Introduction to Jordan Canonical Form

[@spiderjerusalem4009]

oh my god. That split after multiplication is what most lecture videos/books miss to elucidate. Everything makes sense now, thank you

[@spiderjerusalem4009]

ye, most math books are outlined such as that unfortunately. It's been running through in the culture, since bourbarki or god knows how long. I'd heavily suggest learning based-proof lin alg(notably axler's lin alg done right) subsequent to whatever this horrid boring computational one.

[@jpbstamaria]

Thank you for an insightful lecture...Not only helpful to students, but also to those who teach this subject.

[@RobertoCarlos-wk3jh]

OMG just find this video and helped me so much. Greatings from México.

[@thatoneguy9287]

Your vid came in clutch 😂😂😂😂, my algebra 2 final is tomorrow and i didn't understand this topic

[@jasonbroadway8027]

This video comes in handy as a refresher. I did not understand it upon first viewing. However, I commend you for working concrete examples!

[@geethamonnappa4645]

You explained step by step.thank you so much Sir.please give illustration if k=3,4

[@shizafatima1272]

You explained it in a very good manner...

[@SLstudio1998]

Why don’t you get the eigen vector from lamda=2 to the chain

[@mikhailshkaralevich574]

Thank you very much for your video. It made lots of sense to me!

[@aris.konstantinidis]

Thank you so much for this thorough explanation!

[@MathematicsMadeSimple1]

Great presentation here.

[@curtisJ-gl2gu]

Love U bro!!! it's really heplful

[@manu40729]

thank you for explaining it fully

[@nahuu4481]

Great!!! But , Eigenvektor for lamba= 4 is (0,-2,1)

[@daniel_an]

Any nonzero multiple of an eigenvector is again an eigenvector. Your vector is -1 times mine. So they are both eigenvectors.

[@nahuu4481]

@@daniel_an Oh yess! Correct Sir. Sorry

[@shilinyou6632]

God, it explains better than my prof lol

[@yb801]

you explained well, thanks

[@jzjMacwolfz]

thank you very much!!!! you are amazing!

[@RaushanKumar-y1i9k]

21:13 directly you written jordan form from where you got didnt explain

[@davidbarta9512]

I think you can do it better this way: A=P*J*P^(-1), thus P^(-1)*A*P=J. So you know A, calculate P, calculate P^(-1) from it and you have J. Makes sense?

[@azeemgadkari4660]

well explained thank u ..

[@pradyutmaji1704]

Thank you sir

[@uzivatel123]

thank you

[@thenewdimension9832]

Wow 🥰🥰🥰🥰🥰🥰