The Fabry Perot Interferometer

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  • Опубликовано: 30 сен 2024
  • By Martin van Exter

Комментарии • 36

  • @prateekjawalkar4112
    @prateekjawalkar4112 6 лет назад +7

    Thks q soo much sir love and respect from India

  • @CognitiveEvolution
    @CognitiveEvolution 2 года назад +3

    Thank you. I have watched several videos on the FB interferometer, but this is the first one that clearly explained that and how all the light is transmitted out the mirror opposite the entrance mirror.

    • @family-accountemail9111
      @family-accountemail9111 Год назад

      Same here the explanation here have me the eureka moment of understanding that's like a drug ! I want more!

  • @Bert0ld0
    @Bert0ld0 6 лет назад +4

    Thank you! You are very good at explaining things.

  • @nohaivce2614
    @nohaivce2614 3 месяца назад

    awesome, super well explained and introduced thru a practical POV as well! thank you!

  • @jaredjones6570
    @jaredjones6570 3 года назад +1

    The magic of interference :)

  • @sanampallegowtham7571
    @sanampallegowtham7571 6 лет назад +2

    excellent but why dont you have more views

  • @nkeiruu7866
    @nkeiruu7866 3 года назад +1

    This is an awesome explanation in plain English.Thank you so much from the USA

  • @benjaminsteinberg8975
    @benjaminsteinberg8975 6 лет назад +1

    Thank you for this excellent presentation. I'm looking forward to your next one, is there a way I could follow you on youtube?

  • @hanaizdihar4368
    @hanaizdihar4368 5 лет назад +1

    Cant read the green writing , its so well explained but cant read

  • @SaiPraneethMunjeti
    @SaiPraneethMunjeti 5 месяцев назад

    and that's the magic of interference

  • @amersaad8939
    @amersaad8939 5 лет назад +1

    Thanks you professor for this wonderful course

  • @safdarsafdari7289
    @safdarsafdari7289 4 года назад

    two questions: does from where input light enters light reflected end transmitted from left mirror has 2 times intensity?
    in confocal interferometer light transmitted from right mirror doesn't diverge?

  • @khatrnafar
    @khatrnafar 2 года назад

    Thank you for this clear and concise explanation.

  • @karthikknarayanan776
    @karthikknarayanan776 3 года назад

    Great explanation, thanks for making this!

  • @jonathanpilgram1119
    @jonathanpilgram1119 4 года назад

    MARTIN!!! Goed filmpje.

  • @samantahira8692
    @samantahira8692 4 года назад

    What is nanoparticles based on Etalon?

  • @dhruvg550
    @dhruvg550 4 года назад

    That's such a beautiful concept!

  • @jj123123123100
    @jj123123123100 3 года назад

    So helpful, thank you!

  • @lambda4931
    @lambda4931 5 лет назад

    Very informative

  • @shahnoorali1904
    @shahnoorali1904 3 года назад

    Excellent Explanation

  • @FiduzP88
    @FiduzP88 7 лет назад

    Question: why do you have to slightly focus inside the confocal FP cavity? Is it possible to input just a narrow collimated beam?
    Thanks!

    • @cornekoks5211
      @cornekoks5211 3 года назад

      Yes, that is possible! The amount of light you couple into the FP is however proportional to the mode overlap between the incoming beam and the cavity eigenmode. A slightly focussed beam has a larger mode overlap than a collimated beam. :)

  • @superbialm
    @superbialm 4 года назад

    Thank you so much!

  • @ElPrestigo
    @ElPrestigo 4 года назад

    If 100% of the signal is transmitted, then 0% is reflected. However when I try to do the calculations I end up with the wrong answer. How would the calculation for reflection look like? Sadly I cannot show my calculations, because if I do the comment gets removed.

    • @ElPrestigo
      @ElPrestigo 4 года назад

      Only if I take the reflection from outside to inside the cavity (r) different from the reflection that occurs inside the cavity (r') with r = -r', then it does add up to zero. Is that true and why?

    • @ElPrestigo
      @ElPrestigo 4 года назад

      @@DW-iq8lt I would say that it is precisely what 100% transmission means. Simply put, everything that goes in on one end comes back out the other end. And this is also what the professor in the video is showing and several times stating. Why do you think otherwise and how would you then define 100% transmission?

    • @DW-iq8lt
      @DW-iq8lt 4 года назад

      My mistake. You were right about the transmitted percentage. And at resonance, reflected intensity is zero.

  • @MaratBikmullin
    @MaratBikmullin 2 года назад

    Спасибо!

  • @sudipnayak1188
    @sudipnayak1188 4 года назад

    Thanks a lot

  • @phatchick691
    @phatchick691 6 лет назад +2

    helped a lot on my assignments thank you :)

  • @therealkeshavsehgal
    @therealkeshavsehgal 7 лет назад +1

    Good one
    Thanks

  • @therealkeshavsehgal
    @therealkeshavsehgal 7 лет назад

    Fyi I'm just a beginner so it's a little high for me

  • @therealkeshavsehgal
    @therealkeshavsehgal 7 лет назад

    😐😐😐

  • @anujKumar-vs2cy
    @anujKumar-vs2cy 5 лет назад

    Sir bsc2 mai physics ke important question explain kr dijiye