INDEX NOTATION; equations when the base is unknown

[@lushomo.s8398]

Mr Chaumba you're a very good teacher,I am a newly deployed mathematics teacher and your channel has really helped me remember most of the concepts.

[@kanengahams8736]

Thank you so much sir God bless you for teaching us.

[@jeankachali3647]

🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼👏👏👏

[@rodgersoluoch7340]

Good teaching indeed,
I've understood the concept

[@okekemosam9057]

So amazing

[@esthersiamutwa]

Thank you I have learnt

[@tumelosakanga9652]

Thank you so much sir

[@kesienaaloko3107]

Beautiful

[@DaddaB-d9l]

Thanks a lot 🎉😊❤❤❤

[@Hafi-ek7fe]

Thanks a lot🙏

[@annasililo5252]

Thanks

[@olawalesauban4011]

Thank you so much

[@kesienaaloko3107]

I wish to express my desire to submit the answers to the questions sir

[@Blessings167]

I now understand

[@esthermukwasa8899]

Kindly send the video on sets

[@tuzagirwanimanaepimaque9966]

Please , can you explain on question one ?? How do you get one roots?? I think that one was quadratic equation .

[@TimothyPhiri-d4j]

It can't be a quadratic equation because 4 is constant, meaning that it has no variable of y. Unless if it was like this y²=4y. Thank you for listening.

[@diorlove651]

Please sir I don't understand by what you mean by resiprocal I am still confused

[@kesienaaloko3107]

It means to switch the numbers. ⬇⬆
The numerator becomes the denominator and the denominator becomes the numerator.

[@mubangasylvester8708]

Sir, when a negative fraction reciprocate is it not going to be a positive or maybe I'm wrong somewhere?

[@TimothyPhiri-d4j]

The negative sign still remain same. You just flip the numbers ( the one on top comes down and the one down comes on top ).

[@MercyMushota-md6zg]

How can I know if my answers are correct

[@tesminwayla9477]

@chaumba mbondo sir in the exercise the first question isn't ok......because 5 has no cube root or maybe you leave it just like that

[@TimothyPhiri-d4j]

Yes 5 has no cube root. But in that case you can end it like this 3√5, there is no problem.

[@emmanuelsakala6700]

5x^1/2 x=80 not 16