How To Solve A Homemade Exponential Equation

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  • Опубликовано: 15 дек 2024

Комментарии • 32

  • @FisicTrapella
    @FisicTrapella 11 месяцев назад +23

    b/a = sqr(7) (9:46)

  • @cav1928
    @cav1928 11 месяцев назад

    I made it with natural logarithms, and applied it several times. It is ease for me to think in log terms that in tower exponents, at the end of course I need to do a variable change and the result is the same. Sincerely at first glance I guess that my solution was wrong because it was very long for a problem that seems at first sight simple.

  • @tarunmnair
    @tarunmnair 11 месяцев назад +1

    I think the value of x is, x=-1/2 +i.arctan(sqrt(7))/ln2 ... that 4 gets cancelled when we do b/a...

  • @Qermaq
    @Qermaq 11 месяцев назад

    I have a problem with the inverse tangent being written as tan(-1)theta. If we want the tan of an angle squared, it's tan(a^2). If we want the tan of a to be squared, it's tan^2(a). So if I want the tan to be raised to the power -1, I must write tan^(-1)(a). So it's ambiguous.

    • @richardguimond7665
      @richardguimond7665 11 месяцев назад

      Indeed I prefer the inverse tangent being written as arctan because there is no risk of ambiguity.

  • @robertibatullin8329
    @robertibatullin8329 11 месяцев назад

    Generally speaking, are there any real a and b such as ab, a1, b1, and the equation a^a^a^x = b^b^b^x has a real solution? An intuitive answer is no, but can it be proven?

    • @robertibatullin8329
      @robertibatullin8329 11 месяцев назад

      The answer is yes, I've found one case and there are infinitely many of them. For a=256, b=256^2, the equation a^a^a^x = b^b^b^x has a solution x=-1/4

  • @Qermaq
    @Qermaq 11 месяцев назад

    From the thumbnail: 2^2^2^x = 4^4^4^x appears to be nonsense. If it were 2^x = 4^x we could easily say x = 0. But beyond that, any change we make on one side is blown up on the other. So I'm stumped for now. I think there's no real solutions.
    5:10 yep I called it. Have fun! I don't chase after all real adversaries!

  • @juergengeisslinger5051
    @juergengeisslinger5051 11 месяцев назад +1

    HELLO
    ARE YOU SURE, THAT THE ANGLE PHI IS CORRECT?

  • @adithyan9263
    @adithyan9263 11 месяцев назад

    Cool

  • @penguin9257
    @penguin9257 11 месяцев назад +3

    2=4

    • @monasimp87
      @monasimp87 11 месяцев назад +1

      Really nice solution

  • @StaR-uw3dc
    @StaR-uw3dc 11 месяцев назад

    Nice.
    Slightly changed equation: 2^(4^(2^x)) = 4^(2^(4^x)) has the real root.

    • @SyberMath
      @SyberMath  11 месяцев назад +1

      Thank you!

    • @SyberMath
      @SyberMath  10 месяцев назад +1

      Here comes the video. Thank you for the suggestion...❤️😍
      Will go public in less than 8 hours:
      ruclips.net/video/8bpzw5bBY40/видео.html

    • @StaR-uw3dc
      @StaR-uw3dc 10 месяцев назад

      @@SyberMath Nice to hear it.

  • @Palkia8-Bit
    @Palkia8-Bit 11 месяцев назад

    I am still convinced you’re tigerofwind XD

  • @scottleung9587
    @scottleung9587 11 месяцев назад

    Wow, that was a doozy! Nice job, though.

  • @mcwulf25
    @mcwulf25 11 месяцев назад +1

    Could see there was no real solution because 2 is not equal to 4. And x=0 doesn't make it go away.

    • @SyberMath
      @SyberMath  11 месяцев назад +2

      could've had some logarithmic solutions

    • @mcwulf25
      @mcwulf25 11 месяцев назад

      @@SyberMath how would that work?

    • @mcwulf25
      @mcwulf25 11 месяцев назад

      @SyberMath OK so you ln both sides a few times and get x * (some weird function of ln(2)) = x * (some weird function of ln(4))

  • @yoav613
    @yoav613 11 месяцев назад

    Nice,but i hope you do not ask problems like this in your tests😂

  • @giuseppemalaguti435
    @giuseppemalaguti435 11 месяцев назад

    Posto t=2^x, risulta t=1+2t^2 che pero non da soluzioni reali...boh

  • @theCzechoslovak
    @theCzechoslovak 11 месяцев назад

    Try to guess the solution
    The solution:

  • @denisseveliz2007
    @denisseveliz2007 11 месяцев назад

    Hello, my boyfriend really like your channel and spend a lot of time solving your problems. His birthday will be soon, asking you our the community to create a problem and I can decorate his birthday cake with it. I hope you can guys help me. Thank you 🫶