I was about to flip out and toss everything out the window because of how frustrated I was. When he put 80s as the denominator I was gonna go on a rampage. Luckily he noticed the mistake. :) you saved lives today sir.
Nope. It's an introductory lesson in a grade 11 ontario course from the first week of the course. It is taught with an assumption of zero understanding of limits, functions or first derivatives.
This literally helped me so much! I’m in integrated science 8 and I had a test tomorrow and I had no clue about tangents or slope calculations so I put it upon myself to study
For the people who didn't understand how (the rise and the run) was calculated he picked two point that are located on the tangant , for the first tangant he picked (2.5,0)_(12.5,80) and for the second tangant (7.5,0)_(13,130) and by calculating the slope of tge tangant at that moment you will eventually end up by getting the insrantaneous velocity 😊
@@patrickallen1330 In case someone else has the same question, I think you can only draw that specific tangent with that specific slope, otherwise you will end up touching more that one point of the curve.
You have a great sens of humour as well as very good teaching skills. Thank you for this explaination , it helped alot and not only to understand but to relax as well.
omg thank you sooooo muchhhhhhh! gosh it literally took me forever to understand this ugly thing! but I finally got it! thank you so much again and a big thank you for your mom and dad for creating such a great soul!!
The "kiss" points for the tangents can be anywhere, but generally people do several of them and space them evenly to produce reliable velocity-time data (especially if the data will be used to produce a velocity-time graph). Otherwise a question may simply ask you what the instantaneous velocity is at a specific time, in which case you would let your tangent "kiss" the curve at that specific time.
Choosing to draw a tangent at 6.5s was an arbitrary time choice. The purpose of the video was to show basic steps. The slope of the associated tangent is the slope that occurred at 6.5s.
Well this shows one thing ..No one was quite understanding what he was trying to say as no one pointed out the mistake at first when he wrote 80 as denominator
Why exactly did you place rise at that point @ 03:50 in the video? I'm really confused regarding that one point, because you placed the the line for the rise at that point but I don't understand if that is a specific point we should place it for or just a random point.
How do you know how far you should extend the line when finding the rise over run? The left side of the tangent line stops at the x intercept but how far should the right side go?
Because the tangent only touches one point on the graph, that means that it has the value of the velocity at that exact instant we make it touch; remember, the slope of a line on a position-time graph equals velocity.
One of the students was joking around about how 80/10 equals 7. He was telling the student to get lost as a joke lol. If that's what you were confused about.
8 years later and this is still extremely helpful
make'm 9
@@Smeme Now its 10
This is more of dating advice than physics.
He’s just going through it
exactly lmaoooo!!!!
I was about to flip out and toss everything out the window because of how frustrated I was. When he put 80s as the denominator I was gonna go on a rampage. Luckily he noticed the mistake. :) you saved lives today sir.
Joe Soria I FEEL YOUUUU
Joe Soria same that's y I checked the comments
Love ur method of teaching, you go through the whole step and that helps sooooosos much
I wish my physics teacher taught like you
I finally understood the concept after 4 people explained the tangent line works to me. 3 students and 1 teacher. GL on your education people.
Nope. It's an introductory lesson in a grade 11 ontario course from the first week of the course. It is taught with an assumption of zero understanding of limits, functions or first derivatives.
I've been through a couple of videos related to this topic....Yours is the best!!
This literally helped me so much! I’m in integrated science 8 and I had a test tomorrow and I had no clue about tangents or slope calculations so I put it upon myself to study
For the people who didn't understand how (the rise and the run) was calculated he picked two point that are located on the tangant , for the first tangant he picked (2.5,0)_(12.5,80) and for the second tangant (7.5,0)_(13,130) and by calculating the slope of tge tangant at that moment you will eventually end up by getting the insrantaneous velocity 😊
but how do you know what slope u should give your tangent, like it could have a slope of 90 or 45 and still touch only one point of the line
@@patrickallen1330 In case someone else has the same question, I think you can only draw that specific tangent with that specific slope, otherwise you will end up touching more that one point of the curve.
thank you so much!basically guyz you are trying to create a TRIANGLE/rise over run UNDER THE CURVE! all the best
This has helped me SO much in my first class of College Physics I.. Thank you so so much!!!
this was great! i love your attitude and approach towards teaching. really helpful
You have a great sens of humour as well as very good teaching skills. Thank you for this explaination , it helped alot and not only to understand but to relax as well.
Superb!!!.give this guy a medal!!
omg thank you sooooo muchhhhhhh! gosh it literally took me forever to understand this ugly thing! but I finally got it! thank you so much again and a big thank you for your mom and dad for creating such a great soul!!
The "kiss" points for the tangents can be anywhere, but generally people do several of them and space them evenly to produce reliable velocity-time data (especially if the data will be used to produce a velocity-time graph). Otherwise a question may simply ask you what the instantaneous velocity is at a specific time, in which case you would let your tangent "kiss" the curve at that specific time.
excellent tutorial, eh! THANK YOU!
Thankyouuuuuu. Ihave a test later and im still confused on this, but luckily i found it on yt
This guy can hook anyone up using physics😂😂
thank you very much i've been searching for that since yesterday.
very intriguing video. Make sure to include the direction at the end of velocity and acceleration value!! you'll lose marks on your tests.
How has no one mentioned how this guy sounds so suspiciously just like Kermit the Frog???!!!
Thank you so much for this. Saved my arse in a GCSE phys test.
this helped me more than my physics teacher ! thank you.
Awhhh you saved my live! Thank you for this videooooooo :DD
sir, . your lecture helped me a lot in clearing my doubts. thank you very very very much sir.
Choosing to draw a tangent at 6.5s was an arbitrary time choice. The purpose of the video was to show basic steps. The slope of the associated tangent is the slope that occurred at 6.5s.
youre so good at teaching omg thank you so much !!
when you choose the point can they be anywhere? Or is there a certain place you must take them from or will a question ask you?
thaikn you really learnt o alot of stuff from this video!!!! *thumbs up*
Thank you sir!
#best physics teacher ever!
YOU ARE AN AMAZING TEACHER GOD BLESS U ! AND CANADA XD
Well this shows one thing ..No one was quite understanding what he was trying to say as no one pointed out the mistake at first when he wrote 80 as denominator
Funky M Not really. They probs just doubted themselves
THANKS! I understand!! Man, I can't believe it was this easy and I failed my test on this. Gonna ace this part of the exam!
really good video
If you have the function you can calculate the derivative using the f(t1+dt)-f(t1)/dt1 formula right? Because we use that to find the slope
respect for my homie
3:12 you wont get a second date otherwise
okay mr k nearly 150k views I see you
too amazing
This helped a lot, thank you.
Thank you!
*I still didn't get why he chose 12.5s as a rise for the second case.* Can someone explain me?
Tqsm sir it was so useful.. saved my day
you sir, are awesome!
Great job
Kevin is a pretty cool dude.
Why exactly did you place rise at that point @ 03:50 in the video? I'm really confused regarding that one point, because you placed the the line for the rise at that point but I don't understand if that is a specific point we should place it for or just a random point.
Help
Notice this one
I have the same question
Big brains out here
this is awesome. thank you!!
Any app for it so we found out that uncertainty with certainty and curve equations for curve at random 🤣🤣🤣🤣
Thanks so much!!! This was great help!
Thank you so much- this really helped!
Why first rise is 12.5 why not 13 what is the reason
excellent explanation, better than my physics teacher lol
thank you, this was very helpful :)
Kevin i like you haha
awesome....!!!! thanks a lotttt....
Nobody:
Physics Teacher: Just to be lucky, if you believe in that sort of thing.
Determinism at its finest.
13-6.5 how it came sir
From where you are friend
NELSON LORDS!!!
How do you know how far you should extend the line when finding the rise over run? The left side of the tangent line stops at the x intercept but how far should the right side go?
Jasmeet Rainal doesn't matter, it can be as big as you want, the slope will be the same.
Jasmeet Rainal hello sir slope is same regardless, just do what is easiest to calculate thanks
How do i know he is canadian without looking at the picture? he said "eh?
"
thank you sir
Why didn’t you go to the end of the line
This teacher sounds just like Corey Feldman! LOL
Nice
lol 2020 12 years later
Jordan Peterson teaches physics too woah
you shluld to explain why you choosen 80 I did not understand that until now
Why does he sound like kermit
I can't laughing when time gone wrong
thumbs up!
excuse me, how we exactly know @13s, d=130m
look at the graph
You helped me a alot man.
I have a girlfriend now.
why the slope of the tangent is the instaneous velocity?
Because the tangent only touches one point on the graph, that means that it has the value of the velocity at that exact instant we make it touch; remember, the slope of a line on a position-time graph equals velocity.
Please come to my school
find oat
This isn't Ap right?
3:13 I think the tangent line will differ depending on how you drew it am I right?
correct I got 23.04 m/s instead of his 23.64 m/s
I am class 9 from India
go canada
Hella worked
5:38 get lost 🤔
One of the students was joking around about how 80/10 equals 7. He was telling the student to get lost as a joke lol. If that's what you were confused about.
Your pum pum pum was distracting though otherwise it was a great video
Hey dude! Shut up! That pum pum pum was awesome.
please cut out all the time-wasting talking
not as good as mr. Jones
Thank you!