Smith chart basics part 2: finding VSWR

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  • Опубликовано: 5 янв 2025

Комментарии • 121

  • @ati4280
    @ati4280 8 лет назад +67

    Wow, that's really easy and clear, my professor uses more than 6 hours to tell what you said in your video. You are an expert.

    • @rahulrajaram6891
      @rahulrajaram6891 5 лет назад +3

      Most of engineering is actually not that difficult to explain, but professor often make it harder than it needs to be.

  • @barbaraszabo7382
    @barbaraszabo7382 3 года назад +5

    I can't even begin to tell you how helpful your videos are. Your three videos in this series are so very understandable. I just spent over a week and many hours trying to understand what was said in my lecture and my book and was getting so frustrated. Why it couldn't have been made this clear in class is beyond me. Thank you sooooo very much!!!

  • @TheDzKid268
    @TheDzKid268 3 года назад +1

    you're a genius , not because of the knowledge of smith chart but the way you explain it. you did it in 5 mn what teacher in school does it in 6 months.

  • @ParthJoshi09
    @ParthJoshi09 9 лет назад +156

    thumbs up if you are watching this night before your exam!!

    • @lupuszzz
      @lupuszzz 4 года назад +1

      I'm here 27years too late, but still enjoying good teachers. ;-)

  • @martinmariscalescobar1491
    @martinmariscalescobar1491 4 года назад +1

    You are my hero Carl, please keep on whistling and doing things "easily"

  • @naamaarnaldoamericoamerico1045

    Ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh My dear Teacher, u r the best I've ever seen in youtube. You explain hard thing as an easy thing.
    Congratulationssssss and Thank u very much

  • @dhrumilchavda2585
    @dhrumilchavda2585 6 лет назад +2

    It is the best video, you blow the whistle and I laughed, totally worth it to see this video. Keep making it.

  • @stevehall7785
    @stevehall7785 6 месяцев назад

    this is the first time in my life I have understood a smith chart :)

  • @fares1651
    @fares1651 8 лет назад

    Maaan. You explained everything to me in less than 10 minutes. My teacher couldn't explain it in a month. Thanks a lot sir!

  • @王來吉
    @王來吉 8 лет назад +4

    Thank you for teaching. I finally know how to find out VSWR.

  • @mrjohn6021
    @mrjohn6021 7 лет назад +1

    I didn't have time to study from the book.. you just made my life easier #king

  • @evanpasero1846
    @evanpasero1846 3 года назад +1

    Thank you very much sir, this is an excellent explanation.

  • @caoxiangyu6687
    @caoxiangyu6687 6 лет назад

    great!your video is much more clear than my professor’s explanation saved my life!

  • @desiyatra2230
    @desiyatra2230 11 лет назад +1

    when my college sir taught this topic..i was wondering if i'l ever understand such things.. and after watching your video for just one time..i am so confident that i can teach my professor..thanks a lot Professor Carl!

  • @user-yx6mq2km3m
    @user-yx6mq2km3m 5 лет назад

    You are a true asset! Thank you for these videos

  • @sarahsal431
    @sarahsal431 10 лет назад +1

    Thank you so much. It helped a lot. And thank you for responding to comments. I had the same question about the other side of the circle drawn :)

  • @seandafny
    @seandafny 6 лет назад +39

    U kno u came a long way when khan academy can no longer be of service

  • @pk5432
    @pk5432 7 лет назад

    Perfect teaching in simple way

  • @divyanipatil3082
    @divyanipatil3082 6 месяцев назад

    Easy explanation but would like to see if there is 2:1 match ? how to do it . thanks

  • @IbrahimKhandker
    @IbrahimKhandker 11 лет назад

    Sir, I am confidence enough now to teach other about Smith Chart! Thanks a lot Professor.
    73
    OH6EAC

  • @PeculiarCortex
    @PeculiarCortex 9 лет назад

    a very helpful video, easy and to the point and very good explanation, thank you so veryy much!

  • @KIKETMASTERMX
    @KIKETMASTERMX 7 лет назад

    God bless you, this is really helpful
    Greetings from Mexico!

  • @electronic_guy8471
    @electronic_guy8471 8 лет назад +1

    thank you a lot sir.... U just saved my semester :)

  • @meghajohn6427
    @meghajohn6427 9 лет назад

    Thank u so much...its such an awsme video fr undrstndng Smithcharts...👍👍👍👍👍

  • @uriel_zapata
    @uriel_zapata 6 лет назад +3

    but the circles touch the axis in 2 points, what about the other number?

    • @AbdullahAhmad-xc3xl
      @AbdullahAhmad-xc3xl 4 года назад

      VSWR is always greater than 1(or equal), since the maximum of the wave can't be lower than it's minimum. So you only take numbers to the left of the center point.

  • @anonghosty
    @anonghosty 7 лет назад +1

    Thank you very much.
    It helped me to prepare for my test!

  • @abhishekpoudel4476
    @abhishekpoudel4476 9 лет назад +8

    while making the circle for vswr from centre , the central line cuts the circle at two points..then why the right side one point is taken as vswr? Why not the left side point? what's the rule for selection of one intersecting point from the available two points?

    • @flowersleewan
      @flowersleewan 9 лет назад +4

      Abhishek Poudel left side is voltage minimum then right for maximum

    • @photonwaves4827
      @photonwaves4827 6 лет назад +10

      +Abhishek Poudel , here's a simple way to look at this...
      VSWR = Vmax / Vmin
      Therefore, the smallest value VSWR can have is, 1 .
      Values on the left of the center of VSWR circle are less than, 1 and thus invalid for the purpose of determining VSWR.

  • @msbdevil
    @msbdevil 8 лет назад

    awesome dude bcoz of u i'll get 5 marks 2mrw..thnx

  • @danielpenney9077
    @danielpenney9077 5 лет назад

    Great stuff. Very blurry video on my end. Anywhere else it can be view? Thanks!

  • @googleuser4203
    @googleuser4203 6 лет назад

    But why we didn't take the other side that passes the line? Since we are moving clock-wise from the negative part(navigating through the angel too).

  • @reubengeorge220
    @reubengeorge220 Год назад

    The first jumper is the impending. How did you derive at -f100

  • @kevinobrien8803
    @kevinobrien8803 7 лет назад

    How do you physically measure the reactive component of an antenna? I would imagine that is essential before you can use the chart to figure stuff out with.

  • @joebell3567
    @joebell3567 5 лет назад

    Hi, thank you for the great video's on smith chart. I can see how to create a matching network between generator and load, but when this is swept over a frequency range (HF) in mind, the match at the design frequency goes out the window. Perhaps you could look at matching over wider frequency ranges in a future video? many thanks, Joe

  • @davidesteves2438
    @davidesteves2438 8 лет назад

    You sir are a wonderful help!

  • @engineeringclass9731
    @engineeringclass9731 9 лет назад +1

    Exellent tutorial. Love it

  • @keivanvalamanesh120
    @keivanvalamanesh120 6 лет назад

    it was really really really helpful and clear :) thanks a lot

  • @Knarcout
    @Knarcout 11 лет назад

    the resistive line will pass through 2 points of a circle, left and right side.. so which one is the vswr? does it always have to be on the right side of the circle, where resistive line passes through?

    • @carloliver4402
      @carloliver4402  10 лет назад +4

      It always has to be the right side. The easiest way to remember is this: the range of possible values for VSWR is 1 (perfect match, no reflections) up to infinity (open or short circuit, 100% reflected power). This means that it cannot be less than 1, ruling out all the values on the left side.

  • @ThomasDemeter
    @ThomasDemeter 11 лет назад +4

    How come you didn't choose the points on the other side of the VSWR circle that crossed center line?

    • @rafiassilian4572
      @rafiassilian4572 10 лет назад +4

      Because it's closer to the load, if you add a 1/4 wavelength stripline it will bring closer to the other point.

  • @poorva19
    @poorva19 8 лет назад

    You are too good!Thank you so much!

  • @donnymac575
    @donnymac575 10 лет назад

    Excellent video. Where can I obtain Smith Chart Paper like you are using?

    • @carloliver4402
      @carloliver4402  10 лет назад +9

      www.cems.uvm.edu/~keoughst/EE141-142/Smith_Chart.jpg

  • @Ionita.Vlad.
    @Ionita.Vlad. 8 лет назад

    You are a saint! Thank you!

  • @harryren383
    @harryren383 10 лет назад

    Excellent, you are my teacher

  • @asatallah
    @asatallah 9 лет назад

    very useful videos , thanks

  • @dalekwon3091
    @dalekwon3091 9 лет назад

    it is very helpful video to a student who study about electronic engineering which is me.!!! Awesome video thank you for video. I subscribe your channel.

  • @thepirates2518
    @thepirates2518 6 лет назад

    Dude you are awesome !!!

  • @gangstaaglide4074
    @gangstaaglide4074 5 лет назад

    Thanks carl you're my saviour now XD

  • @electronics_classes3302
    @electronics_classes3302 4 года назад

    Nice video

  • @PowKu10
    @PowKu10 8 лет назад

    nice job bro! helps a lot

  • @widyaagsari2725
    @widyaagsari2725 9 лет назад

    very good explanation, thank you so much

  • @MrAjaynagadeep
    @MrAjaynagadeep 7 лет назад

    Thank you, Carl!!!

  • @charlessamuellasiste2752
    @charlessamuellasiste2752 7 лет назад

    Please help me. You're given a line's characteristic impedance, but you're given just the magnitude of the load impedance, not the complex expression of the impedance. How do we solve VSWR for this case? Should we assume that the load is purely resistive?

  • @DG-zv2tj
    @DG-zv2tj 11 лет назад

    Is the VSWR ratio always to 1?
    I understand the left part of the ratio is determined from the VSWR circle, but just curious about the 1. Thanks in advance.

  • @psonney
    @psonney 10 лет назад

    Big Thank you.

  • @zaeemmazhar973
    @zaeemmazhar973 6 лет назад

    Thanks...very helpful video (Y) may God bless you... Amen

  • @lhcj21
    @lhcj21 11 лет назад

    This helps so much! Thank you!

  • @tidegoesin_tidegoesout
    @tidegoesin_tidegoesout 8 лет назад +1

    Excellent video

  • @shahriarmostafiz1292
    @shahriarmostafiz1292 5 лет назад

    you are a life saver

  • @lalayev
    @lalayev 9 лет назад

    Thank u so much ! Very helpful!

  • @saket1380
    @saket1380 8 лет назад

    Thanks man....helps alot ..👍

  • @amgadtaher4059
    @amgadtaher4059 8 лет назад

    Thank you sooooooo much.....My Transmition Line exam is tommorow!! :'(

  • @黄嘉宇-z6l
    @黄嘉宇-z6l 3 года назад

    sounds effect is as good as usual :)

  • @Abrahamsproperties
    @Abrahamsproperties 6 лет назад

    Thanks to world of technology have been trying to get this in lecture room but finally I got it here #yoppylaspotech

  • @bakhtiaruddin.2577
    @bakhtiaruddin.2577 4 года назад

    Thank you SiR..

  • @urjathakur4545
    @urjathakur4545 7 лет назад

    very good explanation .....

  • @hassanaziz39
    @hassanaziz39 10 лет назад

    brilliant.I must call you sir now

  • @robertocarloschavarriamart7045
    @robertocarloschavarriamart7045 9 лет назад

    OMG, thank you Bro, your videos are better than the spanish version
    NICARAGUA lol

  • @sudeep6716
    @sudeep6716 8 лет назад

    Thank you Sir!

  • @carloliver4402
    @carloliver4402  11 лет назад +1

    73 is "best regards." The other letters and numbers are an amateur radio operator's callsign. files.qrz.com/a/ta4a/ham_radio_world_map.jpg

  • @nimiechaylone5481
    @nimiechaylone5481 9 лет назад

    Thank you very much!

  • @edwardwonder9258
    @edwardwonder9258 9 лет назад

    great explaination

  • @consuelosanchez1833
    @consuelosanchez1833 4 года назад

    thank you!

  • @rahul122112
    @rahul122112 11 лет назад

    Mind if I ask you what "73 OH6EAC" is ? Just curious, no reason for asking.

  • @srinunavya5433
    @srinunavya5433 5 лет назад

    Super video sir

  • @thomaspeterson2568
    @thomaspeterson2568 7 лет назад

    Thank you!

  • @aniket7743
    @aniket7743 6 лет назад

    Well Explained sir

  • @rajcodes100
    @rajcodes100 10 лет назад

    I wish i can find a practical tutorial on S parameters.I am thinking like a block showing the network port connections and the explanations - the maths will come but just how you connect and what measurements you make.

    • @carloliver4402
      @carloliver4402  10 лет назад +1

      For Sxy, the signal is measured at port x, and it came from port y. Simple as that. So for S21, the signal is transmitted out of port 1, and you measure it at port 2. Since it has to travel through a device or TX line to get there, it is insertion loss. For S11, the signal is transmitted out of port 1 and is measured at port 1. Wait! These are the same port! So it must be REFLECTED power that is being measured: return loss. Check out the video on insertion and return loss for more on that.

  • @nibzlegend99
    @nibzlegend99 6 лет назад

    How to find impedance , given VSWR

  • @rahul122112
    @rahul122112 11 лет назад +1

    Ah wow. Thats news for me.
    Thanks :D

  • @neerajdharmadhikari9424
    @neerajdharmadhikari9424 10 лет назад

    Thank u very much!!

  • @MrNemay
    @MrNemay 7 лет назад

    Thanks !!

  • @MrRefract
    @MrRefract 10 лет назад

    Thanks!

  • @edwatts9890
    @edwatts9890 5 лет назад

    Minor quibble: Load 3 should have been noted as (50 + j0) Ohms.

  • @seank9122
    @seank9122 10 лет назад +1

    wow, shouldv found these videos earlier when i took the smith chart class.

  • @omaralngar330
    @omaralngar330 10 лет назад

    really thank u :)

  • @leonidfinkel4347
    @leonidfinkel4347 8 лет назад

    THANKS

  • @PauloConstantino167
    @PauloConstantino167 6 лет назад

    But the VSWR is 1+ Gamma / 1 - Gamma. What you did is just 1 + Gamma. Why ?

    • @vk2ig
      @vk2ig 6 лет назад

      The Smith Chart can be thought of as a plot of complex reflection coefficient Gamma in polar form (hence the circular boundary). The magnitude of Gamma is linearly scaled from the horizontal axis (the X'=0 line which has the R' values marked on it), and the angle (or argument) is plotted per a scale marked around the outer circle (which hasn't been mentioned in the video as it's not pertinent to finding VSWR easily). Accordingly, the circle centred on the R'=1 point and including the plotted Z' point will have a radius directly proportional to the magnitude of Gamma. (Edit: this is addressed in the next video ruclips.net/video/9KlIgae0ad8/видео.html)
      VSWR = (1+|Gamma|)/(1-|Gamma|), where |Gamma| is the magnitude of the reflection coefficient. It turns out that when the magnitude of Gamma is plotted on the right-hand segment of X'=0 line, the R' value equates to the VSWR value for the given magnitude of Gamma.
      To understand this fully, I recommend you read up on how the Smith Chart is mathematically derived from R, jX, and reflection coefficient. Any decent electromagnetics text dealing with transmission lines should include such a derivation. The maths isn't particularly difficult: some complex number manipulation and understanding the equation for a circle would suffice.

  • @abdulatifdhia382
    @abdulatifdhia382 10 лет назад

    Thanks alot

  • @Kwatcher100
    @Kwatcher100 8 лет назад

    In response to your question of "cany you see my circle?", the answer for me is no. The image was too blurry to make it out.

  • @sanjoybasak9646
    @sanjoybasak9646 10 лет назад

    thank u..:)

  • @seandafny
    @seandafny 6 лет назад

    Bro does this shit ever end

  • @jessiequinn6180
    @jessiequinn6180 4 года назад +1

    You're Canadian, Eh?

  • @TheCheng1993
    @TheCheng1993 11 лет назад

    agree

  • @Xristina8anos
    @Xristina8anos 11 лет назад

    radio amateur's code-name probably : )
    73 is like "greetings" from what i know

  • @jwill6676
    @jwill6676 7 лет назад

    please come and Teach at my school!

  • @wa4aos
    @wa4aos 11 лет назад

    EXCELLENT and THANKS!!!!
    73,
    WA4AOS

  • @MCSGproject
    @MCSGproject 7 лет назад

    You have a gift lol

  • @wolleausmallo1
    @wolleausmallo1 3 года назад

    To bad. I can't see any circle

  • @ConanTodd-t8h
    @ConanTodd-t8h 3 месяца назад

    Aurelio Rapids

  • @BessieNick-q1y
    @BessieNick-q1y 3 месяца назад

    Tromp Alley

  • @RobertCoffey-j4k
    @RobertCoffey-j4k 3 месяца назад

    Elise Avenue