Find the area of the square

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  • Опубликовано: 22 окт 2024

Комментарии • 18

  • @bpark10001
    @bpark10001 4 месяца назад +26

    You don't need all those constructions! As soon as you determine the congruency of the 2 triangles, you know both are 2 - 3 - √13 triangles. Side of the square is √13, so its area is 13.

    • @mathu6514
      @mathu6514  4 месяца назад +7

      thank you for the comment, the video wasn't necessarily about finding the area of the square but more to prove the Pythagorean theorem in a roundabout, serendipitous manner. Think of it as an exercise to introduce the Pythagorean theorem to students learning it for the first time.

    • @mrigankabhowmick137
      @mrigankabhowmick137 2 месяца назад

      ​@@mathu6514Then it's a good one.

  • @ketrin-fz8be
    @ketrin-fz8be Месяц назад +1

    Jacob Bronowski used a variation on the Pythagorean proof given here in his series The Ascent of Man.

  • @mrigankabhowmick137
    @mrigankabhowmick137 2 месяца назад +1

    This could be easily done by showing the triangles congruent at first and then using Pythagoras theorem to find out the side of the square and then the area

  • @mrigankabhowmick137
    @mrigankabhowmick137 2 месяца назад +1

    But the thought process of doing it in a other way was also good.

  • @Paul-sj5db
    @Paul-sj5db 4 месяца назад +1

    I reflected each triangle along their hypotenuse and added two more on the other sides of the square. You end up with a 5*5 square, area 25. If you subtract 4 of the triangles, 4*1/2*2*3 = 12 you get 13.

    • @mathu6514
      @mathu6514  4 месяца назад

      that's a nice way of looking at it, like a flower blooming.

    • @mathu6514
      @mathu6514  4 месяца назад

      c² = (a + b)² - 4(ab/2) = a² + 2ab + b² -2ab = a² + b² → a² + b² = c²

  • @xualain3129
    @xualain3129 3 месяца назад +1

    Let the side of the square be a.
    a*sin(alpha)=3. ….(1)
    a*sin(belta)=2 or a*cos(alpha)=2. …..(2)
    Dividing (1) by (2)
    tan(alpha)=3/2 from which sec(alpha)=sqrt(1+(3/2)^2)=sqrt(13)/2 hence
    cos(alpha)=2/sqrt(13)
    From (2) a*2/sqrt(13)=2 then a=sqrt(13)
    Area=a*a=13

    • @montyhall-vs3ul
      @montyhall-vs3ul 3 месяца назад +2

      wow. why not just realize that the side of the square equals sqrt(2^2 + 3^2). (Pythagorean!)
      Square that to get the area
      13
      Btw, the exercise in the vid was to get the area using the most primitive method possible, which doesnt include trig function, or Pythagorean either, for that matter

  • @BerzerkaDurk
    @BerzerkaDurk 4 месяца назад +7

    or... you could have half a brain, take one look at the drawing and realize that the two triangles are equal and know that the area of the square is 2 squared plus 3 squared.

    • @spinbulle5312
      @spinbulle5312 4 месяца назад +1

      yea even i was thinking the same

    • @mathu6514
      @mathu6514  4 месяца назад +4

      Brains aren't created with the knowledge of the Pythagorean Theorem already impregnated in them, it had to be learnt by the brain at some point. The point of the video was more to prove that 2 squared plus 3 squared is the area of the square.

    • @dannypipewrench533
      @dannypipewrench533 4 месяца назад +1

      Do not be mean to the nice math man.

    • @spinbulle5312
      @spinbulle5312 4 месяца назад

      ​@@mathu6514 the title of your video reflects to finding the area rather than proving it. If it would have to be done in an Olympiad exam, then this approach shouldn't be applied.

  • @alessiola
    @alessiola 4 месяца назад +4

    Very good 👍

  • @northdallashs1
    @northdallashs1 4 месяца назад +1

    very obvious