Module 15: Antenna Gain

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  • Опубликовано: 3 дек 2024

Комментарии • 12

  • @volehoang5184
    @volehoang5184 Месяц назад

    great lectures. Really appreciate this. Thank you, sir

  • @cloudyclo
    @cloudyclo 4 года назад +1

    Your video was so clear and detailed and informative! Thank you for the content!

  • @santhoshkatravath1
    @santhoshkatravath1 3 года назад +1

    i loved it sir,, thank you,, u r one of then who do share knowledge,, ,,, it's fantastic that u make people happy, clearing their doubts

  • @mohamednajm6990
    @mohamednajm6990 2 года назад +1

    Thanks for the lectures. Very simple and informative
    Request, can you provide the lecture slides (presentation) for us
    Thanks

  • @sabrialimi
    @sabrialimi 4 года назад

    Amazing great. Thank you Professor
    May you kindly give my friends about this lesson,
    inside gulag.

  • @_FizaPUJANA
    @_FizaPUJANA 3 года назад +1

    sir, actual answer of power radiation is A(3pi/4) ,there is not pi^2.

  • @eswnl1
    @eswnl1 8 месяцев назад

    First time I had a professor tell me to go and watch a Bond movie.

  • @wyw4466
    @wyw4466 3 года назад

    Hi there, thank you for posting the video. Question: since the Antenna gain = the antenna efficiency * Directivity, by having two different directivity equations for Tx and Rx meaning the antenna gain could be different between the Tx and Rx? Or is the term “U_pk/P_rad” and “effective aperture / lamda^2” in the Directive equation could equal to each other? Thanks!

  • @Ashxxik-EC001
    @Ashxxik-EC001 Год назад

    Thank you sir ❤

  • @Adrian-me4qz
    @Adrian-me4qz 4 года назад

    Great video, thanks! :)

  • @Coolgiy67
    @Coolgiy67 2 года назад

    Your integral you calculated is just wrong and the directivity you calculate is also wrong you forgot to multiply in A into the power radiated

  • @science_electronique
    @science_electronique 4 года назад

    هايل