..... but could you? No one has ever found such a loop. If numbers are infinite, then the numbers in the sequence which can be divided by two constantly back to 1 are infinite too and subsequently using the arbitrary rules of this conjecture, eventually you fall onto that constantly descending sequence, no?
thats my whiteboard!
You could get stuck in a local loop.
..... but could you? No one has ever found such a loop.
If numbers are infinite, then the numbers in the sequence which can be divided by two constantly back to 1 are infinite too and subsequently using the arbitrary rules of this conjecture, eventually you fall onto that constantly descending sequence, no?