Lecture 28 Protection of Generators-I

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  • Опубликовано: 25 ноя 2024

Комментарии • 8

  • @nateshsrinivasan3784
    @nateshsrinivasan3784 4 года назад +5

    Sir,
    At 26:26 of the video there is a small calculation error. Actual fault current is 111565A. But actual current given is 11565 A

  • @bharathsankar.t9703
    @bharathsankar.t9703 2 года назад

    very nice explanation sir

  • @lollotshangela6154
    @lollotshangela6154 3 года назад

    Hi there Prof , thank you for an informative lecture. I however have a question , how would one go about doing the protection calculation settings of an induction motor with only the following given: P(6MW), f(50Hz), Irated( 382A), V(11kV)...

  • @surendrakverma555
    @surendrakverma555 2 года назад

    Very good. Thanks 🙏🙏🙏🙏🙏

  • @sureshpadhy2243
    @sureshpadhy2243 3 года назад

    Which type of motoring action ( induction or synchronous motor ) happens in generator pole slip protection?

  • @paridalipu
    @paridalipu 3 года назад

    Thank u sir

  • @bijapurdgpowercontrols7391
    @bijapurdgpowercontrols7391 2 года назад

    Sir great u are contract Number

  • @alankarraj007
    @alankarraj007 2 года назад

    Thank you sir