Real Analysis | Heine Borel Theorem | Closed & Bounded set is Compact.

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One of the best teacher I've ever seen! He's so fast, but he makes every topic so easy! Thank you so much sir! (From Bangladesh)

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Not understandable just reading what's written

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Super sir you are role model for young Mathematics students sir 🙏

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Best teaching ... Sir thank you so much

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Sir your videos are genuinely helpful for us. They clearly explain everything in a short period.👍 thumbs up sir

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Sir thank you so much... Best real analysis class

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Ye bahut useful hai sir

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Full of knowledgeable video sir....🙏🙏🙏

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Thanku very much sir for providing us that much quality education 👌

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Million Of thanks sir

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M 1to Msc final tk k study m apke jaise sir mujhe mil nhi isliye m bhut dukh ho rh h nhi to aj m aur achha hot love you sir

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Sir very good teaching

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[@BiswajitDas-ml5tb]

no deep explanation, easily pass the goal !!!

[@Sword05...............]

Means?

[@ritikasharma1500]

Sir ....can you please upload the videos of vector calculus.

[@balkeshbhardwaj1801]

sir jo ye aap pdha rhe ho inka pdf mil jaye to bhut benifit hoga..plzz sir if you can provide then do it sir ....its a humble request.

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Clear hai

[@muhammadisrarurrehman9103]

thanks alot sir

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Thank you sir

[@UttamKumar-jz8oj]

Riemann integration per video uploaded Keejiye

[@deepaansh121]

Thanks sir🙏
Sir real Analysis pr aur video bnaiye

[@kanhaiyagupta4543]

Sir sets ka real life practical me kya use hai????

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Thanks sir😍

[@Abhishek29010]

Sir plz continuity and diffrantibility aur rimen integral pr b classes lao

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Sir ye topology kalian b same hain?

[@targetacc8993]

Sir Mertens theorem ka vedio upload kar da

[@AdityaKumar-vb9jh]

Nice👍

[@shubhamsagar299]

Sir Heine borel theorem meto aapke conversely bhi proof krna tha... Yeto aadhi hui bs.... Compact lekr closed nd bounded bhito proof krna tha... If I'm not wrong????

[@nirmalan4801]

👌👌👌😊

[@pavithrar6588]

What about interval I1.

[@siddheshthakur8079]

Thanks

[@tushroy81]

Please help me. To prove lim(sinx/x), we need to prove it through sine series which is dependent on Maclaurin Series which is dependent on derivative of sin x which is dependent on lim(sinx/x). Then it's a cyclic way. Which is the fundamental theorem and how to prove it without depending on daughter theorems.

[@theUnorthodoxxx]

then prove it by first principle.

[@qaisarfarhad2835]

Use squeeze theorem to prove it.
As -1 1
Divide by x
-1/x 1/x
As lim -1/x = lim 1/x = 0
This implies lim sinx/x=0

[@depressedguy9467]

You can prove geometrically

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[@krishnapaudel1852]

Sir namaste I am student of master level i need your suport in mathmatical analysis in med level please upload the vedios related topic

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Thanks sir

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Thank you sir

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Sir[a,b] hi kyo maan ke chale h reason to bataye. 😊

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Sir phle aap likh k padate the tb jyada achha smj aata tha 😔😔

[@GamingYT-ve7di]

Pichli videos sari samajh aayi but ye hein borel theorem samajh nhi aayi 🤒

[@the_informative_edge]

Hai na.. 😁 😁 😁

[@sukunag1373]

💯💯

[@sakshijhajharia2013]

Kya koi bta skta h sir open cover or sub cover kisko bol rhe h

[@Iqbalhossain-eb2iy]

​​​@@sakshijhajharia2013 Cover: If union of some sets contains all the points of a set S, then those sets together work as the cover of S.
Example: (1,2),[2,3),[3,5]
Sets are together Cover of a set S=(2,4) Because union of those 3 sets contains all points of S.
Subcover: When union of some sets of cover contains all the points of a set(S) then those sets together work as a subcover.
From the example given above,
[2,3],[3,5] is a subcover bcz union of these two sets contains all the points of S.
I am not good in English, maybe you will find some grammatical error, sorry for that.

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👍🙏

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🙏

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There are so many wrong explanation in the proof.

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SMJHAYA CLEARLY NAHI HAI

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Samjhana to Ata nhi

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The worst teacher even just translations what written in english to hindi lmao all these bot comments are praising him

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Than pay coaching fee why you here??

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Very bad

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Thanks sir

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