In Q7(b)(iv) when the current in the filament wire decreases shouldn't the resistance across it increase since resistance and current are inversely proportional
Current flowing in the loop decreases which results in less potential difference in the loop which also means lowered resistance of filament lamp. Do not just blindly link the variables according to the formula.
The graph that I have drawn is of velocity vs time where slopes of both cars are not supposed to intersect at any time. If you drew the distance vs time graph, the slopes will intersect at some point there.
Thank you so much for all the videos. Cant thank you more. It is really helpful for me. Thanks a lot 🥰
I luv u soooo much (as a teacher for helping)
In Q7(b)(iv) when the current in the filament wire decreases shouldn't the resistance across it increase since resistance and current are inversely proportional
Current flowing in the loop decreases which results in less potential difference in the loop which also means lowered resistance of filament lamp. Do not just blindly link the variables according to the formula.
@@examhelpweb2090 explain it properly then instead of simply reading from ms lizzo fc member
@@justblitz1566 my guy didn't hesitate but true💀
@@examhelpweb2090 how does the potential difference decrease? shouldn't it be same as it is provided by battery?
WHY SO MUCH ADS
Okay so here's a question:
What is the difference between drag force and upthrust force in question (1b)
Upthrust force remains the same but drag force changes with velocity.
Thank you. This was helpful
I don't understand how Car Q passes Car P after 12 s because the graph doesn't meet after 12 secs in Q2 (d)
The graph that I have drawn is of velocity vs time where slopes of both cars are not supposed to intersect at any time. If you drew the distance vs time graph, the slopes will intersect at some point there.
You don't make any sense
I too i don't understand. after time 12 the velocity remains constant which means it will never cross each other
Thank u ❤️👍