Sir, why the cyclic integral of dQ in case of reversible heat pump or refrigerator can be equal to zero??Atleast some positive work input will be required there also.
@jagdeesh he erased in example 4 that is irreversible process but there was an equal to symbol in example 2 which is a refrigerator example reversible process
For a reversible process , Q1/T1=Q2/T2, thus Q1/T1-Q2/T2=0 thus Q1/T1+(-Q2/T2)=0, Q1 is heat accepted from a reservoir at temperature T1 and Q2 is heat rejected to reservoir at temperature T2(therefore , is denoted by "-Q2").
In Clausius inequality there are explained that T is the temperature of the source in several books but you told that T is the temperature of system. Please explain me the reason sir..
Sir can you kindly explain the question Prove that both Kelvin Planck and Clausius statements are contained in Clausius inequality statement that the proceses for which integral of delQ/T >=0 are impossible
You are one of the reasons why I love thermodynamics, sir.
Great teaching, love you sir. Thanks a lot
Love this lecture. Amazing way in dealing with subtle things.
Great video thank you to nptel and all IIT's professor and all team who contribute to make nptel's video.
This is an awesome lecture and very informative 👍
Thank you sir 🙏
VERY GOOD VIDEO
WOW
16:17 , its true for the refrigerator, but not for heat pump, as there are different formulae for efficiency in both case. Am I correct?????
as in refrigerator QL is constant, while in heat pump QH is constant in irreversible process.
Sir, why the cyclic integral of dQ in case of reversible heat pump or refrigerator can be equal to zero??Atleast some positive work input will be required there also.
Sir said the same too. Watch from 14:35, he was erasing 'equal to' symbol at 14:40.
@jagdeesh he erased in example 4 that is irreversible process but there was an equal to symbol in example 2 which is a refrigerator example reversible process
It is not equal to zero
Integral of dq/t is only equal to zero
For a reversible process , Q1/T1=Q2/T2, thus Q1/T1-Q2/T2=0 thus Q1/T1+(-Q2/T2)=0, Q1 is heat accepted from a reservoir at temperature T1 and Q2 is heat rejected to reservoir at temperature T2(therefore , is denoted by "-Q2").
Thanks sir for your kind information.
In Clausius inequality there are explained that T is the temperature of the source in several books but you told that T is the temperature of system. Please explain me the reason sir..
clear, but where does deltaQ/T comes from ?
Sir can you kindly explain the question
Prove that both Kelvin Planck and Clausius statements are contained in Clausius inequality statement that the proceses for which integral of delQ/T >=0 are impossible
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Good
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Bakwas