Thermodynamics - 4-2 Moving Boundary Work in a constant pressure process

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  • Опубликовано: 11 сен 2024
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Комментарии • 13

  • @nickoemmanuelvillacruz3090
    @nickoemmanuelvillacruz3090 3 года назад +21

    Arguably one of the best engineering youtube channels

  • @abdullateef187
    @abdullateef187 2 года назад

    You’re an amazing human being. Thanks dude

  • @ilfi.
    @ilfi. 8 месяцев назад

    Dr, u mixed between 200 degree and 250 degree, that when u were looking for v2 . So the final answer is wrong

  • @abdullahemirtaskesen9666
    @abdullahemirtaskesen9666 Год назад +1

    Thank u for your great effort to provide us such nice videos.
    I wan t to ask that isnt the boundary work in this case negative because we said expansion means Wout so it should be negative am i wrong?

    • @engineeringdeciphered
      @engineeringdeciphered  Год назад +2

      The equations we derived for boundary work are all for “expansion” boundary work. So the equations will give us the value for boundary work out. Now, when we get ready to put that boundary into the conservation of energy equation- that’s when we need to make sure we plug in boundary work “out” as negative. But our boundary work equations are all positive for expansion (boundary work “out”).

    • @yigitcan824
      @yigitcan824 9 месяцев назад

      I thought same thing mate, the system is doing work so it's Wout which is negative?

  • @desirexiluvelosebise7725
    @desirexiluvelosebise7725 3 года назад +1

    Hi. How do I calculate the initial and the final temperature while the constant pressure ?

  • @huangbabarotmg
    @huangbabarotmg 2 года назад +1

    legend, if i ever meet you in person I will drop everything im doing and make you fried rice on the spot

  • @turk2589
    @turk2589 3 года назад +1

    There is one digit error.

  • @samibasha
    @samibasha 2 года назад

    Super

  • @emirbfitness
    @emirbfitness 2 года назад

    goat

  • @iDovahkiin
    @iDovahkiin Год назад

    Thanks for the tutorials.
    Btw, You could've substituted PV for mRT right? Or did you not do it because you don't know if it is an ideal gas?

    • @solounomas0
      @solounomas0 Год назад

      I think so but I search it and it says saturated water vapor can be considered as an ideal gas. If so you could substitute by mR(T2-T1) but you should get R and T1 by the tables.