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@@raiza.chakufora5271 well then the answer is what I said before. A sigma agebra is contained the power set (and satisfied certain properties) a subset of R cannot be any sigma algebra
![Measure Theory 2 | Borel Sigma Algebras [dark version]](/img/1.gif)
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❤❤❤ pdf please
@@HanaHana-r5u You can access the boards by becoming a donor on Ko-fi (ko-fi.com/problemathic ) or a Patreon (www.patreon.com/problemathic/membership) for a very small amount!
Your style of explaining stuff is very easy to catch...wish u a great future in online math community❤
Thanks!
How do we prove that uncountable subset of R is not a borel sigma algebra
What do you mean? A sigma algebra will be a set of subsets of X, not a subset itself 🤔
Ooh it's prove that a non countable subset of R is not a borel sigma algebra
@@raiza.chakufora5271 well then the answer is what I said before. A sigma agebra is contained the power set (and satisfied certain properties) a subset of R cannot be any sigma algebra
Thx dearest
Wow! I like your explanation. thumbs up
Thanks! 🥰
Just too good.
Glad you liked it!! 🥰