This incessant babbling caused a flashback to first year trig, when a woman who must have been your grandmother gave an equally disjointed and rambling lecture on sine, cosine, and tangent. Just because you can do math doesn’t mean you can teach it. Fortunately I found a handbook in the university bookstore that finally clarified things. Schaum’s Outline, I believe it was called. Link to it and save us all a lot of grief.
Just because you can do math doesn’t give a law degree that gives you the right to judge. If you are so smart why did you even click on this sight. Not everyone is genius like you.
Use an equilateral triangle of sides = 2 with each angle = 60 deg. Drop a perpendicular from any point to the opposite base, this perpendicular will bisect the angle and side exactly in half. You then have a right-angle triangle of 30, 60 and 90 deg with the hypotenuse = 2, the side opposite 30 deg angle = 1 (bisected in half). Applying Pythagorean Theorem, the side opposite 60 deg = (sq root 3). Hence, Sin (60 deg) = Opposite / Hypotenuse = (sq root 3) / 2.
you are just saying its√3/2 because it is √3/2. There is no definition or proof. I already know sin(60) but that doesn't mean I found sin(60). I just memorized like everybody else. I want to know how to evaluate sin without memorizing sin values or specific triangles.
I never took geometry or trigonometry in high school or college. I did take algebra and business math in high school and algebra in college, however, the highest mathematics class I took in college was finite mathematics, and statistics. But my point, is that I felt that your explanation is very good. I always believed in taking good notes in any subject.
I really like the explanation of how to solve for Sin(60), tho, it might be better to have led with the Triangle and explained what the Sine of a function really is first before graphing it. Thanks for the video.
its hard for me to take notes, i try but i end up convincing myself that i don't need to (which has been true for me but thats not the point and also doesn't help my complex). I know at some point i will really need to.
You didn't show where those numbers, 1, 2 and root 3 came from? Totally confusing. You should have started with an equilateral triangle of side 2 and shown where the came from. This just looks like magic otherwise, you just plucked them out of nowhere.
I have a question about PEMDAS (LR). Is this the only way to calculate multiple operation equations/formulas? I'm asking here because since this is like 5th grade level math the results I got searching here are from 6 years forward, and I don't think the owners would respond if I inquired on such old videos. Appreciate the help, anyone's! Thanks! =).
UR on the right track. When researched, you'll find that the problem seems to have FEW clues. They do give enough 2B soluable. That's where TRIG (& a calculator) come into play. With practice, it will become automatic. Then U graduate.
You have great lessons but when you were referring the definition of sine you mistakenly used the the term “angle” instead of the correct term “side.” I just thought this should be corrected.
This incessant babbling caused a flashback to first year trig, when a woman who must have been your grandmother gave an equally disjointed and rambling lecture on sine, cosine, and tangent. Just because you can do math doesn’t mean you can teach it. Fortunately I found a handbook in the university bookstore that finally clarified things. Schaum’s Outline, I believe it was called. Link to it and save us all a lot of grief.
L
Wow❤
Out for blood
Dang I just thought I was impatient, so I checked the comments to see if I wasn’t the only one
Just because you can do math doesn’t give a law degree that gives you the right to judge. If you are so smart why did you even click on this sight. Not everyone is genius like you.
Use an equilateral triangle of sides = 2 with each angle = 60 deg.
Drop a perpendicular from any point to the opposite base, this perpendicular will bisect the angle and side exactly in half.
You then have a right-angle triangle of 30, 60 and 90 deg with the hypotenuse = 2, the side opposite 30 deg angle = 1 (bisected in half). Applying Pythagorean Theorem, the side opposite 60 deg = (sq root 3).
Hence, Sin (60 deg) = Opposite / Hypotenuse
= (sq root 3) / 2.
WOW!
Yes the logical way to show how sin 60 = root3/2. I don't know why this video didn't show that?
@@markjakeway2035the video is 15 minutes long and yet it was basically a giant ad in the beginning
you are just saying its√3/2 because it is √3/2. There is no definition or proof. I already know sin(60) but that doesn't mean I found sin(60). I just memorized like everybody else. I want to know how to evaluate sin without memorizing sin values or specific triangles.
I just wanted to learn the formula...
I never took geometry or trigonometry in high school or college. I did take algebra and business math in high school and algebra in college, however, the highest mathematics class I took in college was finite mathematics, and statistics. But my point, is that I felt that your explanation is very good. I always believed in taking good notes in any subject.
sin 60° = height of equilateral triangle / side length of equilateral triangle = √3/2 • a / a = √3/2
I really like the explanation of how to solve for Sin(60), tho, it might be better to have led with the Triangle and explained what the Sine of a function really is first before graphing it.
Thanks for the video.
this guy makes a 16 minute video and doesn't explain the point of the video until 14+ minutes in. damn.
its hard for me to take notes, i try but i end up convincing myself that i don't need to (which has been true for me but thats not the point and also doesn't help my complex). I know at some point i will really need to.
Straight to the point. Filter out the crap.
Homeschool science teacher. Will suggest your videos. Thanks
You didn't show where those numbers, 1, 2 and root 3 came from? Totally confusing. You should have started with an equilateral triangle of side 2 and shown where the came from. This just looks like magic otherwise, you just plucked them out of nowhere.
Now it's stuck in my brain, I no longer have brain damage
I have a question about PEMDAS (LR). Is this the only way to calculate multiple operation equations/formulas? I'm asking here because since this is like 5th grade level math the results I got searching here are from 6 years forward, and I don't think the owners would respond if I inquired on such old videos. Appreciate the help, anyone's! Thanks! =).
Thanks it is helpful to me.
Why do so many steps? Just search sin60 deg and you will find it on your screen
if you use the UNIT CIRCLE, it shows the Hypotenuse of this triangle as 1...this way is a lil confusing
Please do a video for jamb exam❤
I’m taking grade 11 physics and I’m in grade 10. I have no clue what Sin and Cos are. And what Soh Cah Toa is
UR on the right track. When researched, you'll find that the problem seems to have FEW clues. They do give enough 2B soluable. That's where TRIG (& a calculator) come into play. With practice, it will become automatic. Then U graduate.
Same bro
nvm ill just buy a calculator
11:56
You have great lessons but when you were referring the definition of sine you mistakenly used the the term “angle” instead of the correct term “side.” I just thought this should be corrected.
YOU CAN FIND IT IN JUST A SECOND BY USING YOUR FINGERS? YOU DON'T KNOW THAT YET?
8 minutes of wasted time on the front of this video
I'm so disappointed