IV Characteristics of a Diode Experiment - GCSE Physics Required Practical
HTML-код
- Опубликовано: 18 сен 2024
- This video allows students to carry out an experiment on the IV characteristics of a diode from home. This is a required practical for students to be able to understand and carry out for GCSE Physics.
A diode is connected to a variable power supply. The potential difference across the resistor is changed in steps of approximately 2V and the values for potential difference and current are taken. Students can pause the video in order to take their own readings. The diode is also connected in the opposite direction such that the potential difference has negative values as well. We can plot the potential difference against the current on a graph in order to investigate the IV characteristics of the diode. We can also calculate the resistance by dividing the potential difference by the current.
The full results as well as a blank table for students to fill in using the video can be found here:
www.gcsephysic...
Thanks for watching,
Lewis
Relevant for GCSE Physics 9-1 in the following exam boards:
AQA (including Trilogy)
OCR A
OCR B
WJEC
_____________________________________
MY PHYSICS WEBSITES
Find even more videos organised by exam board and topic at:
GCSE Physics Online
► www.gcsephysic...
A Level Physics Online
► www.alevelphys...
MY RUclips CHANNEL
Your support in watching this video has been invaluable! To contribute towards the free videos on RUclips, make a small donation at:
► www.paypal.me/...
FOLLOW ME
► www.youtube.co...
► / physicsonline
► / gcseandalevelphysicson...
#physicsonline
I am sincerely grateful for the wealth of knowledge and insights I've gained through this experience.
Thank you
you're welcome
I feel very enriched after this - thanks a lot mate :)
would defo recommend to a friend
pls reply it would make my day
hi, if possible could you explain why we need a protective resistor for a diode?
If you had a diode in its own, it had a very low resistance so a very high current would go through it - causing it to overheat and melt!
@@PhysicsOnline Thanks
How would this look in a graph
Hello Dulwich 9I