Power Factor Correction || pf correction || Example 11.15 || Practice Problem 11.15 || ENA 11.8 (E)

ENA 11.8 (E) || Example 11.15 || Practice Problem 11.15 (English)(Alexander & Sadiku).
The process of increasing the power factor without altering the voltage or current to the original load is known as power factor correction. This technique is very useful for industrial applications. The concept has been emphasized with the help of examples.
Example 11.15: When connected to a 120-V (rms), 60-Hz power line, a load absorbs
4 kW at a lagging power factor of 0.8. Find the value of capacitance
necessary to raise the pf to 0.95.
Practice Problem 11.15: Find the value of parallel capacitance needed to correct a load of
140 kVAR at 0.85 lagging pf to unity pf. Assume that the load is supplied by a 110-V (rms), 60-Hz l
Fundamentals of Electric Circuits -Alexander & Sadiku
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[@macpat4490]

Hello sir, thank you for your lecture videos. Watched all your videos from chapters 7-11. Best electrical engineering lecture videos.

[@ElectricalEngineeringAcademy]

Welcome dear. Best wishes.

[@MDRISHAD-qz9zn]

Assalamualikum sir, From Bangladesh sir. I always to understood in your whole lecture. I appreciate to you ❤️❤️❤️❤️

[@ElectricalEngineeringAcademy]

Thanks dear. Best wishes.

[@zainullah-kq2vr]

Assalamualaikum sir please upload 11.13 and 11.14 example and practice problem

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