NCERT 11 Maths Ch 5 Complex Numbers | Ex 5.1 hints & solutions(Basics of Complex Number)
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- Опубликовано: 1 окт 2024
- This video explains how to represent complex number in a+ib form .
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See the explanation here
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See the full explanation here
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12:19 Sir Ex 5.1 question 14 can also be solved using properties.
In numerator, apply z × z' (z complement) = (3)^2 + (√5)^2 = 14
In denominator, apply z - z' = 2(ImZ).i = 2√2i
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