Calculus 3: Vector Calculus in 3-D (21of 35) Magnitude of the Cross Product of 2 Vectors

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  • Опубликовано: 11 окт 2024
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    In this video I find the magnitude=? of the cross product of vectors AxB=? given A=3i-2j-5k and B=i+4j-4k using 2 method. Method 1: |AxB|=|C|=ABsin(theta)=?, Method 2: using matrices.
    Next video in the series can be seen at:
    • Calculus 3: Vector Cal...

Комментарии • 28

  • @Decidiovs_OG
    @Decidiovs_OG 4 года назад +6

    why did it change from sin to cos? And Vice Versa?

    • @Koolb-wn4er
      @Koolb-wn4er 4 года назад +2

      It's because he was using the dot product formula when solving for theta. Then when he was solving for the cross product, he switched back.

  • @mclovelacenoether
    @mclovelacenoether 7 месяцев назад +1

    Thank you for your video!

  • @safartalib5414
    @safartalib5414 3 года назад +4

    why did it change sin for cos??😐

    • @mikefaraday1720
      @mikefaraday1720 2 года назад

      There were two formulae involved. A different formula involving cos and dot product was used to find theta before substituting theta into the cross product formula involving sin to find the magnitude of the cross product. It may be late for you but hopes this helps somebody.

  • @carlbenedictsolomon5894
    @carlbenedictsolomon5894 2 года назад +1

    Thank you sir!

  • @humpty2360
    @humpty2360 2 года назад +1

    Thank you

  • @cyrusdotillos3498
    @cyrusdotillos3498 2 года назад +1

    Sir I have a vector product given the problem is my answer using the vector product is in negative but using the magnitude equation which is ABsintheta is positive but still they ended up the same answer, they only differ in sign. Is it possible sir or the way I solve was wrong

    • @MichelvanBiezen
      @MichelvanBiezen  2 года назад +2

      A x B = - B x A The sign is only relevant if you want the direction of the vector product. When you use AB sin(theta), then you are calculating the magnitude of the vector product, and magnitudes of vectors can only be positive.

    • @cyrusdotillos3498
      @cyrusdotillos3498 2 года назад +1

      thank you sir

  • @divyamtyagi
    @divyamtyagi 6 лет назад +1

    Sir please give the Proof of cross product formula

  • @hectorlml1257
    @hectorlml1257 3 года назад +1

    Hi teacher If I get a result close to the other, is it correct or is there something to correct? Greetings.

    • @MichelvanBiezen
      @MichelvanBiezen  3 года назад +1

      It is probably correct. There may be some round-off errors.

    • @hectorlml1257
      @hectorlml1257 3 года назад

      @@MichelvanBiezen Thank you so much!

  • @agharenovweavwerosuo1916
    @agharenovweavwerosuo1916 Год назад +1

    Sir why did you change it from sin -cos

    • @MichelvanBiezen
      @MichelvanBiezen  Год назад +1

      Not sure what you mean by: "from sin - cos"

    • @MichelvanBiezen
      @MichelvanBiezen  Год назад +1

      We use the dot product to find the angle between two vectors (since A dot B = | A| * |B| cos (theta) )

  • @mtv280
    @mtv280 3 года назад +1

    How did you get 7,14,28?

    • @MichelvanBiezen
      @MichelvanBiezen  3 года назад +1

      That was shown in the videos before this one in the playlist: Calculus 3: Vector Calculus in 3-D (19 of 35) How to Calculate the Cross Product of 2 Vectors?

    • @mtv280
      @mtv280 3 года назад

      @@MichelvanBiezen ok thank you

  • @battulavivek8550
    @battulavivek8550 4 года назад

    Very good

  • @raiton_gamer
    @raiton_gamer 2 года назад +1

    Arigato sir

  • @Tantheta.30
    @Tantheta.30 Месяц назад

    Jee wale like karo😂