re Model (Solved Problem 1)
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- Опубликовано: 24 дек 2024
- Analog Electronics: re Model (Solved Problem 1)
Topics Covered:
1. Calculation of emitter current.
2. Calculation of dynamic emitter resistance.
3. Calculation of input impedance.
4. Calculation of output impedance.
5. Calculation of voltage gain.
6. Calculation of current gain (Homework)
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You are so awesome sir! Very helpful for EE, CPE, & ECE engineering colleges.
sir i have seen your all the videos of digital electronics. i am really very thankful to you.
sir if you could upload more videos of analog electronics covering the topics of opamp,amplifers,feeback,oscillators,power amplifers,jfet,mosfet etc it would be better for my preparation,not only mine,for everyone as well. We will always be greatful to you for your great contributions in our preparations.
Your videos are helping me to prepare for my electronics exam. Thanks!
In order to calculate the current gain, first we have to determine both io and ii.
This is done, in my opinion, by using the impedances zi and zo and ohm's law. Therefore, ii = vi / zi, and io = vo / zo.
By doing the fraction in Ai, we will have the answer of around 61.
THANKS
where did you get vi and vo from
@@abusamraaslan3157
Vi=ib(B+1)re
Vo=io(re)
what about RL(load resistance)?
I=V/R
Then
Ai=(Av*Zi)/Zo
Ai=(216.1*619.55)÷2.08k
Ai=64.37
Approximately also we can calculate
RL is infinite
ro
why didnt u use -ve sign from av?
@@vsrgaming6680 How that formula Ai = AV*Zi/Zo came
since Rb>=10(beta+1)re and ro>=10Rc therefore Ai=beta..which is 60
@Samay Kar smart boi
Still cnt figure out
With a negative?
io=ic because you should remember that in the original circuit that's the current at the output:
Ai=(Beta*RB*ro)/(ro+Rc)(RB+Beta*re)
big respect to you sir, more practical problems to upload sir, Thanks a lot!
Ai=current output /current input =ic/ib=Bib/ib=B=60
@Sơn Nguyễn Hồng R load not given and there is open circuit that's load R is infinite and that's the reason gain will be beta
In general if we don't consider simplification then current gain=56.74
And if simplification is considered i.e. here Rb>>10(beta+1)re & ro>>10Rc then Current gain= beta=60
Without any approximations, I guess A_i should be 59.86.
56.74 is current gain\
If we consider parallel combination of r0 and Rc then the current gain is 59.86 and it's 56.74 when only Rc is considered. But don't know what should be the exact concept.
@@debanjan5402 where is the RL? How do we calculate it?
You are doing a great job sir....thanks a lot sir
Thanks Sir ....these videos are excellent for the subject.Please add more videos on other topics.
thank you soo much sir . u made it easier for me. bless your soul
Eagerly waiting for rest of the videos...very helpful series Sir.. Thanks a lot :)
Nice piece of work.Well Done
Thank you very much
thank u sir :)
please upload videos on opamp and multivibrators
your lectures are awesome
There is no load across the output. As a result, there will be no output current. So the current gain will be Ai= 0/i(input current)=0.
or we can consider the R(load) as infinity. Then if we put the value on formula, we will get the Current gain 0.
current gain=59.86===(60)approx..
where do we get RL?
i think it's equal to zero
@@chitikeshikarthik5832
@@sahilking8357 Not necessarily it should be ...if the same configuration was maintained with the small singal added in the emitter branch then voltage gain would be positive
@@chitikeshikarthik5832 RL=0??
thanks sir
Ur the best💖
Actually, you must take io as current passing through Rc....Not the io explained by the lecturer...Refer boylsted page no. 287...io is taken as current passing through Rc..
If we consider parallel combination of r0 and Rc then the current gain is 59.86 and if we consider only the Rc current then it's 56.74. What should be the exact ans?
Current gain=60 with 180 deg phase displacement
Ai= Av*(Zi/Zo) which is equals to -61 approximate
Please how correct is this formular
Thank you so much sir
Ai = 0 bcoz RL = infinity
Thank you very much
will the current gain for this case be zero as there is no load connected?
Ai = beta...which is given 60 ( because of (ro>=10*Rc) and (RB>=10*beta*re).
current gain is approx. 60
current gain will be -B*Rb/(Rb+(B+1)Re)
Gaurav Agrawal y -????
Sir please add videos on FET and FET biasing. your all lectures are fabulous.
in minute 2:51, why is it 12v - 0.7v? isnt the direction of the vbe positive?
Wow 6 years ago, hope you got your degree
Value of current gain = 59.8 approx
sir i need to small signal analysis of fet at high and low frequency and bjt at high frequency also
Sir in calculating voltage gain you only considered rc for output voltage while it should be ro||rc.
So if I put heavy load on this circuit, lets say I'll change the Av?
and how can I calculate cut-off point?
sir please upload further videos ......op amps,Jfet ,mosfet etc ..our whole college is dependent on u :/ our semester will end this november sir please sir ..i beg u sir
+Neso Academy thank you sir...
Isn't your November came till now ????
+Neso Academy sir please give the solution how to calculate current gain. Here load resistance is not given.but the general formula includes load resistance..please help me....
@@rajapandyp2505 bhai load ke bina wala formula derive kr le khud se
as load is not given then output current (Io)=Ic and we know that Ic=(beta)Ib.
now , current gain (Ai)=Io/Ii=Ic/Ib=(beta)
therefore current gain = 60;
thanks.
Thanks sir.......please upload MATLAB videos also.......you are awsome
Not just matlab upload any subject videos they all will be equally awesome....
how we obtain the formulas of v0 and vi ?
for voltage gain
I'm feeling a bit slow here, by with no load resister RL, there would be no output current, so isn't the current gain zero (that's what the derived formula Ai would suggest).
sir please upload some more problems of h parameter model
Sir ,please add videos on FET and other chapters.
What if have Rsense and a battery source Vs than will Ib b same?
thank u very much sir
@neso academy eagerly waiting for video no.-105
sir, please add more videos...
sir plz upload more lectures on signals and syestem
Your re model and hybrid model same ? Only change the re and r pi ?
sir plz upload the rest videos..we hv very less time for GATE
GATE 2017 .... When will you complete the series ???
Rl is not given, should we consider it to be much less than ro?
Don't we need RL for calculating current gain??
Actually, you must take io as current passing through Rc....Not the io explained by the lecturer...Refer boylsted page no. 287...io is taken as current passing through Rc..
If follow the lecture, according to his io, if RL is open circuited, io =0 always and hence Ai=0
Ai = 60. ( Ai is approximately equal to Beta in case of r0>10Rc and rb>10(B+1)re)
why is one of the input resistors (1+b)re?, i thought it should only be re
current gain is Ai = 59.86
what happend when we put high resistence in emmiter terminal
current gain is nothing but directly equals to beta
Ai=beta
therfore answer is 60
I got 59.86 for the current gain
Booyaka booyaka 6:44, hey!
haha! 6....1....9
56.87
242.82a
Can anyone tell me why Rb is soo high than Rc in every case (270k ohms and 2.2 k ohms)
Current gain=-60(180 degree phase difference)
56.74
Is current gain 60 or -60?
Ai=61 (or)60
How is the current gain 60?
or can we consider beta value as current gain if load is not connected?
io = ic assuming no current flows through other branches (r0 ,Rc)... WTF
26mv where do u get it?
thermal voltage
Sir pls pls more videos of analog..and.. signal system
is it 60?...
guys??
appx. value of beta
60
plz explain me how u got
Wrong answer I think...you can not neglect beta* Re compared to Rb...
Ai= ic/ib= beta
Beta=60
That means Ai=60
59.863 is answer
sir
60.85
Bro at 9:46 plz can you tell me why Av=-216.1 ? Is it not Av=-Rc/re = 2.2/40 =- 0.055 ?
@@edhotchakma4772 no its 2200/10.18. = 216.1
Is Ai 60 or -60
without approximation Ai=56.74
Ai=60
Ai=Beta=60?
given/ assumed.
Ai = 59.86
Current gain hi to main tha. Whi no bataya sir
is it 60
Beta
a lecture on jfet .
Thank you so much sir
60
Ai=-60
60
Ai =60
60