Discrete Mathematics | MA3354 | Unit 2 | Combinatorics | Principle of Inclusion & Exclusion in Tamil

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  • Опубликовано: 19 дек 2024

Комментарии • 7

  • @Parthiban.mParthi-q2r
    @Parthiban.mParthi-q2r 10 месяцев назад +1

    Thankyou mam❤

  • @rameshselvaraj1341
    @rameshselvaraj1341 10 месяцев назад +3

    Mam ques la verum not divisible by 2 nor 3 nor 5 dha irundhadhunaalum adha divisible by 7 nu namba eduthukunu adhuku problem pota ok la mam?

  • @arunsuresh8547
    @arunsuresh8547 Год назад +2

    Please upload the 3rd ,4th ,5th unit fast mam .. have you uploaded mam ?

  • @Monk3y-D-Luffx
    @Monk3y-D-Luffx 10 месяцев назад +5

    4) How many integers between 1 to 100 that are
    i) not divisible by 7,11 or 13
    Ans :
    |AuBuC| = |A| + |B| + |C| - |A^B| - |B^C| - |A^C| + |A^B^C|
    |AuBuC| = 14+9+7-1-1-0+0 = 28
    Total - |AuBuC|
    100 - 28 = 72
    ii) divisible by 3 not 7
    Ans :
    |AuB| = |A| - |A^B|
    |AuB| = 33 - 4 = 29
    |AuB| = 29
    (^ AND)

  • @Yuvi.R.yuvanesh
    @Yuvi.R.yuvanesh 10 месяцев назад +2

    Complete

  • @Monk3y-D-Luffx
    @Monk3y-D-Luffx 10 месяцев назад +2

    3) Determine the number of postive integers n 1 < n < 2000, That are not divisible by 2,3 or 5 but are divisible by 7
    Ans :
    = |D|-|A^D|-|B^D|-|C^D|+|A^B^D|+|B^C^D|+|C^D^A|-|A^B^C^D|
    = 285-142-95-57+47+19+28-9
    = 76
    ( ^ AND )