I already shared the Entire playlist of Big Data. My teacher also created the college notes from your videos 📸. Because the content of teacher notes and your videos are exactly the same.
Write the script to sort the values contained in the following vector in ascending order and descending order: (23, 45, 10, 34, 89, 20, 67, 99). Demonstrate the output
U class is very neat and clean...i have dought sir....in 5th rule how can u select the bucket length...in some cases 2bits,4bits,and last 8bits of length...how it is possible
Thank you so much for the thorough explanation! what if we wanna use this algorithm for estimation? I've seen they add half of the size of the partial bucket to the result. Can you please explain?
I have a question. Do we have to always show those 3 scenarios : if new entering bit is 0,1,1 and then we have to count the number of recent/first bits whatever is asked? or can I count it directly in the question's given stream?
Its not mandatory to show all these three scenarios and then count the bits.. it's totally up to you, but if time permits in the exam then please show all these scenarios. Hope it helps! Thanks for watching ☺️
sir,till when we need to add 1 to the end to form buckets...what is the terminating condition of adding 1 at the end. Because if there is no terminating condition then the answer of the query i.e. how many 1's are there in the last 16 bits.......will be different for different students.
If new number is entering then we have to take it into the right side ? And in book the formula of 1’s is half of the size of oldest bucket+size of all newer bucket.
See standard way of adding elements is from right side and also make sure if you are adding elements from right then you have to start creating buckets from right side only In the video I have told how to count 1's you can use that
For the case of first 20 bits, the answer would be 13! As you know for the first 18 bits there are 9 bits of one. Now if you increase the count to first 20 bits. The length of entire next bucket (4) will be counted. That is why 9+4=13 is the answer... As DGIM algorithm is meant for providing only approximated count of 1's in a stream data as any streaming data is much huge and continuous. Therefore it's difficult to get correct results! Hope it helps❤️ Best wishes for your exams💕
Thanks a lot for appreciating!❤️ See for counting 1's in a stream we use DGIM algorithm because it gives the approximated answer by forming buckets. For counting 1's in a specific window also you can use DGIM algorithm. But since the window contains finite number of elements you can use any simple algorithms also for counting. In short, both the problems are going to count the 1's but the DGIM algorithm has a sublinear time complexity, which makes it efficient for counting 1's in large windows / stream. Hope it helps!❤️ Best wishes for your exams.... 💕
Heyy that's a great question, look once buckets are formed it's location/timestamp is also stored.. so if you want to count number of 1's in a particular location/timestamp you can easily traverse to that timestamps and access the number of buckets that comes under it and easily count the total number of 1's in it.. Ans: Here, for your example, for getting 1's from first 18 bits, you can start counting from the left and easily count it because here the data is extremely small and it's easy to access. But when it comes to big data, the counter will traverse to the target timestamp and then will count the first 18 bits.... Hope it helps! Thanks for watching! Please do share with your friends ❤️😁
Look in the first 18 bits there are total 9 1's, And now if you ask for first 19 bits you can see that the 19th bit lies in a separate bucket with length 4 So the total number of 1's in the first 19 bits will be 9 (for first 18 bits) + 4 (bucket length that contains the 19th bit) = 13. So in summary the answer will be 13. Now this is acceptable because dgim is meant for counting "approximate" numbers of 1's. Hope it helps, please share it with your friends too ♥️☺️
For this case yes you are correct! As DGIM algorithm is meant for providing only approximated count of 1's in a stream data as any streaming data is much huge and continuous. Therefore it's difficult to get correct results! Hope it helps❤️ Best wishes for your exams💕
Very helpful 💖 thank you
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Thank you brother for such an easy explanation .... i understood all the steaming issues in one go from your videos... keep up the good work🔥
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I already shared the Entire playlist of Big Data.
My teacher also created the college notes from your videos 📸.
Because the content of teacher notes and your videos are exactly the same.
That's really great and nice of you 💗 Thank you so much 😊
It was such a very detailed and clear explanation. Really appreciate your work :)
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very good explanation and visual representation is awesome
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This is the best. Really helped me for my exam
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AWESOME EXPLANATION!!
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Thank you for this awesome and simple explanation really helped me in understanding the concept😃
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very smooth explaination
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Write the script to sort the values contained in the following vector in ascending
order and descending order: (23, 45, 10, 34, 89, 20, 67, 99). Demonstrate the
output
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Great explanation
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Thanks a lot ! You helped me a lot ! The explanation is very clear
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wonderful explanation ,
thank you so much Sir....
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Thanks alot..Really helped👍
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Great... thank you so much 👏
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Clear explaination
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Very Helpful ,Thank U for such good Explaination .
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Very well explained thank you 😊
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Thankyou so much❤😊
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sir if 2 more bits of 1 are added then how will we alter the bucket
U class is very neat and clean...i have dought sir....in 5th rule how can u select the bucket length...in some cases 2bits,4bits,and last 8bits of length...how it is possible
what a beautiful video
What a beautiful comment😍 Thanks a lot🥳
Thank you so much for the thorough explanation! what if we wanna use this algorithm for estimation? I've seen they add half of the size of the partial bucket to the result. Can you please explain?
Crystal clear thank you🙏
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wonderful explanation
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What a explanation bro. Marvelous.🥺.
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easy to understand explaination brother thanks🤗
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I have a question. Do we have to always show those 3 scenarios : if new entering bit is 0,1,1 and then we have to count the number of recent/first bits whatever is asked? or can I count it directly in the question's given stream?
Its not mandatory to show all these three scenarios and then count the bits.. it's totally up to you, but if time permits in the exam then please show all these scenarios. Hope it helps! Thanks for watching ☺️
Thank you sooo muchh❤
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As you said well no two buckets should be of same size then why you consider same sizes bits repeatedly regardless of rule conventions?
No more than two buckets should be of the same sizes.. please carefully listen🙏
sir,till when we need to add 1 to the end to form buckets...what is the terminating condition of adding 1 at the end.
Because if there is no terminating condition then the answer of the query i.e. how many 1's are there in the last 16 bits.......will be different for different students.
Thanksss alot
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Excellent explanation
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Very great explanation and so easy✨
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How was the paper?
Just amazing
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why did u add bits as 011 can i add any combination of bit i want?? also how do we know how many bits we can add?
If new number is entering then we have to take it into the right side ? And in book the formula of 1’s is half of the size of oldest bucket+size of all newer bucket.
See standard way of adding elements is from right side and also make sure if you are adding elements from right then you have to start creating buckets from right side only
In the video I have told how to count 1's you can use that
@@ataglanceofficial ya I saw your complete video, great explanation
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total number of elements present in the stream were 21 then why was n=20
what if the questio would have been [ No's of 1 in recent 20 bits?]
For the case of first 20 bits, the answer would be 13! As you know for the first 18 bits there are 9 bits of one. Now if you increase the count to first 20 bits. The length of entire next bucket (4) will be counted. That is why 9+4=13 is the answer... As DGIM algorithm is meant for providing only approximated count of 1's in a stream data as any streaming data is much huge and continuous. Therefore it's difficult to get correct results! Hope it helps❤️ Best wishes for your exams💕
Helpful!!!
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Nice sir
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Yash, You are amazing man!
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very clear
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How we are mapping the bucket
Great work ✨✨
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bro, you are doing a really great job hats off bro🤗
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We'll explained ❤
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Great ❤
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Great explanation!
One question, are counting 1's in a stream and window both same or different?
Thanks a lot for appreciating!❤️
See for counting 1's in a stream we use DGIM algorithm because it gives the approximated answer by forming buckets. For counting 1's in a specific window also you can use DGIM algorithm. But since the window contains finite number of elements you can use any simple algorithms also for counting.
In short, both the problems are going to count the 1's but the DGIM algorithm has a sublinear time complexity, which makes it efficient for counting 1's in large windows / stream.
Hope it helps!❤️ Best wishes for your exams.... 💕
@@ataglanceofficial Got it, thanks!
Cool 🙌🏻
Sarthak udya help kar paper madhe🙏
@@ayushyelne7064 😆
Simple explanation ❤
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What if the questions is to count the first 18 bits , should we count from the left?
Heyy that's a great question, look once buckets are formed it's location/timestamp is also stored.. so if you want to count number of 1's in a particular location/timestamp you can easily traverse to that timestamps and access the number of buckets that comes under it and easily count the total number of 1's in it..
Ans: Here, for your example, for getting 1's from first 18 bits, you can start counting from the left and easily count it because here the data is extremely small and it's easy to access. But when it comes to big data, the counter will traverse to the target timestamp and then will count the first 18 bits.... Hope it helps! Thanks for watching! Please do share with your friends ❤️😁
nice
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what if they asked for recent 19 bits instead of 18 ?
Look in the first 18 bits there are total 9 1's,
And now if you ask for first 19 bits you can see that the 19th bit lies in a separate bucket with length 4
So the total number of 1's in the first 19 bits will be 9 (for first 18 bits) + 4 (bucket length that contains the 19th bit) = 13.
So in summary the answer will be 13. Now this is acceptable because dgim is meant for counting "approximate" numbers of 1's.
Hope it helps, please share it with your friends too ♥️☺️
Great
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Please explain about this sir
What if we need to count the number of 1's in recent 19 bits instead of 18?
My guess: 13
Is it correct?
For this case yes you are correct! As DGIM algorithm is meant for providing only approximated count of 1's in a stream data as any streaming data is much huge and continuous. Therefore it's difficult to get correct results! Hope it helps❤️ Best wishes for your exams💕
@@ataglanceofficial Thank you so much!!!
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NIce Video Simply explained🫡🫡
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Very helpful 💖 thank you
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Thank you
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great explanation
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