Hi Shivansh....Well Thanks for appreciating my work... All the best in life And if you wanna support my channel visit this link: manaspatnaik.in/?page_id=401 Small contributions can make a Big Difference
hexagonal pyramid of base side 40 mm and axis length 55 mm is resting on H.P. with one of its base corners. The two adjacent base edges containing the corner are equally inclined to H.P. the axis is inclined at 35o to V.P. and parallel to H.P. draw its projections.
A pentagonal pyramid, 50 mm side of base and 80 mm height, rests on one of its corner of the base on the H.R.P. with axis making an angle of 30° to the HP. The side of the base, opposite to the corner on the H.R.P., is parallel to the VP. Draw the projection of pyramid
Thanks for appreciating my work Raushan... All the best man... And do create an awareness amongst your friends and classmates to subscribe to this channel so that al can benefit...
Hi bro the question is : a hexagonal pyramid of side 30 mm at height 65 mm is resting on its base is in Hp.one of its base lights is parallel to VP it is cut by the cutting plane which is parallel to HP and perpendicular to VP and passing at a height of 45 mm from its bottom and rather development of the surface.
Very very thanks for manas patnaik i followed ur vedios on solids planes lines etc all topics and i cleared my engineering drawing subject which i failed for 4 times this time i clear the exam thanks for ur vedios
Thanks for appreciating brother...... All the best...And do encourage your classmates to subscribe to this channel so that all can learn Engineering Drawing in the best possible way.....
hexagonal pyramid of base edge 30mm and axis height 70 mm has one of its triangular faces, making an angle of 450 to V.P. Draw its projections when the base edge o f the triangular face is inclined to 500 to the H.P and parallel to V.P.
Are you a human being or god... Your welcome teaching is like a god level... Every eg teacher should beg you.... No one got knowledge like you and your teaching like even a kindergarten can understand engineering graphics concepts clearly... Thanking from bottom of my heart...
hexagonal pyramid is resting on a side of its base on the ground having its axis inclined at 45° to the H.P. and the vertical plane containing that axis is inclined at 30° to the V.P. Draw its projections. Base 30 mm side; height 60 mm.
Thanks Bharat Do watch all the content on drawing and mechanics..... And do tell your friends about this channel so that they can also benefit..... All the best
Thank you so much sir for uploading such videos👌👌 You teach us in the best possible way.I understand every concept of ED with the help of you only.I like you so much sir..........plz help us in the same way forever.Thank you so much sir..........😘😘😘
6} a hexagonal piramid side of base 25mm annd axis 50mm long rest with 1 of the adge of the space of hp and is axis is incliend at 30' to hp and parpenducular to vp draw the projection
On Projection of Solids: 3. Draw projections of the hexagonal pyramid you made, with base on HP, and a side of the base parallel to and 25 mm in front of VP. 1:321:321:321:321:321:321:321:32
thanks sir you are the best teacher. sir me and my all friends sees your video which are very helpful for stdy sir pls upload more videos of different kinds
Q5. A pentagonal pyramid, edge of base 30 mm and height 50 mm, stands on its base on the HP with an edge of base parallel to the VP. A section plane cuts the pyramid at point 30 mm along the axis and above the base and makes an angle of 50_ with the axis. Draw the development of the truncated pyramid.
+LOKESH KMS Hi lokesh.... Thanks for appreciating the content.... All the best and do let your friends know about this channel so that they can also benefit...
Sir can you please upload some more and some tricky or tough questions becoz they are frequently asked in exams .if you do so dont show how to draw becoz we have learned it in previous lectures just question with answer and how that answer came.so that in a single video no of questions will be covered which will be helpful.thank you
Thanks for appreciating my work Saransh... Do watch more videos on projection of solids... All the best man And do encourage and recommend this channel to your friends...
Sir can we take angle from opposite side?as the protractor have 180° it shows angle from both the sides,from right side and also from left side. Example:I have to take 30° degrees then there are 30° on left side and as well as on right side,then which 30° I have to choose? Hope u understand my question
Sir can we take other type of hexagon in this problem?could u plz explain which type of hexagon can take if hexagonal pyramid is resting on hp on one of its base corners
Sir pls explain projection of solid..final top and front I will find but inclination should not be understand..because variation from other questions..one question is 30° inclined to HP but using different types of inclination to HP
A cube of 35mm long edge is resting on the H.P on one it's face with a vertical face inclined at 30* to the v.p it is cut a section plane inclined at 60* to the v.p and perpendicular to the h.p so that face which makes 60* angle with the v.p is cut in two equal holes.sir ise bhi bna ke btaye nhi ban rha f
Sir please ek video es question pe bhi banado a hexagonal Pyramid base 25mm side and axis 55mm long has a corner of its base in hp its axis makes an angel of 30° with hp and parallel to vp draw its projections . Please 🥺
Sir when we draw the projections how can we say which lines to be imaginary lines in projections I mean in axis inclined to 30degrees the one which is below the reference line how can we say the imaginary lines in it and where do we get imaginary lines how can we say the imagined lines sir in this diagram Sir please reply to this comment
Hi Shashank…Thanks for appreciating my work…and all the best for your examI am sure this channel is helping you learn…You can support my channel by donating and do watch this video: ruclips.net/video/WfyUEhxhjZUH/видео.htmlave a nice day.
Brilliantly explained. This is how our professors shoul be.
Even my teacher recommend your videos for reference. Great Work
Hi Shivansh....Well Thanks for appreciating my work...
All the best in life
And if you wanna support my channel visit this link: manaspatnaik.in/?page_id=401
Small contributions can make a Big Difference
My teacher should learn from you . excellenct of excellence understanding
🤣🤣😛
Ur fantastic i grabbed 75% of knowledge of caed from ur videos which i cannot in college
Excellent brother you've nailed it
Finally I understood
Your teaching skills are marvelous
Thank you bro
hexagonal pyramid of base side 40 mm and axis length 55 mm is resting on H.P.
with one of its base corners. The two adjacent base edges containing the corner are
equally inclined to H.P. the axis is inclined at 35o to V.P. and parallel to H.P. draw its
projections.
Super. Now I learned projection of solid better than my college staff thank you.
Engineering Drawing | Engineering Graphics |: ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS
A pentagonal pyramid, 50 mm side of base and 80 mm height, rests on one of its corner of the base on the H.R.P. with axis making an angle of 30° to the HP. The side of the base, opposite to the corner on the H.R.P., is parallel to the VP. Draw the projection of pyramid
Legend for legendary department of Engg graphics superb sir 👍👍👍🙏
thank u so much sir for loading these type of videos bcoz this is important for better understanding
Thanks for appreciating my work Raushan...
All the best man...
And do create an awareness amongst your friends and classmates to subscribe to this channel so that al can benefit...
Hi bro the question is : a hexagonal pyramid of side 30 mm at height 65 mm is resting on its base is in Hp.one of its base lights is parallel to VP it is cut by the cutting plane which is parallel to HP and perpendicular to VP and passing at a height of 45 mm from its bottom and rather development of the surface.
Solve this question please
Very very thanks for manas patnaik i followed ur vedios on solids planes lines etc all topics and i cleared my engineering drawing subject which i failed for 4 times this time i clear the exam thanks for ur vedios
Gowtham....What can i say!!!
All the best in life
Go ahead with confidence...
thank u alot sir dis video solved my doubts ! about placement of hexagon !
Thanks for appreciating brother......
All the best...And do encourage your classmates to subscribe to this channel so that all can learn Engineering Drawing in the best possible way.....
hexagonal pyramid of base edge 30mm and axis height 70 mm has one of its triangular faces, making an angle of 450 to V.P. Draw its projections when the base edge o f the triangular face is inclined to 500 to the H.P and parallel to V.P.
Are you a human being or god... Your welcome teaching is like a god level... Every eg teacher should beg you.... No one got knowledge like you and your teaching like even a kindergarten can understand engineering graphics concepts clearly... Thanking from bottom of my heart...
Really helped mee a day before my exam can't thk u enough in words
The best explanation ever I have seen . Thank you sir 😊
hexagonal pyramid is resting on a side of its base on the ground having its axis inclined
at 45° to the H.P. and the vertical plane containing that axis is inclined at 30° to the V.P.
Draw its projections. Base 30 mm side; height 60 mm.
Really something like learning from a scholar of drawing!!!!!!!!!!!!!!
Sir really it's very very easy to understand......u explained it in a simple way and also catchy
Nice sir its too easy for understand..
Thanks Bharat
Do watch all the content on drawing and mechanics.....
And do tell your friends about this channel so that they can also benefit.....
All the best
Thank you so much sir for uploading such videos👌👌
You teach us in the best possible way.I understand every concept of ED with the help of you only.I like you so much sir..........plz help us in the same way forever.Thank you so much sir..........😘😘😘
Thanks Tahreem.......
All the best in life
Sir your teaching methodology is completely different and superb
Thanks Madhukar...
It's helps me a lot for my Tmrw paper
Me too sir
same lol
6} a hexagonal piramid side of base 25mm annd axis 50mm long rest with 1 of the adge of the space of hp and is axis is incliend at 30' to hp and parpenducular to vp draw the projection
On Projection of Solids:
3. Draw projections of the hexagonal pyramid you made, with base on HP, and a side of the base
parallel to and 25 mm in front of VP. 1:32 1:32 1:32 1:32 1:32 1:32 1:32 1:32
Sir!!!!!!! U've made my day xcllnt stuff thank you sir
Hi Jony....
Thabks for appreciating man......
A great learning from you sir a best way you choossed to teach us thank you sir from the core of my 💞 heart
Keep learning
And all the best
Thanks a lot lot sir i appreciate with you sir
thanks sir you are the best teacher.
sir me and my all friends sees your video which are very helpful for stdy
sir pls upload more videos of different kinds
sure shubham i will....GOD BLess u...
Amazing video.You made everything crystal-clear!!!!
Q5. A pentagonal pyramid, edge of base 30 mm and height 50 mm, stands on its base on the
HP with an edge of base parallel to the VP. A section plane cuts the pyramid at point 30
mm along the axis and above the base and makes an angle of 50_ with the axis. Draw the
development of the truncated pyramid.
Thanks a lot sir u are really great , this type of explanation we really need in our education system by which we understand it by real condition.
Fantastic sir...Keep posting many advanced problems sir
+LOKESH KMS
Hi lokesh....
Thanks for appreciating the content....
All the best and do let your friends know about this channel so that they can also benefit...
Sir can you pls post projection of solid without inclinations..Thanks in advance sir
Video is really helpful.... waiting for more and more uploads...of different types....your lectures are very far better than my sir
Hmm yes
Sir,your video is very helpful for me
Sir can you please upload some more and some tricky or tough questions becoz they are frequently asked in exams .if you do so dont show how to draw becoz we have learned it in previous lectures just question with answer and how that answer came.so that in a single video no of questions will be covered which will be helpful.thank you
great content sir....very helpful
Thanks for appreciating my work Saransh...
Do watch more videos on projection of solids...
All the best man
And do encourage and recommend this channel to your friends...
Thank you sir!!
You are doing a such a great job
I can't explain how thanks to you for these videos
What a teacher 👍 Thanks sir
Sir super ..it help me for my examinations . thank a lot
Sir can we take angle from opposite side?as the protractor have 180° it shows angle from both the sides,from right side and also from left side.
Example:I have to take 30° degrees then there are 30° on left side and as well as on right side,then which 30° I have to choose?
Hope u understand my question
your all the videos are really awesome
I wish u can be my teacher !pls do more videos like this .
Thank you sir !
sir in dis lecture u taech with a xcitmnt ....its rly gd ...anywy its rly nice...i lyk ur spokn styl
Thanks goutam and all the best
My dear manas you helped me a lot.
legendry eg teacher
Great video.
Thank u so much
I understood it very well
Excellent explanation 😊
Great explanation
Very nice sir
Engineering Drawing | Engineering Graphics |: ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS
@@ManasPatnaikofficial Thank you sir , i have also informed my friends about your channel . Thumbs up from me for quality content you have provided.
your videos are really helpful sir thankyou.
nice sir this method is easy to understand problems
Thank you so much sir, It is very easy to understand this type of questions
Great work sir
From on words I wanted to follow ur videos because I was failed in graphic because don't know the basics properly can u suggest me sir
Nice one bro
You cleared my concept easily
Thanks!
Engineering Drawing | Engineering Graphics |: ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS
Sir Tell me how to draw " projections of cylinder base 40mm diameter and axis is 50mm long , resting on Hp and VP with their bases.".
In previous videos u didn't said ...when axis is inclined to ground (90-teta) y??
It is so helpful to me to understand it by easily way🙂🙂
We can make directly if if it is given 60 degree then we can make or not without doing minus from 90 minus theta
Sir we are understanding but how can identify the project to draw the given question
Sir , why you have taken 30 degree toward left side , why not in right side to HP
Thanks sir. You have done something great
Sir,can we make the second step with c',d' on the HP? Then the axis also makes an angle of 30° with HP.
Really awesome please teach us by solid edge V19 application
Tq very much sir i learn alot from u sir
I don't understand when we should do 90deg -30deg n when we shouldn't
Fabulous sir
Excellent explaination 🤗
Sir can we take other type of hexagon in this problem?could u plz explain which type of hexagon can take if hexagonal pyramid is resting on hp on one of its base corners
Thank you very much sir. Really the explanation was 👌
If the pyramid is in front view and it is said that it should be nearer to observer then what we should do?
If the axis is inclined to hp,,then we can take 30° from either of the sides right ?...
I like it sir😘 but sound quality thodi kharab h 😔will you please improve it for next videos 🙏🙏🙏
axis inclined at 30° to v.p means..why u have written in condition inclined 30° to h.p..sir..please answer me sir
sir,
can we draw 2nd step(F.V) to opposite side??(FROM LEFT TO RIGHT)
When the axis is inclined to hp
Can we take axis line another way i.e, perpendicular to the axis which you have taken
Thank you very much for the explanation, it helped alot.
It was very to understand, Thanks sir 🙏
Sir how will understand the base side is parallel or perpendicular to x-y plane? Sir plz give replay
Sir pls explain projection of solid..final top and front I will find but inclination should not be understand..because variation from other questions..one question is 30° inclined to HP but using different types of inclination to HP
Add perspective view & isometric projection of simple solids.
Sure ....i will
A cube of 35mm long edge is resting on the H.P on one it's face with a vertical face inclined at 30* to the v.p it is cut a section plane inclined at 60* to the v.p and perpendicular to the h.p so that face which makes 60* angle with the v.p is cut in two equal holes.sir ise bhi bna ke btaye nhi ban rha f
Thanks u save my semester.
Sir please ek video es question pe bhi banado a hexagonal Pyramid base 25mm side and axis 55mm long has a corner of its base in hp its axis makes an angel of 30° with hp and parallel to vp draw its projections . Please 🥺
Thanks sir college is a best teaching you solid plens
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Sir jb axis ground se inclind ho rahi hai top view to upper banega (3rd Angle projection me)
Best video..all my doubts were cleared...
Enjoy.....all the best
U cleared all my doubts...
Thank you sir
Engineering Drawing | Engineering Graphics |: ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS
Sir why can't we make edge "b e" with hp 60 degrees in clockwise please explain it sir??
Can we tilt the object either side in second stage??
Please reply
Wonderful sir
The trick is very much useful..
+Viswa Spartan
Enjoy.....
Sir, why this hexagonal pyramid is a two step process.
Sir when we draw the projections how can we say which lines to be imaginary lines in projections I mean in axis inclined to 30degrees the one which is below the reference line how can we say the imaginary lines in it and where do we get imaginary lines how can we say the imagined lines sir in this diagram
Sir please reply to this comment
An edge of the base on the ground .. where will it be used
tq sir I learn something to u
tomorrow I have drawings exam 😃
Hi Shashank…Thanks for appreciating my work…and all the best for your examI am sure this channel is helping you learn…You can support my channel by donating and do watch this video: ruclips.net/video/WfyUEhxhjZUH/видео.htmlave a nice day.
Tq so much sir...
It helps me a lot.....