A Cool Cube-root Challenge | IMO | Algebra

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  • Опубликовано: 7 сен 2024

Комментарии • 11

  • @user-kt1dm9jz5t
    @user-kt1dm9jz5t Месяц назад +2

    E=1+2(2)^1/2

  • @yakupbuyankara5903
    @yakupbuyankara5903 Месяц назад +1

    2×(2^(1/2))+1.

  • @Richardsui-e5u
    @Richardsui-e5u Месяц назад +1

    =1+(2)3/2

  • @user-kp2rd5qv8g
    @user-kp2rd5qv8g Месяц назад +1

    56+10√(32) = (2+2√2)^3. So, E = [25+22√2]^1/2. But 25+2√2 = (1+2√2)^3 > E = 1 +2 √2.

  • @RajeshKumar-wu7ox
    @RajeshKumar-wu7ox Месяц назад +1

    2√2 +1

  • @mariusherghelegiu6241
    @mariusherghelegiu6241 Месяц назад

    somehow out of the "gut" the trasnformation showing there are cubes ... One can easily show by establishing a 3rd degree system of 2 vars, then noticing the (1,1) and (1,2) are the solutions for the first respective the second system ...

  • @user-ny6jf9is3t
    @user-ny6jf9is3t Месяц назад +1

    (2×ριζα2)+1

  • @kassuskassus6263
    @kassuskassus6263 Месяц назад +1

    1+2sqrt2

  • @RealQinnMalloryu4
    @RealQinnMalloryu4 Месяц назад

    {9x^3+"33x^3}= 42x^6 {168x^3+30x^3}= {198x^6+96x^3}= 294x^9 {42x^6+294x^9}=336x^15 10^306^6x^3^5 2^55^6^6^6x3^5 2^1^1^3^2^3^2^3^2x^3^1 1^1^1^1^1^1^2x^3^1 1^2x^3^1 2x^3 (x ➖ 3x+2).

  • @tanbw922
    @tanbw922 Месяц назад

    cube root of 25?