[[Year One 問數]]Advance Maths Q20241003|| q2|| Limit|| Delta Epsilon|| Convergence
HTML-код
- Опубликовано: 22 окт 2024
- [[Year One 問數]]Advance Maths Q20241003|| q2|| Limit|| Delta Epsilon|| Convergence
Facebook account & link :
Dr.K.Liu Maths-Erudition Education 博學習坊
/ eruditioneducation
Instagram account & link :
drkliu_math
![[[Year One 問數]]Advance Maths Q20241003|| q1|| Sequence|| Increasing|| Bounded Above|| Convergence](http://i.ytimg.com/vi/ku9aHfp3-CA/mqdefault.jpg)
![[[Year One 問數]]Advance Maths Q20241003|| q1|| Sequence|| Increasing|| Bounded Above|| Convergence](/img/tr.png)
![[[Year One 問數]]Advance Maths Q20241002|| q1|| Limit|| Exponential Function](http://i.ytimg.com/vi/k1vigxUDWG0/mqdefault.jpg)
![[[Year One 問數]]Advance Maths Q20241007|| q1|| Cauchy Sequence|| Delta Epsilon|| Convergence](http://i.ytimg.com/vi/lJ36S2rEZsU/mqdefault.jpg)
![[[Year One 問數]]Advance Maths Q20241011|| q5|| Inverse Function|| Injective|| Surjective|| Bijective](/img/1.gif)
歡迎各位同學, 老師, 家長發表有意義的意見, 多多討論!!!
I think it is necessary to show n^5.4
n^5.4=9
@DrKLiuMaths really? I use calculator, it shows that when n=9, n^5.4 still larger then n(n-1).....(n-5)
@@rayraychen6925 n >= 13 is right
@@rayraychen6925 anyway, in calculating this question, my mind is trivial that n^5.4
@@DrKLiuMaths I think that maybe I can choose the N=max{1/E+6,13} 🤔