Hi Ayisha - no, numbers change, although most examples tend to use 'easier' numbers. I'll post a video with some harder questions and let you know when done. All best S :-)
I have this equation that I would like you to help me with, if possible. Parking Station A: charges $3.20 (first hour) and $2.00 (afterwards) Parking Station B: charges $6.00 (first hour) and $1.20 (afterwards) Calculate the times of parking which would result in the cost being the same at both parking stations. I hope that you can help, Thanks and you are great
Thank you SO MUCH Mr. Simon, I didn't understand what my secondary teacher was explaining. Again, Thank you. Everyone, I hope all of you guys are free from the covid - 19 virus. Stay Home, Stay Safe, Be Safe.
Hi - this is really the easiest way. You could solve by plotting a graph but it takes a while and isn't always very accurate. Keep practicing and good luck!
Just so you know, at 7:44, you wrote x=4 instead of x=6. I just wanted to point it out. Anyway, the video was very useful! Thank you! I just solved more than half of my math homework thanks to this video!
Could you help me with a question? It asks to consider the equations: (k-3)x+5y=-2 2x-3y=4 where k is a real constant for which I have to find the unique solution. Thanks in advance!
Hi - you need to plot both lines and see where they cross. It's OK if you have an idea where they are likely to be on a graph... but it can take a long time to get that information. I'll post a video on this and let you know. Simultaneous solving by using algebra is better and easier. All best S
Well, I don't know about life, but this was definitely needed in my math homework tonight, and thanks to you I can get it done. Thanks, friend! Good vid :)
Hi - there isn’t really a formula you can use for simultaneous equations. This topic is really just so you have an awareness that straight lines can cross on a graph. Best S
Hi - it's really all about trying to eliminate one of the terms, so you can work out the other. Here's a playlist with some other examples: ruclips.net/p/PLPglScc3TJ-PkkPq8fL81mx0-eC7WzmUi. All best S :-)
Hi 6 + 4y = 14 I need to get y term on one side, and everything else on the other. The 6 needs to move so I subtract 6 from both sides: 4y = 14 - 6 4y = 8 y = 2 I hope this is OK. Here's a playlist on linear equations that might help: ruclips.net/p/PLPglScc3TJ-Mvi9Gk651-7y-bUJKC2y4H. All best S :-)
+lewb Dangos - Hi - I'll arrange a video on this one and will let you know when done. In the meantime here's a link to a similar question: ruclips.net/video/z-pUHrtVT4c/видео.html. All best S :-)
+lewb Dangos - Hi - here is the video for 7x + 5y = 20 and minus8x - 3y = 12 and hope it helps. ruclips.net/video/E4xxyDSOn0w/видео.html . All best S :-)
Hi Shoot Fresh Mine as you're working simultaneously you can change the order: 7u+v=29 3u+v=17 Then takeaway the bottom equation: 4u = 12 Divide by 4 both sides: u = 3 If you then put u=3 into any of the equations you can work out v, so: 7(3) + v = 29 21 + v = 29 Take 21 from both sides v = 8 I hope this all helps :-)
im trying understand something quadratic equations no 1 x sqaured minus x minus 56 =0 changed from minus b at start to positive minus minus is a plus comes out right as 8 and minus 7 next question 3x sqaured + 7x minus 13 =0 but with this one if you change the minus at start to plus answers in back of book are different to what it comes up with any advice.
Hi stephen barker .. it's quite difficult to read through this but (I think): xsquared - x - 56 = 0 factorises to (x - 8)(x + 7) = 0 So, x = +8 and x = - 7 ... this is because x - 8 = 0 and x + 7 = 0 The next one 3xsquared + 7x - 13 = 0, is a little difficult to factorise and you need to use the quadratic formula. Here's a video with this particular question ruclips.net/video/lz5j4T49HJk/видео.html . All best S
Hi - This video is all about elimination. Here's an example of substitution and hope it helps: ruclips.net/video/_qo7x80s5HI/видео.html. All best S :-)
+Bad News Bullet - Hi ... with these you'd need to add to get rid of the y's (as +y + -y = 0) 2x + y = 4 x - y = -1 (Adding them) 3x = 3 Divide by 3 x = 1 Put x = 1 back into the first equation: 2(1) + y = 4 2 + y = 4 Minus 2 both sides y = 2 So x = 1, y = 2 You can also check this by putting into equation 2: x - y = -1 1 - 2 = -1 I hope that's all OK? Best S :-)
Hi Hamza Roblox .. as you're working simultaneously you can put the equations the other way around. So: 8p+5q=73 3p+5q=43 Then take the bottom equation away from the top 5p=30 Divide through by 5 p=6 Put the value of p back into any of the equations 8(6)+5q=73 48+5q=73 Take 48 from both sides 5q=25 Divide through by 5 q=5 So, p=6, q=5 I hope this is OK. All best S
hey you have to multiply 1 or both equations t make X or Y the same if i multiply equation 2 by 2 i get 2x - 2y = 38 so your equations are 3x+2y= 18 and 4x-2y = 38 ADD to eliminate so 4x + 3x = 7x 2y + minus 2y cancels out and 38 + 18 = 56 so 7x = 56 divide both sides by 7 X = 8 sub back in any equation 3(8)+ 2y = 18 24 + 2y = 18 subtract 24 from both sides 2y = minus 6 divide both sides by 2 Y = minus 3 solutions are X = 8 and Y = minus 3
Though all of this is true some of it is unnecessary. Keeping equals signs in a vertical line is essential for clear manipulation of decimals but, since x and y are different with no decimal places, it doesn't matter. Also, I chose the 2nd equation since it ends up with smaller numbers to compare viz: 3x + 12y = 42 then subtract 3x + y = 20 to get 11y = 22, much easier to see, in my opinion. Stop asking, "OK?" at the end of each sentence - students think you are asking a question. Well done, though, Simon.
+Cydney Lozano - Hi - y = x - 1 y = -x + 11 Because I've got a positive x and a negative x I can add them together to 'cancel them out.' 2y = 10 y = 5 Substitute y = 5 into equation 1 y = x - 1 5 = x - 1 x = 6 So, x = 6 and y = 5 for both equations. Hope this is OK and all best S :-)
Hi stephen barker you need to make sure that all your y co-ordinates are 3. If you plot a line to join (1,3), (5,3), (8,3) then it'll be y=3. All best S
you see i have this equation tht i dont get may u help me? see i have {5x+2y=19 ... 1 {2x+3y=12 ...2 but i dont get how you r suppose to multiple this by 3 for the top and then u need to multiple by 2 for the second part
Hi yukicross6767 OK, as you said, multiply the top by 3 ... this will give you 6y so: 15x + 6y = 57 Multiply the second equation by 2 ... this will also give you 6y, so: 4x + 6y = 24 Take one away from the other: 11x = 33 These type of questions usually work out OK - if you start to get lots of decimals of odd fractions, it might be a good idea to check your working. If I divide both sides by 11 I get: x = 3 Use x = 3 in either the first or second equation. I'll use the first: 5x + 2y = 19 When x = 3 15 + 2y = 19 take 15 from both sides: 2y = 4 Divide by 2 y = 2 I hope this helps and all best with your studies. S :-)
Hi - both of these equations represent straight lines and we're working out where they cross. By taking one away from the other you can get rid of one of the terms, and work out the other. Here's a playlist with some more examples and hope it helps: ruclips.net/p/PLPglScc3TJ-PkkPq8fL81mx0-eC7WzmUi. All best S :-)
Hi - I've worked through this (by substituting the x) to get to 3y^2 - 15y - 5 = 0, but it doesn't easily factorise ... can you just check the question? Is it 1 / (x - 3) = y or (1/x) - 3 = y? Best S
Hi HilalFener when you've calculated the value of x, use that value to work out y. In this case I used x = 6 and then 'substituted' that in the x + 4y = 14 equation. This allowed me to then calculate the value of y as 2. Here's a video playlist on working with linear equations that might help: ruclips.net/p/PLPglScc3TJ-Mvi9Gk651-7y-bUJKC2y4H All best S
Hi - this type of question uses ‘elimination’ to get rid of either the x or the y’s. I multiplied by 4 so that, when I subtracted, the 4y’s cancelled out. Best S
Hi Dafydd Morris You need to multiply the equations to make one of the terms the same. In this case I'll multiply the first by 2 and the second by 3... so I can make the y's the same: I'm also going to put the 'larger' number equation at the top (6x+2y=13) 6x+2y=13 4x+3y=12 Multiplied becomes: 18x+6y=39 8x+6y=24 Take the bottom away from the top: 10x = 15 Divide through by 10 x = 1.5 Then use x = 1.5 in any of the equations, to work out y 6(1.5) + 2y = 13 9 + 2y = 13 Take 9 from both sides: 2y= 4 y=4 I hope this helps and all best :-)
+Neil Jerzynek - You sure about that? How did you write this comment, and then have it appear online? Here's something on quadratic equations that might be of interest: www.mathswrap.co.uk/what-use-is-a-quadratic-equation/ All best S
Hi If you take away the 5a's you'll get: -3b - - 4b .... this will be 1b as two minus signs make a plus. On the left hand side you now have 1b. On the right it's 6 - 8 = -2. So b = -2. To get 'a' just substitute the value of b back into one of the equations. 5a - 3b = 6 5a -3(-2) = 6 5a + 6 = 6 5a = 0 a = 0 Hope that's OK. Best S
I have my GCSE's this year and you have managed to teach me what my maths teacher has failed to. Thank you so much!
Hello where are from
Xcxf
You're such a humble bloke. I miss London just because of your manners.
Thanks Cethical and all best :-)
Please like and leave a comment!
Visit www.mathswrap.co.uk for real maths, tips and techniques.
Simon Deacon thanks for this, your are officially a legend
It really helped a lot
@@nanayahaya5917 Hi - that’s great and glad to help - all best S :-)
Hi Simon Deacon I am looking for questions that give the answer of both x's and both y's FOR SOLVING SIMULTANEOUS LINEAR EQUATIONS. Thank you
Doing my GCSEs this year and was struggling with these in class but after watching your video I understand them more clearly
Thanks
Hi Ayisha - no, numbers change, although most examples tend to use 'easier' numbers. I'll post a video with some harder questions and let you know when done. All best S :-)
Night before the maths exam I had a dream that I was watching this vid and it helped
Little did I know that was reality
Thank you may God be with you
I have this equation that I would like you to help me with, if possible.
Parking Station A: charges $3.20 (first hour) and $2.00 (afterwards)
Parking Station B: charges $6.00 (first hour) and $1.20 (afterwards)
Calculate the times of parking which would result in the cost being the same at both parking stations.
I hope that you can help, Thanks and you are great
Well i was going to give the solution but its been 5 years.....😂
Thank you SO MUCH Mr. Simon, I didn't understand what my secondary teacher was explaining. Again, Thank you.
Everyone, I hope all of you guys are free from the covid - 19 virus. Stay Home, Stay Safe, Be Safe.
u just taught me what my sir could taught me in one whole year..and u taught me in 10 mints ...thnks
+Mickale Ahmed - Glad to help :-)
Hi - this is really the easiest way. You could solve by plotting a graph but it takes a while and isn't always very accurate. Keep practicing and good luck!
Thanks for the video! It was so helpful leading up to my Maths Test. You are such a great teacher! Keep doing what you do because your awesome!
Glad to help thejchan16 :-)
Dear please I want you to give some example of two different terms of simultaneous equations as x& y
Hi - generally yes, although you might need to change the equations a little. Thanks for the comment :-)
Very useful doing this in maths and I didn't understand it till now and I can solve these in my up and coming maths exam
That's great ***** and good luck with your exams !
you are a very good teacher dude.
Ajit King Thanks and glad to help :-)
simon you know i am from india. what about you simon?
Ajit King Hi - based in the UK.
What a shot.
I love ur teaching keep it up
Thank you and glad the video helped - all best S :-)
anytime you have an equation do u always have to use the numbers 3 and 4
Just so you know, at 7:44, you wrote x=4 instead of x=6. I just wanted to point it out. Anyway, the video was very useful! Thank you! I just solved more than half of my math homework thanks to this video!
At 8:45 , you wrote 'substitute x=4 in 2'. Isn't it suppose to be "substitute x=6 in equation 2?" Thank you sir , this video also helped me out.
Could you help me with a question?
It asks to consider the equations:
(k-3)x+5y=-2
2x-3y=4
where k is a real constant for which I have to find the unique solution.
Thanks in advance!
willoxens I think I may have it, my solution wask=5/9
willoxens Hi - looks good! All best S :-)
Thanks!! :D
thank you so much. you are better than my math teacher
WARSAME Production same
Thanks alot Mr.Deacon!That was great help for me!
Very helpful! Good recap and clearly explained!
+Chris Hardy - That's great and glad to help :-)
Hi - you need to plot both lines and see where they cross. It's OK if you have an idea where they are likely to be on a graph... but it can take a long time to get that information. I'll post a video on this and let you know.
Simultaneous solving by using algebra is better and easier.
All best
S
we had solve them on a graph in 2016 gcse exam
Well, I don't know about life, but this was definitely needed in my math homework tonight, and thanks to you I can get it done. Thanks, friend! Good vid :)
+In All The Chaos - Glad to help and all best with your studies :-)
Sir can you tell me that why we use the formula in simultaneous linear equation
Hi - there isn’t really a formula you can use for simultaneous equations. This topic is really just so you have an awareness that straight lines can cross on a graph. Best S
Awesome Best tutor you are better than my maths teacher.. :)
Hi ibraheem nawaz glad to help :-)
Great teaching,thank you
The best teacher ever
ty i understand now!
Hi, how do we know which side to multiply and how do we know which letter to multiply?
Hi - it's really all about trying to eliminate one of the terms, so you can work out the other. Here's a playlist with some other examples: ruclips.net/p/PLPglScc3TJ-PkkPq8fL81mx0-eC7WzmUi. All best S :-)
Thanks!
Thank you very much!! Your video helped me a lot!
That's great and glad it helped :-)
Hey Mr. I'm lost how did you eventually get an 8? was following just got lost there...
Hi
6 + 4y = 14
I need to get y term on one side, and everything else on the other. The 6 needs to move so I subtract 6 from both sides:
4y = 14 - 6
4y = 8
y = 2
I hope this is OK. Here's a playlist on linear equations that might help: ruclips.net/p/PLPglScc3TJ-Mvi9Gk651-7y-bUJKC2y4H.
All best S :-)
chill out fam. he explained it well
For effective presentation, hearty congratulation
Hi can you help me on this problem?
7x-5y= 20
-8x-3y= 12
This video helped me a bit by the way. Thank you :).
+lewb Dangos - Hi - I'll arrange a video on this one and will let you know when done. In the meantime here's a link to a similar question: ruclips.net/video/z-pUHrtVT4c/видео.html. All best S :-)
+Simon Deacon Thank you very much :)
+lewb Dangos - Hi - here is the video for 7x + 5y = 20 and minus8x - 3y = 12 and hope it helps. ruclips.net/video/E4xxyDSOn0w/видео.html . All best S :-)
+Simon Deacon Thank you so very much, again! :D
+lewb Dangos - No worries and hope it helped :-)
Hi, where did you get 11 from?
Hi - do you mean 11x? If so, it's 12x - x as we're subtracting each of the terms. Best S
Thank you so much I didnt understand how to do this before now. You just got another like :)
+KaanPlays - Glad to help and all best S :-)
x squared +y squared = 29 y minus x = 3 thats the first set set 2 is y+ 1 =x squared and x = y minus 1
THANK YOU !
I do get it now this video was really useful thanks
whats the easyest way to solve these
Thnks teacher perfect explanation
This video really helped me ! Thanks so much
Glad to help and all best S :-)
@@3minutemaths I am Indian and thanks for video
Hey I got a question which I need help with working out.
3u+v=17
7u+v=29
Hi Shoot Fresh Mine as you're working simultaneously you can change the order:
7u+v=29
3u+v=17
Then takeaway the bottom equation:
4u = 12
Divide by 4 both sides:
u = 3
If you then put u=3 into any of the equations you can work out v, so:
7(3) + v = 29
21 + v = 29
Take 21 from both sides
v = 8
I hope this all helps :-)
good teacher
im trying understand something quadratic equations no 1 x sqaured minus x minus 56 =0 changed from minus b at start to positive minus minus is a plus comes out right as 8 and minus 7 next question 3x sqaured + 7x minus 13 =0 but with this one if you change the minus at start to plus answers in back of book are different to what it comes up with any advice.
Hi stephen barker .. it's quite difficult to read through this but (I think):
xsquared - x - 56 = 0 factorises to (x - 8)(x + 7) = 0
So, x = +8 and x = - 7 ... this is because x - 8 = 0 and x + 7 = 0
The next one 3xsquared + 7x - 13 = 0, is a little difficult to factorise and you need to use the quadratic formula. Here's a video with this particular question ruclips.net/video/lz5j4T49HJk/видео.html .
All best
S
ive got quadratics and fractions question can you tell me if its right 3 over x +1 minus 2 over x +5 =1 thanks
any chance of a video on them please
stephen barker Will do and let you know. Best S :-)
can you advise me with factorising please
how is it x=4? where did this come from? it got me so confused. pls reply
ohhh i get it... took time
hi ih Glad to help and all best with your studies :-)
Thank you,this was very helpful
Was that substitution or elimination
Hi - This video is all about elimination. Here's an example of substitution and hope it helps: ruclips.net/video/_qo7x80s5HI/видео.html. All best S :-)
+Simon Deacon what happens if the second equation doesn't have a number in it, what do you do then?
+sean turner - Hi - can you give me an example?
Or the first equation has two numbers?
+Simon Deacon here is an example 2x+y=4 and x-y=-1
+Bad News Bullet - Hi ... with these you'd need to add to get rid of the y's (as +y + -y = 0)
2x + y = 4
x - y = -1
(Adding them)
3x = 3
Divide by 3
x = 1
Put x = 1 back into the first equation:
2(1) + y = 4
2 + y = 4
Minus 2 both sides
y = 2
So x = 1, y = 2
You can also check this by putting into equation 2:
x - y = -1
1 - 2 = -1
I hope that's all OK? Best S :-)
Simon Deacon
Awesome that was really helpful :)
where did x=4 come from?
Hi Ambra Onyss - where do you mean? Can you give me the time? Thanks S :-)
Simon Deacon 7.46 when you substitute
Ambra Onyss Hi .. ah yes, sorry, bit of an error. x = 6 and I need to edit. Thanks for pointing out :-)
Simon Deacon no problem :-)
@@3minutemaths what if its 5x= 6 what do i do then, is it a fraction?
How would u work out
3p+5q=43
8p+5q=73
Hi Hamza Roblox .. as you're working simultaneously you can put the equations the other way around. So:
8p+5q=73
3p+5q=43
Then take the bottom equation away from the top
5p=30
Divide through by 5
p=6
Put the value of p back into any of the equations
8(6)+5q=73
48+5q=73
Take 48 from both sides
5q=25
Divide through by 5
q=5
So, p=6, q=5
I hope this is OK.
All best
S
I need a help sir....can u solve this for me
r + 2s = 6
3/2 r -s = -7
R = minus 2 S = 4
stephen barker thank you sir ...i got it
Hi I'm a maths tutor and also run three first class learning centres.
It was really useful, thank you 💓
+Florence Farhana Akther - Glad to help :-)
but what happens if the signs are different i.e the question is 3x+2y=18/2x-y=19
i dont know how to solve this simultaneous equation?
Hi - here's a playlist that might help: ruclips.net/p/PLPglScc3TJ-PkkPq8fL81mx0-eC7WzmUi. All best S :-)
hey you have to multiply 1 or both equations t make X or Y the same if i multiply equation 2 by 2 i get 2x - 2y = 38 so your equations are 3x+2y= 18 and 4x-2y = 38 ADD to eliminate so 4x + 3x = 7x 2y + minus 2y cancels out and 38 + 18 = 56 so 7x = 56 divide both sides by 7 X = 8 sub back in any equation 3(8)+ 2y = 18 24 + 2y = 18 subtract 24 from both sides 2y = minus 6 divide both sides by 2 Y = minus 3 solutions are X = 8 and Y = minus 3
Thanks, this really helped!
Thank you so much I finally understand how to do it without making stupid mistakes wuhuuuuu!
Hi Justin Beary that's great and glad the video helped :-)
Well explained.
Glad to help :-)
How do you do this:
a - 5b = -12
8a + 3b = -10
Renea Chua Here you go ruclips.net/video/Mm8TJw22lYU/видео.html . I hope it helps and all best S :-)
Thanks helped me out!
Glad to help Jibrael Malik :-)
It really helps me, thank you
+Kailing Chen - Glad to help :-)
Though all of this is true some of it is unnecessary. Keeping equals signs in a vertical line is essential for clear manipulation of decimals but, since x and y are different with no decimal places, it doesn't matter. Also, I chose the 2nd equation since it ends up with smaller numbers to compare viz: 3x + 12y = 42 then subtract 3x + y = 20 to get 11y = 22, much easier to see, in my opinion. Stop asking, "OK?" at the end of each sentence - students think you are asking a question. Well done, though, Simon.
I am in university and you have helped me greatly. Thank you!
Glad to help and all best S :-)
Thanks this helped me a lot
+SparklyMermaid - Glad to help and all best with your studies :-)
this helped a little but im still having trouble.what if the y is first
example: y=x-1 & y=-x+11
+Cydney Lozano - Hi -
y = x - 1
y = -x + 11
Because I've got a positive x and a negative x I can add them together to 'cancel them out.'
2y = 10
y = 5
Substitute y = 5 into equation 1
y = x - 1
5 = x - 1
x = 6
So, x = 6 and y = 5 for both equations.
Hope this is OK and all best S :-)
thank you so much ! i subscribed!! :))
+Cydney Lozano - Very welcome and glad to help :-)
have i got this right if both equations are + you subtract if both minus you add and 1 of each you add
Hi stephen barker ..yes, you're really just trying to cancel out one of the terms. Best S
Simon Deacon
cool im mainly struggling with the quadratic simultanious any chance of a vid on them
Simon Deacon
how do i draw a line y = 3 on a graph
Hi stephen barker you need to make sure that all your y co-ordinates are 3.
If you plot a line to join (1,3), (5,3), (8,3) then it'll be y=3.
All best S
Simon Deacon
ive got a trapezium with height of x and parralel sides of x + 1 and x+2 area is 10 cm what is the value of x thanks
Thank you so much! I finally get it!
Glad to help Charlie Michele :-)
you see i have this equation tht i dont get may u help me?
see i have {5x+2y=19 ... 1
{2x+3y=12 ...2
but i dont get how you r suppose to multiple this by 3 for the top and then u need to multiple by 2 for the second part
why*** you r suppose to multiple this by 3....
Hi yukicross6767
OK, as you said, multiply the top by 3 ... this will give you 6y so:
15x + 6y = 57
Multiply the second equation by 2 ... this will also give you 6y, so:
4x + 6y = 24
Take one away from the other:
11x = 33
These type of questions usually work out OK - if you start to get lots of decimals of odd fractions, it might be a good idea to check your working. If I divide both sides by 11 I get:
x = 3
Use x = 3 in either the first or second equation. I'll use the first:
5x + 2y = 19
When x = 3
15 + 2y = 19
take 15 from both sides:
2y = 4
Divide by 2
y = 2
I hope this helps and all best with your studies. S :-)
Simon Deacon yes i understood thx so for the second part finding the y it doesnt matter which equation u use it will still be the same answer right?
yukicross6767 yes - you could use any of the equations to get the value of y.
i cant not understand the logic behind subtracting one from anothercan you explain?
Hi - both of these equations represent straight lines and we're working out where they cross. By taking one away from the other you can get rid of one of the terms, and work out the other. Here's a playlist with some more examples and hope it helps: ruclips.net/p/PLPglScc3TJ-PkkPq8fL81mx0-eC7WzmUi. All best S :-)
hi can you help with this please 1/x minus 3 =y and 1/y minus 5 = x
Hi - I've worked through this (by substituting the x) to get to 3y^2 - 15y - 5 = 0, but it doesn't easily factorise ... can you just check the question? Is it 1 / (x - 3) = y or (1/x) - 3 = y?
Best S
@@3minutemaths i will ask the person who posted it
@@3minutemaths hi it isnt my questinon its 1 somebody else put up
I’m in love with eamon
U deserve more subscribers ;-;
great video man helped me understand this grade B topic alot more... need a new camera man doe lool
+Movez.Corleone - Thanks and glad to help ... the latest videos are a lot better :-)
I’m so confused, how did you get 6 after dividing 11 X?
Hi - you need to divide both sides of the equation (around the = sign). So 11x divided by 11 is 1x, and 66 divided by 11 is 6. Best S
@@3minutemaths oh ok thx man
you are saving my life
Why is y=2? im kind of confused how you got 2
Hi HilalFener when you've calculated the value of x, use that value to work out y.
In this case I used x = 6 and then 'substituted' that in the x + 4y = 14 equation.
This allowed me to then calculate the value of y as 2.
Here's a video playlist on working with linear equations that might help:
ruclips.net/p/PLPglScc3TJ-Mvi9Gk651-7y-bUJKC2y4H
All best
S
great help
Wow Simon your my best friend and I love you thanks
Lol, glad to help Mathew Stenton :-)
Thanks Simon Deacon helped alot!
Thanks makes a lot more sense.
Glad to help Mateen Malik :-)
Thank you sir!
Glad to help Michelle Wanha :-)
this was very helpful
Glad to help and all best S :-)
Why do i need to multiply by 4?
Hi - this type of question uses ‘elimination’ to get rid of either the x or the y’s. I multiplied by 4 so that, when I subtracted, the 4y’s cancelled out. Best S
How would I do
4x+3Y=12
6x+2Y=13
Hi Dafydd Morris
You need to multiply the equations to make one of the terms the same. In this case I'll multiply the first by 2 and the second by 3... so I can make the y's the same:
I'm also going to put the 'larger' number equation at the top (6x+2y=13)
6x+2y=13
4x+3y=12
Multiplied becomes:
18x+6y=39
8x+6y=24
Take the bottom away from the top:
10x = 15
Divide through by 10
x = 1.5
Then use x = 1.5 in any of the equations, to work out y
6(1.5) + 2y = 13
9 + 2y = 13
Take 9 from both sides:
2y= 4
y=4
I hope this helps and all best :-)
hae ..solve matrix [3n+n]=
8
[-n-n]=8
hae ..solve matrix [3n+n]=
8
[-n-n]=8
Thank You, Thank You, Thank You!!!!!!
it helps me thanks
a graph how would i do that
where have you been all this time??
I've never used this at all, THIS IS NOT NEEDED IN LIFE!
+Neil Jerzynek - You sure about that? How did you write this comment, and then have it appear online?
Here's something on quadratic equations that might be of interest:
www.mathswrap.co.uk/what-use-is-a-quadratic-equation/
All best S
+Simon Deacon was just a bit bored online looking at rubbush and thought of pointless maths
+Neil Jerzynek No worries - some maths is pretty pointless. There's a lot of good stuff though :-)
Thank you sir
Very welcome and glad to help - all best S :-)
Thanks alot
THIS GUYS THE G.O.A.T
how is y=2 pls reply
+chris studios - Hi, when you get x = 6, I then put this value back into one of the equations to get y = 2. All best S
mast 1no.mala shekayala madat a zalei
thank you so much
You're welcome vani na, glad the video helped :-)
:-) thanks
3m=2n-2*6+1
4m+n=6
How to solve this one
M = 1/11 N= 62/11
stephen barker thanku
no prob weird solutions though
5a-3b=6
5a-4b=8
How to do this?????
Hi
If you take away the 5a's you'll get:
-3b - - 4b .... this will be 1b as two minus signs make a plus. On the left hand side you now have 1b.
On the right it's 6 - 8 = -2.
So b = -2.
To get 'a' just substitute the value of b back into one of the equations.
5a - 3b = 6
5a -3(-2) = 6
5a + 6 = 6
5a = 0
a = 0
Hope that's OK.
Best S