Another method (notation: /# means square root of #, and _ _ around an expression is just bringing attention to the expression, or "underlining" it): (/3+/2) / (/5-/3)= multiply by (/3-/2) / (/3-/2) (/3+/2)(/3-/2) / [(/5-/3)(/3-/2)]= multiply out the conjugates (3-2) / [(/5-/3)(/3-/2)]= simplify 1 / [(/5-/3)(/3-/2)]= multiply the denominator by (/5+/3) / (/5+/3) which creates a complex fraction for now 1 / [(/5+/3)(/5-/3)(/3-/2) / (/5+/3)]= multiply out the conjugates 1 / [(5-3)(/3-/2) / (/5+/3)]= simplify 1 / [2 * (/3-/2) / (/5+/3)]= notice that the underlined expression... 1 / [2 * _(/3-/2) / (/5+/3)_]= ...turns out to be the reciprocal of x; substitute 1 / [(2 * _(1/x)_]= simplify 1 / [2/x]= "reciprocate" if that's a word x/2
Solved this very similarly. I used the reciprocal of the first expression, it's equal to 1/x. Then I multiplied both sides by y, so 1/2 = y/x and y = x/2.
@@Jha-s-kitchen omg! Thank you so much I solved it some hours ago and got the same answer as yours But solution was given as 17/3(only numerical answer not full solution) So I was confused whether I had made any mistake Thanks for clearing my doughts!
just multiply and divide the equation of x by the conjugate of the numerator and do the same for the denominator gives x = 2.(V(3) + (V(2))/(V(5)-V(3)) therefore: (V(3) + (V(2))/(V(5)-V(3)) = x/2
I just rationalised the denominators of both fractions and compared the two. The answer is X/2
I did the same
traditionally everyone wud hav done this..even this approach clicked in my mind too..as that is what we all have been taught in our high school
Another method (notation: /# means square root of #, and _ _ around an expression is just bringing attention to the expression, or "underlining" it):
(/3+/2) / (/5-/3)= multiply by (/3-/2) / (/3-/2)
(/3+/2)(/3-/2) / [(/5-/3)(/3-/2)]= multiply out the conjugates
(3-2) / [(/5-/3)(/3-/2)]= simplify
1 / [(/5-/3)(/3-/2)]= multiply the denominator by (/5+/3) / (/5+/3) which creates a complex fraction for now
1 / [(/5+/3)(/5-/3)(/3-/2) / (/5+/3)]= multiply out the conjugates
1 / [(5-3)(/3-/2) / (/5+/3)]= simplify
1 / [2 * (/3-/2) / (/5+/3)]= notice that the underlined expression...
1 / [2 * _(/3-/2) / (/5+/3)_]= ...turns out to be the reciprocal of x; substitute
1 / [(2 * _(1/x)_]= simplify
1 / [2/x]= "reciprocate" if that's a word
x/2
Solved this very similarly. I used the reciprocal of the first expression, it's equal to 1/x. Then I multiplied both sides by y, so 1/2 = y/x and y = x/2.
ME TOO BRO!
Thank you very much sir SyberMath! Your'e a very good teacher.
Np. Thank you!!! 💖
@@SyberMath 😊😊🙏🙏
Wow I'm shocked at how simple this is and I just didn't know!Keep enlightening
I 🧡 when the answer is so simple!
I have got x/2 by double rationalization
Here is a problem suggestion
{(log(2x-5))/(log(x^2-8)}=(1/2)
solve for x
x=11/3 or x=3, but x=3 cause denominator to be 0,
So x = 11/3
@@Jha-s-kitchen omg!
Thank you so much
I solved it some hours ago and got the same answer as yours
But solution was given as 17/3(only numerical answer not full solution)
So I was confused whether I had made any mistake
Thanks for clearing my doughts!
Yeah I got 11/3 as well. 17/3 comes from having a typo of log(x^2+8) in the denominator.
@@Green_Eclipse oh thank you too for pointing that out!
Genial, Merci
just multiply and divide the equation of x by the conjugate of the numerator and do the same for the denominator gives
x = 2.(V(3) + (V(2))/(V(5)-V(3)) therefore: (V(3) + (V(2))/(V(5)-V(3)) = x/2
Does not worth the electricity consumed by his tablet.
X/2.
Yup I also got x/2 😁
Good-nice 🙂
x/2.
Must be the easiest of yours!
x/2
👍
You explain like you know why?
x/2
x/2
x/2
x/2