Boron Aldol Reaction - Organic Chemistry, Reaction Mechanism

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  • Опубликовано: 10 сен 2024

Комментарии • 14

  • @danielchin9309
    @danielchin9309 2 года назад +5

    Where were your videos during my undergrad? 😂 Good content, keep it up!

    • @CasualChemistry
      @CasualChemistry  2 года назад +1

      Thanks for the feedback and glad you enjoyed the video 🙂

  • @Gurdeepsingh-wv5tn
    @Gurdeepsingh-wv5tn 11 дней назад +1

    Very nice explanation. I have one question, if you are taking R group as a iPr, then enolisation occur from other side because, NEt3 is not that much strong and bulky base.

    • @CasualChemistry
      @CasualChemistry  11 дней назад

      The main idea is there has to be a difference between the two sides of the carbonyl do differentiate between. The NEt3 is bulky enough but not too bulky to be able to get the H off the ethyl group but not the isopropyl group just on sterics. This is the dominant thing going on.
      I’m going to touch on this in my next video: another factor is the isopropyl group’s bulk favours the boron Lewis acid sitting on the ethyl group side. There’s also a Stereoelectronic effect that helps make the ethyl group’s protons a bit more acidic.
      These reactions are done at low temperatures when you need to be careful to select so small differences in activation energies are enough to get selectivity.

  • @nicholasmwanzia776
    @nicholasmwanzia776 Год назад +1

    Thanks for your wonderful explanation.

  • @m.jadidinejad6727
    @m.jadidinejad6727 Год назад +1

    Very good😊 when I understand problem I bacome very happy

  • @sarvanks7711
    @sarvanks7711 3 года назад +2

    Great explanation.

    • @CasualChemistry
      @CasualChemistry  3 года назад +2

      Many thanks :). I'll probably do some extension material on this type of aldol topic in the future as there's all sorts of ways of building stereocontrol into these models.

    • @sarvanks7711
      @sarvanks7711 3 года назад +2

      @@CasualChemistry Yes, that would be very great for everyone. Please.

  • @amitkumarde9239
    @amitkumarde9239 Год назад +1

    Hlw casual chemistry I love your lecture series. It helps me a lot even at my master's degree. I have a small question in your retrosynthesis series you said that boron enolisation give Z enolate but here E enolate gets formed. Here bulky iso propyl also present.

    • @CasualChemistry
      @CasualChemistry  Год назад +1

      That's great to hear - glad the videos are useful :) I think I've understood which other video your question refers to
      With the boron-mediated enolisation, it is very dependent on what you choose as the substituents/ligands on the boron centre and what you choose as the base. Hence, this technique is a reagent-controlled enolisation. Although others options exist, two common reliable techniques are:
      (1) For making Z enolates - use Bu2BOTf and iPrEt2N. This is a small alkyl substituent, a really good leaving group in the triflate, and a slightly bulkier base.
      (2) For making E enolates - use Cy2BCl and Et3N. This is a bulkier alkyl substituent, a less good leaving group in the chloride, and a slightly smaller base.
      I should probably get around to making a video lecture of some sort on enolates as I have lots of teaching materials on this topic as it's very close to my PhD work.

    • @amitkumarde9239
      @amitkumarde9239 Год назад

      @@CasualChemistry that will be great and thank you once again