You are correct. Thank you for the observation. I hope others can help out like this in other videos. I will leave a note in the video description. I appreciate your keen attention.
This really helps! For 1234ˆ432, shouldn't the answer be 36? ((17ˆ4)ˆ108) should have been simplified to (21)ˆ27 since 108 should be divided by 4? It will then give you 41. So it should be 24x4x41 = (....36).
@@PrimeNewtons is that an error really? Because 17^4=21 and if it should be raised to power of 4. You'll get (21^4)^27 . It will give the answer as again as 81^27=61 so 56 is the answer. Please explain sir.
Well done, but the rule of number 5 doesn't always work successful, because if you calucl 5^26 you'll get 96 as they are last digits and not 25 as you said... Can you explain why?
@@PrimeNewtons in fact i used my c++ compiler and unsigned long long as type of variable to store the input, and the result of calcul of 5^26 gave me : 1490116119384765696 I don't know how, perhaps there was something wrong in limit of variable or in my compiler.. Thnks any way ✌
Okay, I can't help with that. I'm sure you know that your answer is not a multiple of five. You should ask some c++ savvy person. I'm just a math teacher.
*@ Prime Newtons* -- As with another comment in another video of yours, please *stop* using the implication symbol. The equals symbols needs to be used instead.
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i like your video. explained in a very simple and clear way
Well done... I have really learnt alot from your videos. However, in this video you got 63 as the last two digits of 47³ whereas it should be 23
You are correct. Thank you for the observation. I hope others can help out like this in other videos. I will leave a note in the video description. I appreciate your keen attention.
thank you sir for this explanation. Very helpful.
Great video. Thank you!
This really helps. Thanks
Thank you sooo much!
last two digits of 247^223 should be 23, no? 47^3 mod 100 is congruent to 23.
Hi sir, why do we multiply by the last digit? for example in the video you only multiplied it by the 2 at the 2nd of the 132
This really helps! For 1234ˆ432, shouldn't the answer be 36? ((17ˆ4)ˆ108) should have been simplified to (21)ˆ27 since 108 should be divided by 4? It will then give you 41. So it should be 24x4x41 = (....36).
That was no error. I just ran it on my computer, and the last two digits are 56.
@@PrimeNewtons But when I run it on wolfram, the last two digis should in fact be 56.
@@PrimeNewtons is that an error really? Because 17^4=21 and if it should be raised to power of 4. You'll get (21^4)^27 . It will give the answer as again as 81^27=61 so 56 is the answer.
Please explain sir.
You're correct. There was no error. Thank you
Correct
Well done, but the rule of number 5 doesn't always work successful, because if you calucl 5^26 you'll get 96 as they are last digits and not 25 as you said...
Can you explain why?
5^26=1,490,116,119,384,765,625
@@PrimeNewtons in fact i used my c++ compiler and unsigned long long as type of variable to store the input, and the result of calcul of 5^26 gave me :
1490116119384765696
I don't know how, perhaps there was something wrong in limit of variable or in my compiler..
Thnks any way ✌
Okay, I can't help with that. I'm sure you know that your answer is not a multiple of five. You should ask some c++ savvy person. I'm just a math teacher.
@@PrimeNewtons yes sir you're right, i respect you for your interest, and thank you for everything 👍👍
what about 1234^5678 using exponent rules
How about last 3 or 4 digits?
I don't know how to do that
*@ Prime Newtons* -- As with another comment in another video of yours, please *stop* using the implication symbol. The equals symbols needs to be used instead.
Noted
Find last twp dgt pf 22^33
please do last 3 digit
That would require a lot of number theory. Let's see.
Bro u sigma
I don't know Will Smith makes math tutorials, hahaha
He doesn't.
You have a stupid comment. I reported it as spam.