to see if it would have happened within his wealth

    • @RGC_animation
      @RGC_animation 3 года назад

      There is litteraly RUclips videos with more views than that number

  • @QUINTIX256
    @QUINTIX256 4 года назад

    Sampled at 48khz, 906,150,257 samples would represent roughly 30 minutes of audio. I wonder the Liouville function sounds like?

    • @yash1152
      @yash1152 2 года назад

      did you figure that out??

  • @AgentM124
    @AgentM124 4 года назад +1

    Checks the first Tree(3) numbers, they all work. then Tree(3)+1 doesn't work.

    • @pendrag2k
      @pendrag2k 4 года назад +1

      Yeah, and the crazy thing is, even Tree(3)+1 is basically zero compared to infinity.

  • @zax1998LU
    @zax1998LU 4 года назад

    Lot's of Tanaka's out there

  • @ChonGeeSan
    @ChonGeeSan 4 года назад

    So the conjecture can still be correct :)

  • @Восьмияче́йник
    @Восьмияче́йник 4 года назад

    Ok now let's find the smallest counter-example to Mertens conjecture !

    • @arnouth5260
      @arnouth5260 4 года назад

      We already have

    • @Восьмияче́йник
      @Восьмияче́йник 4 года назад

      @@arnouth5260 Nope

    • @arnouth5260
      @arnouth5260 4 года назад +1

      Восьмияче́йник sure, no explicit counterexample has been found, but we know for a fact it exists between 10^16 and 10^(7.91*10^39). Seeing how huge these are the exact number will probably not be found anytime soon.

    • @Восьмияче́йник
      @Восьмияче́йник 4 года назад

      @@arnouth5260 Yes but I asked for the smallest counter-example :D

  • @yuvrajsarda6660
    @yuvrajsarda6660 4 года назад

    You could very much reduce the amount of computation required by choosing say every 5th or 10th number, and selectively doing all computation for areas when it gets close to zero. I can think of other ways to reduce the amount too. You see, the trick here is to Compute Smart 😀

    • @yash1152
      @yash1152 2 года назад

      hey, can u share the scipt? or your version of it?

  • @Nebukanezzer
    @Nebukanezzer 4 года назад

    Commenting for those metrics!

  • @nivolord
    @nivolord 4 года назад

    Just to be annoying, wouldn't the first case be n=1? Since 1 has zero prime factors? I know it is a corner case, so it doesn't matter all that much. Unless you somehow argue 0 has and odd number of prime factors? :p

  • @marshill88
    @marshill88 3 года назад

    great video! Awesome

  • @OBGynKenobi
    @OBGynKenobi 4 года назад

    But "most" up to N is still vague. Is it 50%, or 66.78% etc...?

  • @MegaKotai
    @MegaKotai 4 года назад +2

    But doesn't the sequence start with positive 1? 1 has 0 prime factors, 0 is even so it would produce a 1, or am I wrong?

    • @ipudisciple
      @ipudisciple 4 года назад +1

      You’re right. I guess we have to start at 2 :)

  • @blimeyitsRichard
    @blimeyitsRichard 4 года назад

    @8:10 is the tanaka you mention any relation to hitomi tanaka?

  • @eldattackkrossa9886
    @eldattackkrossa9886 4 года назад +1

    matplotlib gang rise up

  • @SimonJackson13
    @SimonJackson13 4 года назад

    1000001, as it involves the least counting.

  • @windir88
    @windir88 4 года назад

    pronunciation captain here: the ly in Pólya is pronounced as the y in yes. And the o is long as in rose or in boat. Pow ya!

    • @gurrrn1102
      @gurrrn1102 4 года назад

      /ˈpoːjɒ/? I can’t remember if Hungarian has vowel reduction.

    • @windir88
      @windir88 4 года назад

      @@gurrrn1102 it's not vowel reduction, it's a digraph. basically there are letter combinations like ly which are denoting a specific sound. your phonetics seems right :)

    • @gurrrn1102
      @gurrrn1102 4 года назад

      @@windir88 vowel reduction is phonetic. I'm referring to the unstressed a at the end of the name.

  • @rosiefay7283
    @rosiefay7283 2 года назад

    0:53 You have misstated it. But you're in good company, as Wikipedia has misstated it, too. It's not "have an odd number of prime factors", it's "are the product of an odd number of primes". But thanks for going on to explain the correct idea.

    • @SparksMaths
      @SparksMaths  2 года назад

      Well, yes. The statements are equivalent if you count the repeated prime factors. But your statement is perhaps neater at capturing what we need to count. I liked the reference to the prime *factors* though as an intrinsic property of the number.

  • @SquirrelASMR
    @SquirrelASMR 2 года назад +1

    Ben u r cool I love ur talks (edit: and sings haha)