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great great I have no words to say After more than 50 youtube videos I got satified with this one .thanks a lot sir
WelcomeDo like share and subscribein which university yo are studying..?
AT INTIAL STAGES I FACED DIFFICULTY BUT WHEN I HOVERED HERE I FINALLY GOT IT THANK HUDDAR SAB
Welcome Do like share and subscribe
Great explanation..thnq sir 😊
Really great explanation sir! Thank you so much for explaining it.
WelcomeDo like share and subscribe
Thank you sir... Explained well
Very good explanation
Is this come under XOR with fully functioning feed forward network
Yes
I did not understand as to why you didi not change the value of w11, while u did it in previous example u taught.!!
Output of w11 = 1, hence it is not changed. In above slides, it's typo error.
Your great sir thank u soo much ❤
When did he used the values from the problem
Really great explaination!!
Thank You Do like share and subscribe
It is not necessary that weights should match at the end irrespective of what we had taken in beginning. Is it ?
Based on initial weights, final weights will change.
Thank you for sharing !!
thanks good explanation.
In table for z1 and z2 why you have not changed values to their complementry values
w21 should be 0.5 instead of -0.5 i think
The one at 9:27?I think it's already correct, likew21 = 1 + 1.5 * (0-1) * 1 = 1 + 1.5 * (-1) * (1) = 1 + (-1.5) = -0.5
Our teacher copied your slide..and made the same mistake at updated w11=0....
Which university..?
@@MaheshHuddar Premier University 🙂
thank u sir
sir truth table galat banayi hai aapne
Watch complete video There is no mistake
@MaheshHuddar Sir 🥺. You said if X and Y both are O means output is Zero. If any either one is high it's 1. But you did mistake in X1=0; X2= 1. The answer you mentioned is 0. Check please 🥺
@@janat.nikash0724 0 and 1 is 0
thaks
great great I have no words to say After more than 50 youtube videos I got satified with this one .thanks a lot sir
Welcome
Do like share and subscribe
in which university yo are studying..?
AT INTIAL STAGES I FACED DIFFICULTY BUT WHEN I HOVERED HERE I FINALLY GOT IT THANK HUDDAR SAB
Welcome
Do like share and subscribe
Great explanation..thnq sir 😊
Really great explanation sir! Thank you so much for explaining it.
Welcome
Do like share and subscribe
Thank you sir... Explained well
Welcome
Do like share and subscribe
Very good explanation
Is this come under XOR with fully functioning feed forward network
Yes
I did not understand as to why you didi not change the value of w11, while u did it in previous example u taught.!!
Output of w11 = 1, hence it is not changed. In above slides, it's typo error.
Your great sir thank u soo much ❤
Welcome
Do like share and subscribe
When did he used the values from the problem
Really great explaination!!
Thank You
Do like share and subscribe
It is not necessary that weights should match at the end irrespective of what we had taken in beginning. Is it ?
Based on initial weights, final weights will change.
Thank you for sharing !!
Welcome
Do like share and subscribe
thanks good explanation.
Welcome
Do like share and subscribe
In table for z1 and z2 why you have not changed values to their complementry values
w21 should be 0.5 instead of -0.5 i think
The one at 9:27?
I think it's already correct, like
w21 = 1 + 1.5 * (0-1) * 1 = 1 + 1.5 * (-1) * (1) = 1 + (-1.5) = -0.5
Our teacher copied your slide..and made the same mistake at updated w11=0....
Which university..?
@@MaheshHuddar Premier University 🙂
thank u sir
Welcome
Do like share and subscribe
sir truth table galat banayi hai aapne
Watch complete video
There is no mistake
@MaheshHuddar Sir 🥺. You said if X and Y both are O means output is Zero. If any either one is high it's 1. But you did mistake in X1=0; X2= 1. The answer you mentioned is 0. Check please 🥺
@@janat.nikash0724 0 and 1 is 0
thaks
Welcome
Do like share and subscribe
Really great explanation sir! Thank you so much for explaining it.