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  • Опубликовано: 5 янв 2025

Комментарии • 5

  • @IG-ln7zt
    @IG-ln7zt 3 года назад

    Yes, it is a good number, I suppose. I like the primorials.

  • @MGmirkin
    @MGmirkin 3 года назад

    Meh, I feel like 30030 ("30 oh 30"; AKA, "2x3x5x7x11x13") is better, but, that's just me... :P ;)
    Though 510,510 is honestly pretty cool too... 'Cause it's literally "510 ... 510." (AKA, "2x3x5x7x11x13x17")
    "30 oh 30" and "510 ... 510" are just pretty nice to say.

    • @MGmirkin
      @MGmirkin 3 года назад

      Likewise:
      Primorial [3,408,696]
      If only because it is the Primorial sieve domain size into which the current largest prime number [24, 862, 048 digits long] falls.
      Primorial [3,408,695] yields a number that is 24,862,045 digits long, whereas Primorial [3,408,696] yields a number that is 24,862,053 digits long. So, the current longest prime number's length falls between the end of the Primorial [3,408,695] domain and the end of the Primorial [3,408,696] domain.
      Thank you Mathematica and my new Ryzen 3700X-based desktop for calculating it out for me. My old Phenom II x6 1045T system just wasn't quite up to the task [though it was a decade old]...

    • @MGmirkin
      @MGmirkin 3 года назад

      Anyway, here's the Mathematica code I used, in case anyone cares. ;)
      -----
      (* Largest known prime: 24,862,048 digits long *)
      FirstPrime = 1;
      LastPrime = 3408695;
      PrimeRange = Range[FirstPrime, LastPrime];
      PrimeList = Prime[PrimeRange];
      Times @@ PrimeList;
      IntegerLength[Times @@ PrimeList]
      [Result:] 24862045
      -----
      (* Largest known prime: 24,862,048 digits long *)
      FirstPrime = 1;
      LastPrime = 3408696;
      PrimeRange = Range[FirstPrime, LastPrime];
      PrimeList = Prime[PrimeRange];
      Times @@ PrimeList;
      IntegerLength[Times @@ PrimeList]
      [Result:] 24862053
      -----
      Just something amusing I fiddled with in my spare time. ^_^

    • @MGmirkin
      @MGmirkin 3 года назад

      Anyway, you'd have to know the first 3,408,695 primes and multiply them together to find out the sieve domain size just to figure out that it's a "candidate," but you'd have to know like all the primes less than or equal to the square root of the number, in order to basically "prove"/check that it's actually prime. Or something? Not entirely sure how they proved it's prime without knowing all the earlier primes [we don't]... Guess they must have some simpler proving method that works on mega-primes? Dunno...