Game Theory 101 (#60): Tit-for-Tat Isn't Subgame Perfect

Поделиться
HTML-код
  • Опубликовано: 31 дек 2024

Комментарии • 28

  • @judy3463
    @judy3463 3 года назад +3

    Thank you so much! You are my lifesaver. Lots of love from Korea :)

    • @leylamirzaei825
      @leylamirzaei825 3 года назад +1

      are you at the hankuk university maybe ? :)

  • @treeman258
    @treeman258 8 лет назад +4

    Keep the videos coming. I wonder what would happen in those competitions if some randomness was incorporated into the move each player made? for instance if my bot chooses cooperation, there is a chance that he will actually defect (simulating accidental failures or the like) what would be the best strategy then?

    • @Gametheory101
      @Gametheory101  8 лет назад +2

      +treeman258 It's been a while since I have read that literature, but I am pretty sure that tit-for-tat does very well in those cases.

    • @treeman258
      @treeman258 8 лет назад

      +William Spaniel no, if tit for tat was used then whenever a bot "accidentally" defected the two players would go into the 4 1 4 alternation you described.

    • @Gametheory101
      @Gametheory101  8 лет назад +7

      +treeman258 By "very well" I meant in comparison to other strategies. You are right that an accident results in the 4 1 4 1 alternation, but:
      1) That's still better than what would happen with a grim trigger strategy.
      2) Another accident can bring them back to mutual cooperation.
      3) Strategies that never cooperate do extremely poorly.
      Combine those factors together, and you still circumstances that would make tit-for-tat fare comparatively well.

    • @sayaks12
      @sayaks12 8 лет назад

      William Spaniel what about forgiving tit-for-tat, that is tit-for-tat which requires the opponent to defect twice in order to defect?

    • @jonahprinceton8132
      @jonahprinceton8132 3 года назад

      Instablaster.

  • @Eichro
    @Eichro 2 месяца назад

    What's not clear to me is if that still applies when the opponent employs different strategies, or even if player 1 knows what the opponent's strategy even is.

  • @Brodysseus113
    @Brodysseus113 4 года назад +1

    I'm looking for a video series that had a simulator game that taught you about this stuff but also allowed for mistakes to be made, and allowed for forgiveness

  • @엠제이-d7c
    @엠제이-d7c 3 года назад

    @5:57 why is it 3+3d >= 4+d ? Isn't it 3(1-d) >= 4+ d? So d =< -1/2 ? (what I mean by d = discount factor)

    • @Gametheory101
      @Gametheory101  3 года назад +1

      From the second line to the third line, multiply everything by (1-d). The left hand side becomes just 3. The right hand side becomes 4/(1+d) + d /(1+d). The rest is easy.
      The confusing thing here is that (1-d)/(1-d^2) = 1+d.

  • @BS33875
    @BS33875 Год назад

    is it that if I don't believe the opponent could want to cooperate I should not cooperate in the beginning?

  • @sammyz1128
    @sammyz1128 5 лет назад +3

    could you make a video about whether grim-trigger is a SPE or not?

    • @menscott2581
      @menscott2581 4 года назад +2

      It is. The reason is explained in grim-trigger video.

    • @BLINKBOXHD
      @BLINKBOXHD 4 года назад

      @@menscott2581Do you mean by identifying which threats are credible? and thus picking the sub game perfect equilibrium through this?

  • @axxenmardok
    @axxenmardok 2 года назад

    This is the first time I didn't get your explanation in this series.
    Isn't the one-shot deviation principle satisfied if no singular player has a profitable deviation at any one subgame? In the previous example, we looked at one player making a deviation from tit-for-tat, and showed that if delta>1/2, they wouldn't have a profitable deviation.
    In this example, BOTH players have made a deviation from tit-for-tat, albeit in separate subgames. Doesn't that mean that this is a different strategy profile altogether from the previous video?

    • @zacharytaylor2423
      @zacharytaylor2423 11 месяцев назад

      In the delta < 1/2, the profitable deviation is on the path of play. In the delta > 1/2 case, the profitable deviation is off the path of play.
      "Profitable" means profitable within the relevant subgame, not just profitable on the path of play. Recall that the definition of SPNE requires that if you "start" play from any subgame, the strategies applied to that subgame also correspond to an equilibrium. So for the same reason any deviation on the path of play is enough to conclude the strategy profile is not an equilibrium, any deviation off the path of play is enough to conclude the strategy profile is not subgame perfect.

    • @SYLee-b3c
      @SYLee-b3c 4 месяца назад

      @@zacharytaylor2423 I really like your answer.

  • @PunmasterSTP
    @PunmasterSTP 3 года назад

    Tit-for-tat? More like 'Get my hat", because it's raining knowledge!

  • @rosokorai9755
    @rosokorai9755 3 года назад +2

    What if there's a 3rd party in the game, an impartial observer - enforcer who would make sure that both parties follow the rules automatically and every single time? Surely then there would not be a subgame inequilibrium. In the real world, there can be all kinds of reasons why a party could not comply EVERY time with the grim trigger... and so it's realistically not very executable. I suppose that's why intermediaries exist in the real world, that of course is costly for both parties both in terms of time and money, but we can also imagine a world in which costly intermediaries are replaced by blockchain enabled smart contracts or trustless protocols.... making the tit for tat strategy work in the long term with no deviation from the happy path. Thoughts?

    • @Stop1601
      @Stop1601 Год назад

      Question: Wouldn’t the process of introducing a contract system to solve for tit for tat’s lack of credible threat, just result in a grim trigger strategy regardless?

  • @BS33875
    @BS33875 Год назад

    why is it no equilibrium less or more than one half?

  • @i-kahn
    @i-kahn 5 лет назад +2

    Why not consider the first C,D period when the opponent defects in the payoff? I.e. why not 1 + 4ẟ +ẟ^2+4ẟ^3....
    EDIT: Nvm got it! Thanks

  • @samkim6933
    @samkim6933 2 года назад

    So isnt tft a SPE when delta is equal to 1/2? Why did you title the video NOT SPE?

  • @Brodysseus113
    @Brodysseus113 4 года назад

    Look up "The Evolution of Trust"

  • @BS33875
    @BS33875 Год назад

    why will Tit For Tat not work?