我想問一題Quadratic Equation 的數 題目:Divide a line 8cm long internally into two parts, so that the rectangle contained by the whole line and one part may be twice the square on the other part. 本書既答案係:Each part 4cm 我唔明佢講咩同點列式,求解。
佢應該係講緊:首先將 8 cm 嘅線斬成兩份,一份我地叫 x,咁另一份就好自然係 8 - x 啦。 然後 "the rectangle contained by the whole line and one part" 就係講緊一個長闊分別係 8 cm 同 x cm 嘅長方形面積;"square on the other part" 就係另一部分嘅正方形面積 (或者二次方啦),即係 (8 - x)^2 咁所以條式就會係:8x = 2 (8 - x)^2 Solve 完就會計到 x = 4,亦即係你嘅答案:兩部分都係 4 cm 我地都覺得條問題係有啲 1999,一開始睇都一頭霧水
估唔到你仲記得,我喺 application of trigonometric ratio 條片度留咗 comment,睇下明唔明 project-identity.hk/8-application-of-trigonometric-ratios-in-plane-figures-%E5%B9%B3%E9%9D%A2%E5%9C%96%E5%BD%A2%E7%9A%84%E4%B8%89%E8%A7%92%E6%AF%94%E6%87%89%E7%94%A8/
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影片內容:
00:15 - 例子 1 | example 1
04:03 - 例子 2 | example 2
06:37 - 例子 3 | example 3
Playlist:
HKDSE Maths | 二次方程 | Quadratic Equations
ruclips.net/p/PL1Pv0-rhcQx7iJf_di2xao6-04U8Qsa1k
我想問一題Quadratic Equation 的數
題目:Divide a line 8cm long internally into two parts, so that the rectangle contained by the whole line and one part may be twice the square on the other part.
本書既答案係:Each part 4cm
我唔明佢講咩同點列式,求解。
佢應該係講緊:首先將 8 cm 嘅線斬成兩份,一份我地叫 x,咁另一份就好自然係 8 - x 啦。
然後 "the rectangle contained by the whole line and one part" 就係講緊一個長闊分別係 8 cm 同 x cm 嘅長方形面積;"square on the other part" 就係另一部分嘅正方形面積 (或者二次方啦),即係 (8 - x)^2
咁所以條式就會係:8x = 2 (8 - x)^2
Solve 完就會計到 x = 4,亦即係你嘅答案:兩部分都係 4 cm
我地都覺得條問題係有啲 1999,一開始睇都一頭霧水
IDENTITY HK 多謝曬😁😁😁
第3題好難呀😢
你之前有短三角比 Application 即片求三角形面積,其間你話可以用二次解。可5可以講下點做
估唔到你仲記得,我喺 application of trigonometric ratio 條片度留咗 comment,睇下明唔明
project-identity.hk/8-application-of-trigonometric-ratios-in-plane-figures-%E5%B9%B3%E9%9D%A2%E5%9C%96%E5%BD%A2%E7%9A%84%E4%B8%89%E8%A7%92%E6%AF%94%E6%87%89%E7%94%A8/
+IDENTITY HK 諗左好耐都5記得有條畢氏定理😅😅😅
第一題個 A'O^2+B'O^2=A'B'^2 洗唔洗括番個 (Pyth. throrem)?
要呀,一時漏咗
我發覺你哋identity 網站條片下面個comment box 好似冇個送出制,同埋個 聯系我們 既comment都send 5 出去喎
+千羽樱 我地會盡快整㗎喇,多謝你專登留言提我地