2x2 Systems of ODEs: Imaginary Eigenvalues and Center Fixed Points

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  • Опубликовано: 5 янв 2025

Комментарии •

  • @johnstuder847
    @johnstuder847 2 года назад +21

    Another great video. I know this can be tedious for you, Dr Brunton, but please remember that is what makes these videos soooo valuable. Non-geniuses like myself can actually follow along, or rewind if needed, unlike classroom lectures where we spent endless hours lost and bored. I actually learn from your awesome lectures. Please stay patient, don’t skip steps, and keep stating the obvious…because if it was obvious, there would be no reason for this type of education. Thank you so much for this!

  • @willson8246
    @willson8246 2 года назад +9

    This is really great video. Thank you very much.
    BTW: 32:20 It's L^2+2.L+5.

  • @starriet
    @starriet 2 года назад +10

    For future ref for beginners)
    1. (28:15 and 35:40) The arrows in the figures should be clockwise direction.
    2. v=2y (not v=y) if the matrix is [[0,2], [-2,0]]
    3. (32:12) actually we don't need to calculate the 2nd order eq., but we can just add -1 to the previous lambdas(+/-2i). (because A-I*lambda=0)

    • @individuoenigmatico1990
      @individuoenigmatico1990 Год назад

      That's exactly true. With the (second-order) differential equation x''=-4x, we get by calling y=x'/2 the linear system
      (x' y')=[[0 2], [-2,0]](x y)

  • @alakeshchandramandal6787
    @alakeshchandramandal6787 Месяц назад

    Amazing way of explanation Prof. Brunton. Keep posting more and more such interesting, insightful, and pedagogical lectures for the present and future generations

  • @Dorstamo
    @Dorstamo 2 года назад +7

    This is art. Beautiful

  • @hydropage2855
    @hydropage2855 5 месяцев назад

    I cannot BELIEVE how underrated you are. You deserve to have millions of subscribers

  • @hoseinzahedifar1562
    @hoseinzahedifar1562 2 года назад +3

    This lecture was awesome... thank you.❤❤❤
    At 32:13, the determinant of matrix [-1-lambda 2; -2 -1-lambda] is equal to (-1-lambda)^2 + 4 = lambda^2 + 2lambda + 1 + 4, which equals lambda^2 + 2lambda + 5...

  • @rbmfavourites7122
    @rbmfavourites7122 17 часов назад

    In Steve’s example at the end of the video, the characteristic equation is: lamda squared + 2*lamda plus 5 = 0, giving the complex solutions: -1 plus or minus 2i, as expected.😊

    • @rbmfavourites7122
      @rbmfavourites7122 17 часов назад

      Sorry - my comment relates to Steve’s previous video on centres, not this video on Stability and Eigenvalues.

  • @michaelzyphur2476
    @michaelzyphur2476 2 года назад +1

    "this might be the point where you speed me up to 1.5 times and I go chipmunk... I've had a lot of coffee so that might happen already...". This is great math and comedy (that quote starting at 10:23).

  • @afammadudaniel2982
    @afammadudaniel2982 2 года назад

    This is beautifully quantum gate in Quantum information science and a squeezing operator in Quantum photonic. Beautiful!

    • @afammadudaniel2982
      @afammadudaniel2982 2 года назад

      I am referring to the rotation matrix. And as beautiful as this is, the position and velocity are conjugate variables in QIS

  • @TheEicio
    @TheEicio 2 года назад +1

    At the 28:00 minute mark, The phase diagram has the arrows pointing counter clockwise. Shouldn’t they be going clockwise? I.e, when the mass is pulled to a positive X, shouldn’t the velocity start in the negative Y direction, not positive Y.

    • @sigfridsixsis3255
      @sigfridsixsis3255 Год назад

      Correct. The velocity will be initially negative so with arrows clockwise

  • @deuteriumlyu9689
    @deuteriumlyu9689 2 года назад +3

    Thank you so much Steve, this is the best tutorial about ODE I have ever seen, very detailed and instructive. One quick question: at 26:32, double derivative of x equaling -4x actually renders A = {{0, 1}, {-4, 0}}, not the matrix you gave at the beginning A = {{0, 2}, {-2, 0}}. Even though they have the same eigenvalues (±2i), their eigenvectors are different, and the final expressions for x(t) and y(t) are different. I feel a bit puzzled, do you mind giving me some hints?

    • @chensong254
      @chensong254 2 года назад +2

      Let v = 1/2 * \dot{x}. Then \dot{x} = 2v, and \dot{v} = 1/2 \doubledot{x} = -2x.

  • @_vishal_kachhad_
    @_vishal_kachhad_ 2 года назад

    Thank you so much, professor. Waiting for the next video

  • @WalterTrindade-fe3pm
    @WalterTrindade-fe3pm 11 месяцев назад

    Thanks Mr. Bruton!

  • @GeoffryGifari
    @GeoffryGifari 2 года назад +1

    I noticed that the originial equation in vector and matrix form has 1st order derivative in time, while the (rotating) solution looks like a solution to 2nd order ODE (and not exponentially blowing up/decaying as 1st order ODE solutions often do). fascinating.
    wonder what happens when we do have a matrix differential equation 2nd order in time

  • @liboyan7010
    @liboyan7010 2 года назад +1

    great lecture!!!!!!

  • @sigfridsixsis3255
    @sigfridsixsis3255 Год назад

    If the eigenvectors are normalized to lenght 1, the inverse of T is simply the transpose T’, making inversion process easier

  • @GeoffryGifari
    @GeoffryGifari 2 года назад +1

    Dr. Brunton, can we tell the overall shape of the phase portrait from the shape of the matrix A in the equation xdot = Ax (where A is 2x2 matrix and x a column vector) . Does whether or not A is diagonal/anti-diagonal, whether or not the non-diagonal entries are real/imaginary/zero matter?

  • @kambizmerati1119
    @kambizmerati1119 6 месяцев назад

    Amazing.

  • @lioneloddo
    @lioneloddo 2 года назад

    There is the hairy ball theorem that guarantees that there's always at least one point on Earth where the wind isn't blowing. I'm wondering if we could also explain it with an imaginary eigenvalues approach ...

  • @mikebull9047
    @mikebull9047 2 года назад

    is it possible that the phase portrait arrows are inverted, should go clockwise not counterclockwise ? if y is the xdot state then positive y should go towards positive x. i am thinking that happened due to the blackscreen inversion maybe?

  • @shashidharreddy2959
    @shashidharreddy2959 2 года назад +1

    at 5.08 can I re write the equation as d/dt [ v x] = [-1 0; 0 1] [v x], so that the A matrix become a diagonal matrix?

    • @chensong254
      @chensong254 2 года назад +1

      The A matrix is actually [0 -1; 1 0] which is not a diagonal matrix either

  • @AymenMeziani1
    @AymenMeziani1 2 года назад

    Thank you a lot for your videos. I just think that you are making a mistake in the direction in which the system is rotating. I think it is supposed to rotate clockwise instead.

  • @zhyfn9773
    @zhyfn9773 2 года назад

    Great explanation about physical intuiation of dynamic systems! But for the model [-1,2;-2,-1], how does it map to a spring oscillator when dx/dt=-x+2v from the first line, but dv/dt=-2x-v looks physical to me.

    • @YusiiVerse
      @YusiiVerse 22 дня назад

      same question....did you figure it out?

  • @sherifffruitfly
    @sherifffruitfly 2 года назад

    to all the learners: when he effed up his own example at the end? THAT'S WHY YOU GO STEP BY STEP AND DON'T DO 20 STEPS AT ONCE :P. even when you're good at this stuff, combining steps leads to tears - go step by step folks!

  • @GeoffryGifari
    @GeoffryGifari 2 года назад +1

    huh so the imaginary part of the eigenvalues turns out to be the angular frequency

  • @GeoffryGifari
    @GeoffryGifari 2 года назад

    oh its in phase space!

  • @shawnyao7850
    @shawnyao7850 Год назад

    Thank you for sometimes doing the calculations wrong. It forced me to actually think through the math instead of idling accepting it.

  • @Jibs-HappyDesigns-990
    @Jibs-HappyDesigns-990 2 года назад

    look out! I just found my bellybutton! super duper! love his teachings!! good luck! I'm just waiting 2 see Steve, break out the
    plywood and make furniture! this might blend well in *rhino-grasshopper* . something like matlab..good luck all !!
    he makes superb use of mathematical principals! I had always used *imaginary* as fractions. where in a nvidia v100, will see this as FP16!
    symmetric!🥳