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Are you sure this is right? I think you could have stopped at 2^x=3 and gotten x=log2(3), or ~1.585. I even substituted that value back in and it was correct. I tried your value and it was way too large.
Are you sure this is right? I think you could have stopped at 2^x=3 and gotten x=log2(3), or ~1.585. I even substituted that value back in and it was correct. I tried your value and it was way too large.